AP State Syllabus AP Board 6th Class Maths Solutions Chapter 6 Basic Arithmetic Ex 6.3 Textbook Questions and Answers.
AP State Syllabus 6th Class Maths Solutions 6th Lesson Basic Arithmetic Ex 6.3
Question 1.
If the cost of 3 apples is Rs. 60/-, then find the cost of 7 apples.
Answer:
Cost of 3 apples = Rs. 60
Cost of 1 apple = \(\frac{60}{3}\) = Rs. 20
∴ Cost of 7 apples = 7 × Rs. 20 = Rs. 140
Question 2.
Uma bought 8 books for a total of ? 120. How much would she pay for just 5 books?
Answer:
Cost of 8 books = Rs. 120
Cost of 1 book = \(\frac{120}{8}\) = Rs. 15
∴ Cost of 5 books = 5 × 15 = Rs. 75
Question 3.
The cost of 5 fans is Rs. 11,000/-. Find the number of funs that can be purchased for Rs. 4,400/-.
Answer:
Cost of 5 fans = Rs. 11000
Cost of 1 fan = \(\frac{11000}{5}\) = Rs. 2200
Number of fans can be purchased for Rs. 4400 = 4400 ÷ cost of 1 fan = \(\frac{4400}{2200}\) = 2
Question 4.
A car is moving at a constant speed covers a distance of 180 km in 3 hours. Find the time taken by the car to cover a distance of 420 km at the same speed.
Answer:
Distance covered = 180 km
Time taken = 3 Hrs.
Distance to be covered = 420 km
Time required = ? = x (say)
Since the car is moving at a constant speed, we have
180 : 3 is as to 420 : x
180 : 3 :: 420 : x
Its a proportion.
So, product of extremes = Product of means
180 × x = 3 × 420
∴ Time required = 7 Hrs.
(OR)
Distance covered by a car in 3 hours = 180 km
Distance covered by a car in 1 hour = 180 ÷ 3
Time taken to cover 60 km distance = \(\frac{180}{3}\) = 60 km
Time taken to cover 420 km distance = 420 ÷ 60 = \(\frac{420}{60}\) = 7 hours
Question 5.
A truck requires 108 litres of diesel for covering a distance of 594 km. How much diesel will be required by the truck to cover a distance of 1650 km?
Answer:
108 : 594 :: x : 1650
So, 108 × 1650 = x × 594
∴ x = \(\frac{108 \times 1650}{\hline 594}\) = 300 litres
(OR)
Distance covered by truck with 108 litres diesel = 594 km
Distance covered by truck with 1 litre of diesel = \(\frac{594}{108}\) km
Diesel required to cover 1650 km distance = 1650 ÷ \(\frac{594}{108}\) = 1650 × \(\frac{108}{594}\)
Diesel required to cover 1650 km distance = 300 litres.