{"id":29330,"date":"2024-02-27T15:42:08","date_gmt":"2024-02-27T10:12:08","guid":{"rendered":"https:\/\/apboardsolutions.in\/?p=29330"},"modified":"2024-02-28T09:40:39","modified_gmt":"2024-02-28T04:10:39","slug":"ap-inter-1st-year-maths-1a-solutions-chapter-3-ex-3a-in-telugu","status":"publish","type":"post","link":"https:\/\/apboardsolutions.in\/ap-inter-1st-year-maths-1a-solutions-chapter-3-ex-3a-in-telugu\/","title":{"rendered":"AP Inter 1st Year Maths 1A Solutions Chapter 3 \u0c2e\u0c3e\u0c24\u0c4d\u0c30\u0c3f\u0c15\u0c32\u0c41 Ex 3(a)"},"content":{"rendered":"

Practicing the Intermediate 1st Year Maths 1A Textbook Solutions<\/a> Chapter 3 \u0c2e\u0c3e\u0c24\u0c4d\u0c30\u0c3f\u0c15\u0c32\u0c41 Exercise 3(a) will help students to clear their doubts quickly.<\/p>\n

AP Inter 1st Year Maths 1A Solutions Chapter 3 \u0c2e\u0c3e\u0c24\u0c4d\u0c30\u0c3f\u0c15\u0c32\u0c41 Exercise 3(a)<\/h2>\n

I.<\/span><\/p>\n

Question 1.
\n\u0c08 \u0c15\u0c4d\u0c30\u0c3f\u0c02\u0c26\u0c3f\u0c35\u0c3e\u0c1f\u0c3f\u0c28\u0c3f \u0c12\u0c15\u0c47 \u0c2e\u0c3e\u0c24\u0c4d\u0c30\u0c3f\u0c15\u0c17\u0c3e \u0c35\u0c4d\u0c30\u0c3e\u0c2f\u0c02\u0c21\u0c3f.
\n(i) [2 1 3] + [0 0 0]
\n(ii) \\(\\left[\\begin{array}{c}
\n0 \\\\
\n1 \\\\
\n-1
\n\\end{array}\\right]+\\left[\\begin{array}{c}
\n-1 \\\\
\n1 \\\\
\n0
\n\\end{array}\\right]\\)
\n(iii) \\(\\left[\\begin{array}{ccc}
\n3 & 9 & 0 \\\\
\n1 & 8 & -2
\n\\end{array}\\right]+\\left[\\begin{array}{ccc}
\n4 & 0 & 2 \\\\
\n7 & 1 & 4
\n\\end{array}\\right]\\)
\n(iv) \\(\\left[\\begin{array}{cc}
\n-1 & 2 \\\\
\n1 & -2 \\\\
\n3 & -1
\n\\end{array}\\right]+\\left[\\begin{array}{cc}
\n0 & 1 \\\\
\n-1 & 0 \\\\
\n-2 & 1
\n\\end{array}\\right]\\)
\nSolution:
\n\"AP
\n\"AP<\/p>\n

Question 2.
\nA = \\(\\left[\\begin{array}{cc}
\n-1 & 3 \\\\
\n4 & 2
\n\\end{array}\\right]\\), B = \\(\\left[\\begin{array}{cc}
\n2 & 1 \\\\
\n3 & -5
\n\\end{array}\\right]\\), X = \\(\\left[\\begin{array}{ll}
\nx_1 & x_2 \\\\
\nx_3 & x_4
\n\\end{array}\\right]\\), A + B = X \u0c05\u0c2f\u0c3f\u0c24\u0c47 x1<\/sub>, x2<\/sub>, x3<\/sub>, x4<\/sub> \u0c32 \u0c35\u0c3f\u0c32\u0c41\u0c35\u0c32\u0c41 \u0c15\u0c28\u0c41\u0c15\u0c4d\u0c15\u0c4b\u0c02\u0c21\u0c3f.
\nSolution:
\nA + B = X \u0c15\u0c28\u0c41\u0c15
\n\"AP
\n\u2234 x1<\/sub> = 1, x2<\/sub> = 4, x3<\/sub> = 7, x4<\/sub> = -3<\/p>\n

\"AP<\/p>\n

Question 3.
\nA = \\(\\left[\\begin{array}{ccc}
\n-1 & -2 & 3 \\\\
\n1 & 2 & 4 \\\\
\n2 & -1 & 3
\n\\end{array}\\right]\\), B = \\(\\left[\\begin{array}{ccc}
\n1 & -2 & 5 \\\\
\n0 & -2 & 2 \\\\
\n1 & 2 & -3
\n\\end{array}\\right]\\), C = \\(\\left[\\begin{array}{ccc}
\n-2 & 1 & 2 \\\\
\n1 & 1 & 2 \\\\
\n2 & 0 & 1
\n\\end{array}\\right]\\) \u0c05\u0c2f\u0c3f\u0c24\u0c47 A + B + C \u0c28\u0c3f \u0c15\u0c28\u0c41\u0c15\u0c4d\u0c15\u0c4b\u0c02\u0c21\u0c3f.
\nSolution:
\n\"AP<\/p>\n

Question 4.
\nA = \\(\\left[\\begin{array}{ccc}
\n3 & 2 & -1 \\\\
\n2 & -2 & 0 \\\\
\n1 & 3 & 1
\n\\end{array}\\right]\\), B = \\(\\left[\\begin{array}{ccc}
\n3 & 2 & -1 \\\\
\n2 & -2 & 0 \\\\
\n1 & 3 & 1
\n\\end{array}\\right]\\), X = A + B \u0c05\u0c2f\u0c3f\u0c24\u0c47, \u0c2e\u0c3e\u0c24\u0c4d\u0c30\u0c3f\u0c15 X \u0c28\u0c41 \u0c15\u0c28\u0c41\u0c15\u0c4d\u0c15\u0c4b\u0c02\u0c21\u0c3f.
\nSolution:
\n\"AP<\/p>\n

\"AP<\/p>\n

Question 5.
\n\\(\\left[\\begin{array}{cc}
\nx-3 & 2 y-8 \\\\
\nz+2 & 6
\n\\end{array}\\right]=\\left[\\begin{array}{cc}
\n5 & 2 \\\\
\n-2 & a-4
\n\\end{array}\\right]\\) \u0c05\u0c2f\u0c3f\u0c24\u0c47 x, y, z, a \u0c35\u0c3f\u0c32\u0c41\u0c35\u0c32\u0c28\u0c41 \u0c15\u0c28\u0c41\u0c15\u0c4d\u0c15\u0c4b\u0c02\u0c21\u0c3f. [May ’06]
\nSolution:
\n\\(\\left[\\begin{array}{cc}
\nx-3 & 2 y-8 \\\\
\nz+2 & 6
\n\\end{array}\\right]=\\left[\\begin{array}{cc}
\n5 & 2 \\\\
\n-2 & a-4
\n\\end{array}\\right]\\)
\n\u2234 x – 3 = 5
\n\u21d2 x = 3 + 5 = 8
\n2y – 8 = 2
\n\u21d2 2y = 8 + 2 = 10
\n\u21d2 y = 5
\nz + 2 = -2
\n\u21d2 z = -2 – 2 = -4
\na – 4 = 6
\n\u21d2 a = 4 + 6 = 10<\/p>\n

II.<\/span><\/p>\n

Question 1.
\n\\(\\left[\\begin{array}{ccc}
\nx-1 & 2 & 5-y \\\\
\n0 & z-1 & 7 \\\\
\n1 & 0 & a-5
\n\\end{array}\\right]=\\left[\\begin{array}{ccc}
\n1 & 2 & 3 \\\\
\n0 & 4 & 7 \\\\
\n1 & 0 & 0
\n\\end{array}\\right]\\) \u0c05\u0c2f\u0c3f\u0c24\u0c47 x, y, z, a \u0c32 \u0c35\u0c3f\u0c32\u0c41\u0c35\u0c32\u0c41 \u0c15\u0c28\u0c41\u0c15\u0c4d\u0c15\u0c4b\u0c02\u0c21\u0c3f.
\nSolution:
\n\\(\\left[\\begin{array}{ccc}
\nx-1 & 2 & 5-y \\\\
\n0 & z-1 & 7 \\\\
\n1 & 0 & a-5
\n\\end{array}\\right]=\\left[\\begin{array}{ccc}
\n1 & 2 & 3 \\\\
\n0 & 4 & 7 \\\\
\n1 & 0 & 0
\n\\end{array}\\right]\\)
\n\u2234 x – 1 = 1
\n\u21d2 x = 1 + 1 = 2
\n5 – y = 3
\n\u21d2 y = 5 – 3 = 2
\nz – 1 = 4
\n\u21d2 z = 4 + 1 = 5
\na – 5 = 0
\n\u21d2 a = 5<\/p>\n

Question 2.
\nA = \\(\\left[\\begin{array}{ccc}
\n1 & 3 & -5 \\\\
\n2 & -1 & 5 \\\\
\n2 & 0 & 1
\n\\end{array}\\right]\\) \u0c05\u0c2f\u0c3f\u0c24\u0c47 \u0c1c\u0c3e\u0c21 A \u0c15\u0c28\u0c41\u0c15\u0c4d\u0c15\u0c4b\u0c02\u0c21\u0c3f. [May ’13]
\nSolution:
\n\u0c1c\u0c3e\u0c21 A = \u0c2a\u0c4d\u0c30\u0c27\u0c3e\u0c28 \u0c35\u0c3f\u0c15\u0c30\u0c4d\u0c23 \u0c2e\u0c42\u0c32\u0c15\u0c3e\u0c32 \u0c2e\u0c4a\u0c24\u0c4d\u0c24\u0c02
\n= 1 – 1 + 1
\n= 1<\/p>\n

\"AP<\/p>\n

Question 3.
\nA = \\(\\left[\\begin{array}{ccc}
\n0 & 1 & 2 \\\\
\n2 & 3 & 4 \\\\
\n4 & 5 & -6
\n\\end{array}\\right]\\), B = \\(\\left[\\begin{array}{ccc}
\n-1 & 2 & 3 \\\\
\n0 & 1 & 0 \\\\
\n0 & 0 & -1
\n\\end{array}\\right]\\) \u0c05\u0c2f\u0c3f\u0c24\u0c47 B – A, 4A – 5B \u0c32\u0c28\u0c41 \u0c15\u0c28\u0c41\u0c15\u0c4d\u0c15\u0c4b\u0c02\u0c21\u0c3f.
\nSolution:
\n\"AP
\n\"AP<\/p>\n

Question 4.
\nA = \\(\\left[\\begin{array}{lll}
\n1 & 2 & 3 \\\\
\n3 & 2 & 1
\n\\end{array}\\right]\\), B = \\(\\left[\\begin{array}{lll}
\n3 & 2 & 1 \\\\
\n1 & 2 & 3
\n\\end{array}\\right]\\) \u0c05\u0c2f\u0c3f\u0c24\u0c47 3B – 2A \u0c28\u0c41 \u0c15\u0c28\u0c41\u0c15\u0c4d\u0c15\u0c4b\u0c02\u0c21\u0c3f.
\nSolution:
\nA = \\(\\left[\\begin{array}{lll}
\n1 & 2 & 3 \\\\
\n3 & 2 & 1
\n\\end{array}\\right]\\), B = \\(\\left[\\begin{array}{lll}
\n3 & 2 & 1 \\\\
\n1 & 2 & 3
\n\\end{array}\\right]\\)
\n\"AP<\/p>\n","protected":false},"excerpt":{"rendered":"

Practicing the Intermediate 1st Year Maths 1A Textbook Solutions Chapter 3 \u0c2e\u0c3e\u0c24\u0c4d\u0c30\u0c3f\u0c15\u0c32\u0c41 Exercise 3(a) will help students to clear their doubts quickly. AP Inter 1st Year Maths 1A Solutions Chapter 3 \u0c2e\u0c3e\u0c24\u0c4d\u0c30\u0c3f\u0c15\u0c32\u0c41 Exercise 3(a) I. Question 1. \u0c08 \u0c15\u0c4d\u0c30\u0c3f\u0c02\u0c26\u0c3f\u0c35\u0c3e\u0c1f\u0c3f\u0c28\u0c3f \u0c12\u0c15\u0c47 \u0c2e\u0c3e\u0c24\u0c4d\u0c30\u0c3f\u0c15\u0c17\u0c3e \u0c35\u0c4d\u0c30\u0c3e\u0c2f\u0c02\u0c21\u0c3f. (i) [2 1 3] + [0 0 0] (ii) (iii) (iv) Solution: Question … Read more<\/a><\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[14],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/posts\/29330"}],"collection":[{"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/comments?post=29330"}],"version-history":[{"count":4,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/posts\/29330\/revisions"}],"predecessor-version":[{"id":29342,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/posts\/29330\/revisions\/29342"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/media?parent=29330"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/categories?post=29330"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/tags?post=29330"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}