{"id":7577,"date":"2023-05-26T16:06:13","date_gmt":"2023-05-26T10:36:13","guid":{"rendered":"https:\/\/apboardsolutions.in\/?p=7577"},"modified":"2023-05-27T17:19:41","modified_gmt":"2023-05-27T11:49:41","slug":"ap-board-8th-class-maths-solutions-chapter-15-ex-15-2","status":"publish","type":"post","link":"https:\/\/apboardsolutions.in\/ap-board-8th-class-maths-solutions-chapter-15-ex-15-2\/","title":{"rendered":"AP Board 8th Class Maths Solutions Chapter 15 Playing with Numbers Ex 15.2"},"content":{"rendered":"

AP State Syllabus AP Board 8th Class Maths Solutions<\/a> Chapter 15 Playing with Numbers Ex 15.2 Textbook Questions and Answers.<\/p>\n

AP State Syllabus 8th Class Maths Solutions 15th Lesson Playing with Numbers Exercise 15.2<\/h2>\n

\"AP<\/p>\n

Question 1.
\nIf 345 A 7 is divisible by 3,supply the missing digit in place of \u2018A\u2019.
\nSolution:
\nIf the sum of the digits of a number is divisible by 3, then the number is divisible by 3.
\n\u2234 345A7 \u21d2 3 + 4 + 5 + A + 7 = 19 + A
\n19 + A = 3 x 7
\n\u21d2 A = 21 – 19 = 2 \u21d2 A = 24 – 19 = 5<\/p>\n

A + 19 = 3 x 8
\n\u21d2 A = 24 – 19 = 5<\/p>\n

A + 19 = 3 x 9
\n\u21d2 A = 27 – 19 = 8<\/p>\n

\u2234 A = {2,5,8}<\/p>\n

Question 2.
\nIf 2791 A,is divisible by 9, supply the missing digit in place of \u2018A\u2019.
\nSolution:
\nIf the sum of the digits of a number is divisible by 9, then the number is divisible by 9.
\n\u2234 2791A = 2 + 7 + 9 + 1 + A = 9 x 3
\n\u21d2 19 + A = 9 x 3 = 27
\n\u21d2 A = 27 – 19 = 8
\n\u2234 A = 8<\/p>\n

\"AP<\/p>\n

Question 3.
\nWrite some numbers which are divisible by 2,3,5,9 and 10 also.
\nSolution:
\n90, 180, 270. are divisible by 2, 3, 5, 9 and 10.
\n[\u2235 The L.C.M. of 2, 3, 5, 9, 10 is 90]<\/p>\n

Question 4.
\n2A8 is a number divisible by 2, what might be the value of A\u2019?
\nSolution:
\nIf the units digit of a number be 0, 2, 4, 6, 8 then it is divisible by 2.
\n\u2234 2A8 is divisible by 2 for any value of A.
\n\u2234 A = (0, 1, 2 ………………….9)<\/p>\n

Question 5.
\n50B is a number divisible by 5, what might be the value of B?
\nSolution:
\nGiven number is 50B.
\nThe units digit of a number \u00a1s either \u20180\u2019 or 5, then it is divisible by 5.
\n\u2234 500 \u2192 \\(\\frac { 0 }{ 5 }\\) (R = 0)
\n505 \u2192 \\(\\frac { 5 }{ 5 }\\) (R = 0)
\n\u2234 B = {0, 5}<\/p>\n

\"AP<\/p>\n

Question 6.
\n2P is a number which is divisible by 2 and 3, what is the value of P
\nSolution:
\nThe given number is 2P.
\nIf 2P is divisible by 2, 3 then 2P should be a multiple of 6. [ \u2235 L.C.M. of 2, 3 is 6]
\n\u2234 2P = 24, 30 ………….
\n24 \u2192 2 + 4 \u2192 \\(\\frac { 6 }{ 3 }\\) (R = 0)
\n\u2234 P = 4<\/p>\n

Question 7.
\n54Z leaves remainder 2 when divided by 5 , and leaves remainder 1 when divided by 3, what is the value of Z\u2019?
\nSolution:
\nIf 54Z is divisible by 3 then the sum of the digits of the number is divisible by 3.
\nAccording to problem 54Z is divisible by 3 and leaves remainder 1\u2019.
\n\u2234 5 + 4 + Z = (3 x 4) + 1
\n= 9 + Z = 13
\n\u2234 Z = 4(or)
\n9 + Z = (3 x 5) + 1
\n9 + Z = 16
\nZ = 7
\nIf 54Z is divisible by 5 then Z should be equal to either ‘0\u2019 or \u20185\u2019.
\n\u2234 54(0 + 2) = 542 (Z = 2)
\n54(0 + 7) = 547 (Z = 7)
\n\u2234 From the above two cases
\nZ = 7
\n\u2235 547 \u2192 \\(\\frac{7}{5}\\)(R = 2)<\/p>\n

\"AP<\/p>\n

Question 8.
\n27Q leaves remainder 3 when divided by 5 and leaves remainder 1 when divided by 2, what is the remainder when it is divided by 3?
\nSolution:
\n27Q is divided by 5 gives the remainder 3
\nLe.,27Q = 27 (0 + 3) = 273(Z = 3)(T)
\n= 27 (0 + 8) = 278 (Z = 8)
\n27Q is divided by 2 gives the remainder 1.
\ni.e., 27Q = 27(0 + 1) = 271 (Z = 1)
\n27Q = 27 (0 + 3) = 273 (Z = 3) (T)
\n\u2234 From above situations Z = 3
\n\u2234 27Q = 273\u2192 2 + 7 + 3 \u2192 \\(\\frac{12}{3}\\)(R = 0)
\n\u2234 273 is divisible by 3 and gives the remainder 0\u2019.<\/p>\n","protected":false},"excerpt":{"rendered":"

AP State Syllabus AP Board 8th Class Maths Solutions Chapter 15 Playing with Numbers Ex 15.2 Textbook Questions and Answers. AP State Syllabus 8th Class Maths Solutions 15th Lesson Playing with Numbers Exercise 15.2 Question 1. If 345 A 7 is divisible by 3,supply the missing digit in place of \u2018A\u2019. Solution: If the sum … Read more<\/a><\/p>\n","protected":false},"author":4,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"spay_email":""},"categories":[6],"tags":[],"jetpack_featured_media_url":"","_links":{"self":[{"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/posts\/7577"}],"collection":[{"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/users\/4"}],"replies":[{"embeddable":true,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/comments?post=7577"}],"version-history":[{"count":1,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/posts\/7577\/revisions"}],"predecessor-version":[{"id":40730,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/posts\/7577\/revisions\/40730"}],"wp:attachment":[{"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/media?parent=7577"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/categories?post=7577"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/apboardsolutions.in\/wp-json\/wp\/v2\/tags?post=7577"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}