{"id":33008,"date":"2023-01-06T17:50:17","date_gmt":"2023-01-06T12:20:17","guid":{"rendered":"https:\/\/apboardsolutions.in\/?p=33008"},"modified":"2023-01-06T17:50:17","modified_gmt":"2023-01-06T12:20:17","slug":"ap-inter-1st-year-maths-1a-solutions-chapter-9-ex-9a-in-telugu","status":"publish","type":"post","link":"https:\/\/apboardsolutions.in\/ap-inter-1st-year-maths-1a-solutions-chapter-9-ex-9a-in-telugu\/","title":{"rendered":"AP Inter 1st Year Maths 1A Solutions Chapter 9 \u0c05\u0c24\u0c3f\u0c2a\u0c30\u0c3e\u0c35\u0c32\u0c2f \u0c2a\u0c4d\u0c30\u0c2e\u0c47\u0c2f\u0c3e\u0c32\u0c41 Ex 9(a)"},"content":{"rendered":"

Practicing the Intermediate 1st Year Maths 1A Textbook Solutions<\/a> Chapter 9 \u0c05\u0c24\u0c3f\u0c2a\u0c30\u0c3e\u0c35\u0c32\u0c2f \u0c2a\u0c4d\u0c30\u0c2e\u0c47\u0c2f\u0c3e\u0c32\u0c41 Exercise 9(a) will help students to clear their doubts quickly.<\/p>\n

AP Inter 1st Year Maths 1A Solutions Chapter 9 \u0c05\u0c24\u0c3f\u0c2a\u0c30\u0c3e\u0c35\u0c32\u0c2f \u0c2a\u0c4d\u0c30\u0c2e\u0c47\u0c2f\u0c3e\u0c32\u0c41 Exercise 9(a)<\/h2>\n

Question 1.
\nsinh x = \\(\\frac{3}{4}\\) \u0c05\u0c2f\u0c3f\u0c24\u0c47 cosh (2x), sinh (2x) \u0c35\u0c3f\u0c32\u0c41\u0c35\u0c32\u0c41 \u0c15\u0c28\u0c41\u0c15\u0c4d\u0c15\u0c4b\u0c02\u0c21\u0c3f. [Mar. ’14, ’12]
\nSolution:
\n\"AP<\/p>\n

Question 2.
\nsinh x = 3 \u0c05\u0c2f\u0c3f\u0c28\u0c2a\u0c4d\u0c2a\u0c41\u0c21\u0c41 x = loge<\/sub>(3 + \u221a10) \u0c05\u0c28\u0c3f \u0c1a\u0c42\u0c2a\u0c02\u0c21\u0c3f.
\nSolution:
\n\"AP<\/p>\n

\"AP<\/p>\n

Question 3.
\n(i) tanh (x – y) = \\(\\frac{\\tanh x-\\tanh y}{1-\\tanh x \\tanh y}\\)
\nSolution:
\n\"AP<\/p>\n

(ii) coth (x – y) = \\(\\frac{{coth} x \\cdot {coth} y-1}{{coth} y-{coth} x}\\) \u0c05\u0c28\u0c3f \u0c28\u0c3f\u0c30\u0c42\u0c2a\u0c3f\u0c02\u0c1a\u0c02\u0c21\u0c3f.
\nSolution:
\n\"AP<\/p>\n

Question 4.
\n\u0c2a\u0c4d\u0c30\u0c24\u0c3f n \u2208 R \u0c15\u0c41,
\n(i) (cosh x – sinh x)n<\/sup> = cosh (nx) \u2013 sinh (nx) [(T.S) Mar. ’15, ’07, ’06]
\nSolution:
\n\"AP<\/p>\n

(ii) (cosh x + sinh x)n<\/sup> = cosh (nx) + sinh (nx) \u0c05\u0c28\u0c3f \u0c28\u0c3f\u0c30\u0c42\u0c2a\u0c3f\u0c02\u0c1a\u0c02\u0c21\u0c3f.
\nSolution:
\n\"AP<\/p>\n

\"AP<\/p>\n

Question 5.
\nx \u2260 0 \u0c05\u0c2f\u0c3f\u0c24\u0c47 \\(\\frac{\\tanh x}{{sech} x-1}+\\frac{\\tanh x}{{sech} x+1}\\) = -2 cosech x \u0c28\u0c3f\u0c30\u0c42\u0c2a\u0c3f\u0c02\u0c1a\u0c02\u0c21\u0c3f.
\nSolution:
\n\"AP<\/p>\n

Question 6.
\nx \u2260 0 \u0c05\u0c2f\u0c3f\u0c24\u0c47 \\(\\frac{\\cosh x}{1-\\tanh x}+\\frac{\\sinh x}{1-{coth} x}\\) = sinh x + cosh x \u0c05\u0c28\u0c3f \u0c28\u0c3f\u0c30\u0c42\u0c2a\u0c3f\u0c02\u0c1a\u0c02\u0c21\u0c3f.
\nSolution:
\n\"AP<\/p>\n

Question 7.
\n\u0c2a\u0c4d\u0c30\u0c24\u0c40 x \u2208 R \u0c15\u0c41 cosh4<\/sup>x – sinh4<\/sup>x = cosh (2x) \u0c05\u0c28\u0c3f \u0c28\u0c3f\u0c30\u0c42\u0c2a\u0c3f\u0c02\u0c1a\u0c02\u0c21\u0c3f.
\nSolution:
\nLH.S. = cosh4<\/sup>x – sinh4<\/sup>x
\n= (cosh2<\/sup>x)2<\/sup> – (sinh2<\/sup>x)2<\/sup>
\n= [cosh2<\/sup>x – sinh2<\/sup>x] [cosh2<\/sup>x + sinh2<\/sup>x]
\n= (1) cosh (2x)
\n= cosh (2x)
\n\u2234 cosh4<\/sup>x – sinh4<\/sup>x = cosh (2x)<\/p>\n

\"AP<\/p>\n

Question 8.
\nu = \\(\\log _e\\left(\\tan \\left(\\frac{p}{4}+\\frac{q}{2}\\right)\\right)\\), cos \u03b8 > 0, \u0c05\u0c2f\u0c3f\u0c24\u0c47 cosh u = sec \u03b8 \u0c05\u0c28\u0c3f \u0c28\u0c3f\u0c30\u0c42\u0c2a\u0c3f\u0c02\u0c1a\u0c02\u0c21\u0c3f.
\nSolution:
\n\"AP<\/p>\n","protected":false},"excerpt":{"rendered":"

Practicing the Intermediate 1st Year Maths 1A Textbook Solutions Chapter 9 \u0c05\u0c24\u0c3f\u0c2a\u0c30\u0c3e\u0c35\u0c32\u0c2f \u0c2a\u0c4d\u0c30\u0c2e\u0c47\u0c2f\u0c3e\u0c32\u0c41 Exercise 9(a) will help students to clear their doubts quickly. AP Inter 1st Year Maths 1A Solutions Chapter 9 \u0c05\u0c24\u0c3f\u0c2a\u0c30\u0c3e\u0c35\u0c32\u0c2f \u0c2a\u0c4d\u0c30\u0c2e\u0c47\u0c2f\u0c3e\u0c32\u0c41 Exercise 9(a) Question 1. sinh x = \u0c05\u0c2f\u0c3f\u0c24\u0c47 cosh (2x), sinh (2x) \u0c35\u0c3f\u0c32\u0c41\u0c35\u0c32\u0c41 \u0c15\u0c28\u0c41\u0c15\u0c4d\u0c15\u0c4b\u0c02\u0c21\u0c3f. [Mar. ’14, ’12] Solution: Question 2. sinh … Read more<\/a><\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[14],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/posts\/33008"}],"collection":[{"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/users\/5"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/comments?post=33008"}],"version-history":[{"count":2,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/posts\/33008\/revisions"}],"predecessor-version":[{"id":33024,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/posts\/33008\/revisions\/33024"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/media?parent=33008"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/categories?post=33008"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/tags?post=33008"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}