{"id":19643,"date":"2023-09-16T16:06:28","date_gmt":"2023-09-16T10:36:28","guid":{"rendered":"https:\/\/apboardsolutions.in\/?p=19643"},"modified":"2023-09-19T12:02:30","modified_gmt":"2023-09-19T06:32:30","slug":"ap-board-7th-class-maths-solutions-chapter-1-unit-exercise","status":"publish","type":"post","link":"https:\/\/apboardsolutions.in\/ap-board-7th-class-maths-solutions-chapter-1-unit-exercise\/","title":{"rendered":"AP Board 7th Class Maths Solutions Chapter 1 Integers Unit Exercise"},"content":{"rendered":"

SCERT\u00a0AP 7th Class Maths Solutions Pdf<\/a> Chapter 1 Integers Unit Exercise Questions and Answers.<\/p>\n

AP State Syllabus 7th Class Maths Solutions 1st Lesson Integers Unit Exercise<\/h2>\n

Question 1.
\nCalculate the following.
\n(i) 8 \u00d7 (-1)
\nAnswer:
\n8 \u00d7 (-1)
\nWe know, a \u00d7 (- b) = – (a \u00d7 b)
\n= – (8 \u00d7 1) = – 8<\/p>\n

\"AP<\/p>\n

(ii) (- 2) \u00d7 175
\nAnswer:
\n(-2) \u00d7 175
\nWe know, (- a) \u00d7 b = – (a \u00d7 b)
\n= – (2 \u00d7 175) = – 350<\/p>\n

(iii) (- 3) \u00d7 (-40)
\nAnswer:
\n(- 3) \u00d7 (-40)
\nWe know, (- a) \u00d7 (-b) = (a \u00d7 b)
\n= (- 3) \u00d7 (- 40)
\n= 3 \u00d7 40 = 120<\/p>\n

(iv) (- 24) \u00d7 (- 7)
\nAnswer:
\n(- 24) \u00d7 (- 7)
\nWe know, (- a) \u00d7 (- b) = (a \u00d7 b)
\n= 24 \u00d7 7 = 168<\/p>\n

(v) (- 7) \u00f7 (-1)
\nAnswer:
\n(- 7) \u00f7 (-1)
\nWe know, (- a) + (- b) = a \u00f7 b
\n= (- 7) \u00f7 (- 1)
\n= 7 \u00f7 1 = 7<\/p>\n

(vi) (- 12) \u00f7 (+ 6)
\nAnswer:
\n(- 12) \u00f7 ( + 6)
\nWe know, (- a) \u00f7 (- b) = – (a \u00f7 b)
\n= (- 12) \u00f7 6 = – 2<\/p>\n

(vii) (- 49) \u00f7 (-7 )
\nAnswer:
\n(- 49) \u00f7 (-7)
\nWe know, (- a) \u00f7 (- b) = a \u00f7 b
\n= (- 49) \u00f7 (- 7)
\n= 49 \u00f7 7 = 7<\/p>\n

\"AP<\/p>\n

(viii) (+ 63) \u00f7 (- 9)
\nAnswer:
\n(+ 63) \u00f7 (- 9)
\nWe know, a \u00f7 (- b) = – (a \u00f7 b)
\n= 63 \u00f7 (-9) = – (63 \u00f7 9) = – 7<\/p>\n

Question 2.
\nReplace the blank with an integer to make it a true statement.
\n(i) (- 7) \u00d7 _______ = 21
\nAnswer:
\n(- 7) \u00d7\u00a0 \u00a0x\u00a0\u00a0<\/span> \u00a0= 21
\n\u00d7 = 21 \u00f7 (-7)
\nWe know, a \u00f7 (-b) = – (a \u00f7 b)
\nx = – (21 \u00f7 7)
\n\u2234 x = – 3<\/p>\n

(ii) 7 \u00d7 _______= – 42
\nAnswer:
\n7 \u00d7 \u00a0x\u00a0\u00a0<\/span> = – 42
\nx = (- 42) \u00f7 7
\nWe know, (- a) \u00f7 b = – (a \u00f7 b)
\nx = – (42 \u00f7 7)
\n\u2234 x = – 6<\/p>\n

(iii) ________ \u00d7 (-9) = – 72
\nAnswer:
\n\u00a0 x\u00a0\u00a0<\/span> \u00a0\u00d7 (- 9) = – 72
\nx = (- 72) \u00f7 (- 9)
\nWe know, (- a) \u00f7 (-b) = (a \u00f7 b)
\nx = (72 \u00f7 9)
\n\u2234 x = 8<\/p>\n

(iv) ________ \u00d7 (- 11) = 132
\nAnswer:
\n\u00a0 x\u00a0\u00a0<\/span> \u00a0\u00d7 (- 11) = 132
\n\u00d7 = 132 \u00f7 (-11)
\nWe know, a \u00f7 (- b) = – (a \u00f7 b)
\nx = – (132 \u00f7 11)
\n\u2234 \u00d7 = – 12<\/p>\n

\"AP<\/p>\n

(v) (- 25) \u00f7 ________ = 1
\nAnswer:
\n(- 25) \u00f7\u00a0 \u00a0x\u00a0\u00a0<\/span> \u00a0= 1
\n(- 25) = 1 \u00d7 x
\nx = (- 25) \u00f7 1
\nWe know, (- a) \u00f7 b = – (a \u00f7 b)
\nx = – (25 \u00f7 1)
\n\u2234 x = – 25<\/p>\n

(vi) 42 \u00f7 ________ = – 6
\nAnswer:
\n42 \u00f7\u00a0 \u00a0x\u00a0 <\/span>\u00a0 = – 6
\n42 = (- 6) \u00d7 x
\nx = 42 \u00f7 (- 6)
\nWe know, a \u00f7 (- b) = – (a \u00f7 b)
\nx = – (42 \u00f7 6)
\n\u2234 x = – 7<\/p>\n

(vii) ______ \u00f7 4 (- 15) = 6
\nAnswer:
\n\u00a0 x\u00a0\u00a0<\/span> \u00a0\u00d7 4 (- 15) = 6
\nx = 6 \u00d7 (- 15)
\nWe know, a \u00d7 (-b) = – (a \u00d7 b)
\nx = – (6 \u00d7 15)
\n\u2234 x = – 90<\/p>\n

(viii) ________ \u00f7 (- 9) = 16
\nAnswer:
\n\u00a0 x\u00a0\u00a0<\/span> \u00a0\u00f7 (- 9) = 16
\nx = 16 \u00d7 (- 9)
\nWe know, a \u00d7 (- b) = – (a \u00d7 b)
\nx = – (16 \u00d7 9)
\n\u2234 x = – 144<\/p>\n

\"AP<\/p>\n

Question 3.
\nWrite all the possible pairs of integers that give a product of – 50.
\nAnswer:<\/p>\n\n\n\n\n\n\n\n\n\n\n\n
a<\/td>\nb<\/td>\na \u00d7 b = – 50<\/td>\n<\/tr>\n
41<\/td>\n(-50)<\/td>\n41 \u00d7 (-50) = – 50<\/td>\n<\/tr>\n
(-D<\/td>\n(+50)<\/td>\n(-1) \u00d7 (50) = – 50<\/td>\n<\/tr>\n
+2<\/td>\n(-25)<\/td>\n42 \u00d7 (-25) = – 50<\/td>\n<\/tr>\n
(-2)<\/td>\n(+25)<\/td>\n(-2) \u00d7 (25) = – 50<\/td>\n<\/tr>\n
+5<\/td>\n(-10)<\/td>\n45 \u00d7 (-10) = – 50<\/td>\n<\/tr>\n
(-5)<\/td>\n(+10)<\/td>\n(-5) \u00d7 (10) = – 50<\/td>\n<\/tr>\n
450<\/td>\n(-D<\/td>\n50 \u00d7 (-1) = – 50<\/td>\n<\/tr>\n
(-50)<\/td>\n(1)<\/td>\n(-50) \u00d7 (1) = – 50<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

Question 4.
\nSarikar, a fruit vendor sells 100 kg of oranges and 75 kg of pomegranates. If he makes a profit of \u20b9 11 per one kg of pomegranates and loss of \u20b9 8 per one kg oranges, what will be his overall profit or loss ?
\n\"AP
\nAnswer:
\nGiven
\nProfit on 1 kg of pomegranates = \u20b9 11
\nProfit on 75 kg of pomegranates
\n= 75 \u00d7 11
\n= \u20b9 825
\nLoss on 1 kg of oranges = \u20b9 8
\nLoss on 100 kg of oranges
\n= 100 \u00d7 8
\n= \u20b9 800
\nProfit is greater than loss.
\nSo, Sankar will get profit.
\nOverall profit = \u20b9 825 – \u20b9 800
\n= \u20b9 25<\/p>\n

\"AP<\/p>\n

Question 5.
\nBhargavi lost 5700 calories in the month of June using yoga. If the calory loss is uniform, calculate the loss of calories per day ?
\n\"AP
\nAnswer:
\nGiven number of calories Bhargavi lost in the month of June = 5700 calories June month has 30 days.
\nSo, number of calories lost in 30 days = 5700
\nNumber of calories lost in 1 day = 5700 \u00f7 30
\nNumber of calories lost per day = 190 Calories.<\/p>\n

Question 6.
\nSimplify 625 \u00d7 (-35) + 625 \u00d7 30 using suitable law.
\nAnswer:
\n625 \u00d7 (-35) + 625 \u00d7 30
\nMultiplication distributes over addition of integers.
\nWe know, a \u00d7 b + a \u00d7 c = a(b + c)
\n= 625 [(- 35) + 30]
\n= 625 (- 35 + 30)
\n= 625 (- 5)
\nWe know, a \u00d7 (- b) = – (a \u00d7 b)
\n= – (625 \u00d7 5)
\n= – 3125<\/p>\n

Question 7.
\nSimplify the following using BODMAS.
\n(i) 12 – 36 \u00f7 3
\nAnswer:
\n12 – 36 = 3 (Division)
\n= 12 – 12 (Subtraction)
\n= 0<\/p>\n

(ii) 6 \u00d7 (-7) + (- 3) \u00f7 3
\nAnswer:
\n6 \u00d7 (- 7) + (- 3) \u00f7 3
\nWe know, (- a) \u00f7 b = – (a \u00f7 b)
\n= 6 \u00d7 (- 7) – 3 \u00f7 3 (Division)
\nWe know, a \u00d7 (-b) = – (a \u00d7 b)
\n= – (6 \u00d7 7) – 1 (Multiplication)
\n= – 42 – 1 (Subtraction)
\n= – 43<\/p>\n

\"AP<\/p>\n

(iii) 38 – {35 – (36 – \\(\\overline{34-37}\\))}
\nAnswer:
\n38 – {35 – (36 – \\(\\overline{34-37}\\))} (Vinculum)
\n= 38 – {35 – (36 – (-3)}
\n= 38 – {35 – (36 + 3)} (Simple bracket)
\n= 38 – {35 – 39} (Curly bracket)
\n= 38 – (-4)
\n= 38 + 4 (Addition)
\n= 42<\/p>\n

Question 8.
\nWrite the absolute values of following numbers.
\n(i) – 700
\nAnswer:
\nWe know, |- x| = x
\n|- 700| = 700<\/p>\n

(ii) 150
\nAnswer:
\nWe know, | x | = + x
\nSo, |150| = 150<\/p>\n

(iii) – 150
\nAnswer:
\nWe know, | – x | = x
\nSo, |- 150| = 150<\/p>\n

(iv) – 35
\nAnswer:
\nWe know, | – x | = x
\nSo, |- 35| = 35<\/p>\n

(v) If p < 10, then |p – 10|
\nAnswer:
\nWe know, if \u00d7 < a, then |x – a | = a – x
\nSo, |p – 10| = 10 – p<\/p>\n

\"AP<\/p>\n

(vi) If y > 7, then |7 – y|
\nAnswer:
\nWe know, if x > a, then |a – x| = x – a
\nSo, |7 – y | = y – 7<\/p>\n","protected":false},"excerpt":{"rendered":"

SCERT\u00a0AP 7th Class Maths Solutions Pdf Chapter 1 Integers Unit Exercise Questions and Answers. AP State Syllabus 7th Class Maths Solutions 1st Lesson Integers Unit Exercise Question 1. Calculate the following. (i) 8 \u00d7 (-1) Answer: 8 \u00d7 (-1) We know, a \u00d7 (- b) = – (a \u00d7 b) = – (8 \u00d7 1) … Read more<\/a><\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[9],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/posts\/19643"}],"collection":[{"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/comments?post=19643"}],"version-history":[{"count":1,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/posts\/19643\/revisions"}],"predecessor-version":[{"id":19644,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/posts\/19643\/revisions\/19644"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/media?parent=19643"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/categories?post=19643"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/tags?post=19643"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}