{"id":10654,"date":"2023-06-05T14:34:51","date_gmt":"2023-06-05T09:04:51","guid":{"rendered":"https:\/\/apboardsolutions.in\/?p=10654"},"modified":"2023-06-06T17:53:00","modified_gmt":"2023-06-06T12:23:00","slug":"ap-board-7th-class-maths-solutions-chapter-13-ex-6","status":"publish","type":"post","link":"https:\/\/apboardsolutions.in\/ap-board-7th-class-maths-solutions-chapter-13-ex-6\/","title":{"rendered":"AP Board 7th Class Maths Solutions Chapter 13 Area and Perimeter Ex 6"},"content":{"rendered":"

AP State Syllabus AP Board 7th Class Maths Solutions<\/a> Chapter 13 Area and Perimeter Ex 6 Textbook Questions and Answers.<\/p>\n

AP State Syllabus 7th Class Maths Solutions 13th Lesson Area and Perimeter Exercise 6<\/h2>\n

\"AP<\/p>\n

Question 1.
\nA path 2.5 m wide is running around a square field whose side is 45 m. Determine the area of the path.
\nSolution:
\n\"AP
\nArea of the path= (Area of outer figure) – (Area of inner figure)
\n= (50 \u00d7 50) – (45 \u00d7 45)
\n= 2500 – 2025 = 475 m2<\/sup><\/p>\n

Question 2.
\nThe central hail ofa school is 18m long and 12.5 m wide. A carpet is to be laid on the floor leaving a strip 50 cm wide near the walls, uncovered. Find the area of the carpet and also the uncovered portion?
\nSolution:
\n\"AP
\nGiven
\nLength of the hail = 18m
\nBreadth of the hail 12.5m
\nWidth of the strip = 50cm = \\(\\frac { 1 }{ 2 }\\)m
\nLength of inner rectangle = 18 – (\\(\\frac { 1 }{ 2 }\\) + \\(\\frac { 1 }{ 2 }\\)) 17m
\nBreadth of inner rectangle = 12.5 – (\\(\\frac { 1 }{ 2 }\\) + \\(\\frac { 1 }{ 2 }\\)) = 11.5 m
\nArea of the strip = (Area of the outer fIgure) – (Area of the inner figure)
\n= 18 \u00d7 12.5 – 17 \u00d711.5
\n= 225 – 195.5 = 29.5 m2<\/sup>
\n\u2234 Area of the carpet = 195.5 m2<\/sup><\/p>\n

\"AP<\/p>\n

Question 3.
\nThe length of the side of a grassy square plot is 80 m. Two walking paths each 4m wide
\nare constructed parallel to the sides of the plot such that they cut each other at the centre
\nof the plot. Determine the area of the paths.
\nSolution:
\n\"AP
\nGiven : A square grassary plot of length 80m
\nTwo paths of width 4m each.
\nFrom the question
\nKL = 4m and KN = 80m
\nEH = 4m and EF 80m
\nPQ = 4m and PS 4m
\nArea of two paths = \ud83d\uddbe KLMN + \ud83d\uddbe EFGH – \ud83d\uddbe FQRS
\n= KN x KL + EF \u00d7 EH – PQ \u00d7 PS
\n= 80 \u00d7 4 + 80 \u00d7 4 – 4 \u00d7 4
\n= 320 + 320 – 16
\n= 624sq.m.<\/p>\n

\"AP<\/p>\n

Question 4.
\nA verandah 2 m wide is constructed all around a room of dimensions 8 m X 5 m. Find the area of the verandah
\nSolution:
\n\"AP
\nLength of outer rectangle = 8 + 2 + 2 =12m
\nBreadth of outer rectangle = 5 + 2 + 2 = 9m
\nArea of outer rectangle = l x b = 12 \u00d7 9 = 108m2<\/sup>
\nLength of inner rectangle = 8m
\nBreadth of inner rectangle = 5m
\nArea of inner rectangle = l x b = 8 \u00d7 5 = 40m2<\/sup>
\n:. Area of the verandah = (Area of outer figure) – (Area of inner figure)
\n= 108 – 40 = 68m2<\/sup><\/p>\n

\"AP<\/p>\n

Question 5.
\nThe length of a rectangular park is 700 m and its breadth is 300 m. Two crossroads, each of width 10 m, cut the centre of a rectangular park and are parallel to its sides. Find the area of the roads. Also, find the area of the park excluding the area of the crossroads.
\nSolution:
\n\"AP
\nGiven
\nLength of the rectangular park = 700 m
\nBreadth of the rectangular park = 300 ni
\nFrom the question,
\nPS 10m. PQ = 700 ni
\nArea of \ud83d\uddbe PQRS = 10 \u00d7 700 = 7000m2<\/sup>
\nAB = 10m, AD = 300m
\nArea of \ud83d\uddbe ABCD = 300 x 10 3000m2<\/sup>
\nKL = 10m, KN = 10m
\n\ud83d\uddbe KLMN = 10 \u00d7 10 = 100m2<\/sup>
\nArea of the two paths = \ud83d\uddbe IQRS + \ud83d\uddbe AF3CD – \ud83d\uddbe KLMN
\n= 7000 + 3000 – 100
\n= 9900m2<\/sup>
\nThe remaining area of the park = Area of the whole park – Area of the two paths
\n= 700 \u00d7 300 – 9900
\n= 210000 – 9900
\n= 200100 q.m.<\/p>\n","protected":false},"excerpt":{"rendered":"

AP State Syllabus AP Board 7th Class Maths Solutions Chapter 13 Area and Perimeter Ex 6 Textbook Questions and Answers. AP State Syllabus 7th Class Maths Solutions 13th Lesson Area and Perimeter Exercise 6 Question 1. A path 2.5 m wide is running around a square field whose side is 45 m. Determine the area … Read more<\/a><\/p>\n","protected":false},"author":4,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[9],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/posts\/10654"}],"collection":[{"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/users\/4"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/comments?post=10654"}],"version-history":[{"count":1,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/posts\/10654\/revisions"}],"predecessor-version":[{"id":41040,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/posts\/10654\/revisions\/41040"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/media?parent=10654"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/categories?post=10654"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/tags?post=10654"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}