Andhra Pradesh AP Board 4th Class Maths Solutions 10th Lesson Measurements Textbook Exercise Questions and Answers.

## AP State Syllabus 4th Class Maths Solutions Chapter 10 Measurements

Activity

Make the students into 4 groups. Provide 1m thread to each group. Ask each group to cut the given thread into possible equal parts as given in the table and complete the table.

Solution:

Exercise – 1

1. Convert the following into centimetres:

a) 18m = 18 × __________ = __________ cm

Solution:

18m = 18 × 100 = 1800 cm

b) 100 m = 100 × __________ = ____________

Solution:

100m = 100 × 100 = 10,000 cm

c) 17 m 25 cm = 17 × __________ cm + 25 cm – __________ cm + __________ cm = __________ cm

Solution:

17 m 25 cm = 17 × 100 cm + 25 cm – 1700 cm + 25 cm = 1,725 cm

d) 45 m 75 cm =45 × __________ cm + __________ cm = __________ cm + __________ cm = __________ cm

Solution:

45 m 75 cm =45 × 100 cm + 75 cm = 4,500 cm + 75 cm = 4,575 cm

2. Convert centimetres into metres and centimetres.

a) 269cm = ___________

Solution:

269 cm = 2.69 m {∵ \(\frac{269}{100}\)}

b) 693cm = ________

Solution:

693 cm = \(\frac{693}{100}\) = 6.93 m

c) 703 cm = ___________

Solution:

703 cm = \(\frac{703}{100}\) = 7.03 m

d) 400 cm = ____________

Solution:

400 cm = \(\frac{400}{100}\) = 4 m

Question 3.

Match the following:

Solution:

Question 4.

Fill in the blanks with suitible symbol <, > or =

a) 4 m 90 cm ___________ 480 cm

b) 67 m ___________ 6800 cm

c) 75 m ___________ 7500 cm

d) 80 m ___________ 9000 cm

Solution:

a) 4 m 90 cm > 480 cm

b) 67 m < 6800 cm

c) 75 m = 7500 cm

d) 80 m < 9000 cm

Textbook Page No. 136

Think and Discuss

Can you cut a rope of length 1m into 4 equal pieces without measuring it. How?

Solution:

Yes, it is possible. The rope is one meter long. If we divide into 4 equal parts, each part is 1/4 of the length of the rope by folding method.

Exercise – 10.1

1. Do the following.

a)

Solution:

b)

Solution:

c)

Solution:

d)

Solution:

2. Do the following.

a) 10 m 55 cm + 65 m 65 cm

Solution:

b) 98 m 50 cm + 115 m 45 cm

Solution:

c) 684 m + 225 m 80 cm

Solution:

d) 60 m 45 cm + 85 m 28 cm

Solution:

3. Do the following.

a)

Solution:

b)

Solution:

c)

Solution:

d)

Solution:

4. Do the following.

a) 75 m 85 cm – 10 m 30 cm

Solution:

b) 69 m 50 cm – 25 m 60 cm

Solution:

c) 95 m – 88 m 40cm

Solution:

Question 5.

Radha’s elder son needs in lm 80 cm of cloth whereas younger son needs 1 m 60 cm of cloth for their shirts. How much length of cloth is needed for them ?

Solution:

Length of cloth required to Radha’s elder son = 1 m 80 cm

Length of cloth required to Radha’s younger son = 1 m 60 cm

Length of cloth required to both of them = 3 m 40 cm

Question 6.

The length of a flower bed is 20 m 50 cm. Radha dug a length of 8 cm 50 cm. Then still how much length of the flower bed is to be dug ?

Solution:

Actual length of flower bed = 20 m 50 cm

Radha dug length of a flower bed = 8 cm 50 cm

∴ Required length of a flower bed = 12 m

Question 7.

Balamma is working in a handloom industry. She spins yarn of length 720 m 50 cm and 850 m 30 cm on successive days, then how much yarn has she spun in both the days ?

Solution:

Balamma spins yam of length on first day = 720 m 50 cm

Balamma spins yam of length on second day = 850 m 30 cm

Balamma spins yam of length on both the days = 1570 m 80 cm

Question 8.

If tw0 ropes of length 10 m 50 cm and 9 m 60 cm are tied together. Then the length of the rope so formed is ? (Approximately)

Solution:

Length of first rope = 10 m 50 cm

Length of second rope = 9 m 60 cm

Length of rope so formed totally = 20 m 10 cm

Question 9.

Narayana can make 60 m thread in one day. If he completes 36 m 50 cm by the afternoon, how much length of thread is to be made by him ?

Solution:

Length of thread made in one day by Narayana = 60 m

Length of thread made by afternoon = 36 m 50 cm

Length is to be made by him = 23 m 50 cm

Textbook Page No. 140

Do this

1. Convert the following into grams.

a) 5 kg = 5 × 1000 grams = __________ grams

Solution:

5 kg = 5 × 1000 grams = 5,000 grams

b) 15 kg = 15 × __________ grams = __________ grams

Solution:

15 kg = 15 × 100 grams = 15,000 grams

c) 7 kg 250 g = __________ × __________ g + __________ g = __________ g + __________ g = __________ g

Solution:

7 kg 250 g = 7 × 1,000 g + 250 g = 7,000 g + 250 g = 7,250 g

d) 35 kg 500 g = __________ × __________ g + __________ g = __________ g + __________ g = __________ g

Solution:

35 kg 500 g = 55 × 1,000 g + 500 g = 55,000 g + 500 g = 55,000 g

2. Convert into kilograms.

a) 2680 grams

Solution:

2680 grams = 2000 g + 680 g

= 2 × 1000 g + 680 g

= 2 × 1 kg + 680 g

= 2 kg + 680 g

= 2 kg 680 g

b) 7455 grams

Solution:

7455 grams = 7000g + 455 g

= 7 × 1000 g + 455 g

= 7 × 1 kg + 455 g

= 7 kg + 455 g

= 7 kg 455 g

c) 4,000 grams

Solution:

4,000 grams = 4 × 1000 grams

= 4 kg

d) 8050 grams

Solution:

8050 grams = 8000g + 50 g

= 8 × 1000 g + 50 g

= 8 kg + 50 g

= 8 kg. 50g

Question 3.

Suggest the suitable symbol in the provided space (<, > or =)

a) 4 kg 900g ________ 4800 g

b) 67 kg ________ 68000 g

c) 75 kg ________ 75000 g

d) 80 kg ________ 9000g

Solution:

a) 4 kg 900g > 4800 g

b) 67 kg < 68000 g

c) 75 kg = 75000 g

d) 80 kg > 9000 g

Exercise – 10.3

1. Add.

a)

Solution:

b)

Solution:

c)

Solution:

d)

Solution:

2. Do the following.

a) 2 kg 250 g + 12 kg 580 g

Solution:

b 500 kg 750 g + 250 kg 800 g

Solution:

c) 580 kg 500 g + 400 kg 680 g

Solution:

3. Subtract

a)

Solution:

b)

Solution:

c)

Solution:

d)

Solution:

4. Do the following.

a) 5 kg 450 g – 3 kg 500 g

Solution:

b) 50 kg 280 g – 12 kg 450 g

Solution:

c) 100 kg 150 g – 85 kg 280g

Solution:

d) 85 kg 250 g – 40 kg 500g

Solution:

Question 5.

A school has a stock of 25 kg 600 g rice. 198 kg 300 g of rice was supplied for the midday meal scheme. Now how many kilograms of rice is available in the school ?

Solution:

Stock of rice a school has = 250 kg 600 g

Supplied stock to mid day meals was = 198 kg 300 g

Now available rice in the school = 52 kg 300 g

Question 6.

To make a sweet the maker added 10 kg 600g of jaggery, 20 kg 350 g of atta and 500g of ghee. What is the total weight of these three ?

Solution:

Weight of jaggery used = 10 kg 600g

Weight of atta used = 20 kg 350 g

Weight of ghee used = 500g

Total weight at these three = 31 kg 450 g

Question 7.

Rangayya bought 1 kg 500g of potatoes, 750 g of carrot, 500g of tomatoes and 2 kg of onions. What is the total weight of vegetables he bought ?

Solution:

Weight of Potatoes = 1 kg 500g

Weight of Carrot = 750 g

Weight of Tomatoes = 500g

Weight of Onions = 2 kg

Total weight of vegetables = 4 kg 750 g

Question 8.

There s 100 kg of sugar in a shop. If the shop keeper sells out 78 kg, find the sugar left in the shop.

Solution:

Quality of sugar in the shop = 100 kgs

Quality of sugar sold = 78 kgs

Quality of sugar left in the shop = 22 kgs

Question 9.

Chinnayya collected 108 kg 800 g of tamarind from one tree and 120 kg tamarind from another tree. If he sells 150 kg from that, how many kilos of tamarind did he have now ?

Solution:

Quantity of tamarind collected from first tree = 108 kg 800 g

Quantity of tamarind collected from second tree = 120 kg

Total collected tamarind = 228 kg 800 g

Quantity of tamarind sold = 150 kg

∴ Remaining tamarind = 78 kg 800 g

Question 10.

Rajani melted 25g amd 28 g weights of gold ear rings. She got 49g of gold. How much weight of gold is lost in melting ?

Solution:

Sum of weights of ear rings = 25g + 28g = 53 g

After melting weight of gold = 49 g

Question 11.

The vendor collected 76 kg butter and mixed it with 12 kg 500 g of butter that is already in his shop. If he sells 82 kg of butter bow much will be left with him ?

Solution:

Quantity of butter in the shop = 12 kg 500 g

Quantity of collected butter = 76 kg

Total butter at vendor =

Vendor sold butter quantity = 82 kg

Quantity of butter left him = 6 kg 500 g

Question 12.

The weight of a new born baby was 2 kg 800g. After 2 years her weight is 8 kg 300 g. Calculate the weight gained.

Solution:

The weight of a new bom baby = 2 kg 800g

After 2 years weight of a new born baby = 8 kg 300 g

∴ Gained weight at baby in 2 yrs = 5 kg 500 g

Question 13.

40 kg 500 g of putharekulu were prepared in a sweet shop on first day and 45 kg 800g of putharekulu on the second day. If he sells 65 kg putharekulu then how much will be left with him ?

Solution:

Prepared weight of putarekulu in the first day = 40 kg 500 g

Prepared weight of putarekulu in the second day = 45 kg 800g

Total weight of putarekulu = 86 kg 300 g

Putarekulu sold = 65 kg

Putarekulu left at him = 21 kg 300 g

Textbook Page No. 145

Do this

1. Convert litres into millilitres.

a) 5 litres = 5 × 1000 ml = ________ ml

Solution:

5 litres = 5 × 1000 ml = 5000 ml

b) 18 litres = 18 × ________ ml = ________ ml

Solution:

18 litres = 18 × 1000 ml = 18,000 ml

c) 37 litres = ________ × ________ ml = ________ ml

Solution:

37 litres = 37 × 1000 ml = 37,000 ml

d) 86 litres = ________ × ________ ml = ________ ml

Solution:

86 litres = 86 × 1000 ml = 86,000 ml

e) 100 litres = ________ × ________ ml = ________ ml

Solution:

100 litres = 100 × 1000 ml = 1,00,000 ml

2. Convert millilitres into litres and millilitres.

a) 8250 ml

Solution:

8 × 1000ml + 250 ml

= 8 l 250ml

b) 7000 ml

Solution:

7 × 1000 ml

= 7 × 1 l

= 7 l

c) 5500 ml

Solution:

5 × 1000 ml + 500 ml

= 5 × 1 l + 500 ml

= 5 l 500 ml

d) 4850 ml

Solution:

4 × 1000m l + 850 ml

= 4 × 1 l + 850 ml

= 4 l 850 ml

e) 10550 ml

Solution:

10 × 1000ml + 550 ml

= 10 × 1l + 550 ml

= 10 l 550 ml

Question 3.

Place the correct symbol in the space provided (>, < or =)

a) 6 l _________ 5550 ml

b) 8 l _________ 8000 ml

c) 5 l _________ 6000 ml

d) 3 l _________ 3500 ml

e) 9 l _________ 980 ml

Solution:

a) 6 l > 5550 ml

b) 8 l = 8000 ml

c) 5 l < 6000 ml

d) 3 l < 3500 ml

e) 9 l > 980 ml

Exercise – 10.4

1. Do the following additions.

a)

Solution:

b)

Solution:

c)

Solution:

d)

Solution:

e) 18 l 450 ml + 28 l 890 ml

Solution:

f) 50 l 850 ml + 70 l 450 ml

Solution:

g) 89 l 950 ml + 45 l 650 ml

Solution:

2. Do the following subtractions.

a)

Solution:

b)

Solution:

c)

Solution:

d)

Solution:

e) 15 l 350 ml – 10 l 800 ml

Solution:

f) 70 l 850 ml – 25 l 900 ml

Solution:

g) 99 l 350 ml – 16 l 600 ml

Solution:

h) 25 l – 18 l 250 ml

Solution:

Question 3.

A buffalo gives 3 l 250 ml milk in the morning and 2 l 750 ml in the evening. Find the total milk given by it in one day.

Solution:

Buffaloes gives milk in the morning = 3 l 250 ml

Buffaloes gives milk in the evening = 2 l 750 ml

Buffaloes gives milk total one day = 6 l

Question 4.

Rajesh purchased 1 l 500 ml and 2 l cool drink bottles. What is the total capacity of cool drink he purchased ?

Solution:

Capacity of first cool drink bottle = 1 l 500 ml

Capacity of second cool drink bottle = 2 l

Capacity of total cool drink bottles = 3 l 500 ml

Question 5.

A liquid blue bottle contains 250 ml. Rajani used 100 ml in it. Find the liquid left in the bottle.

Solution:

Quantity of liquid blue bottle = 250 ml

Quantity of liquid used in bottle = 100ml

Quantity of liquid left in the bottle = 150ml

Question 6.

Sreenu used some kerosene fro 200 l drum. If there is still 18 l 750 ml of the kerosene in the drum, how much kerosene was used by him ?

Solution:

Actual quantity of brasene in the drum = 200 l

After using kerosene left in the drum = 18 l 750 ml

Quantity of kerosene used by Sreenum = 181 l 250 ml

Textbook Page No. 147

Skipping competition:

The following table shows number of skips / jumps made by the students. Observe the table and answer the questions given below.

Question 1.

How much time did Vani take for 50 skips ?

Answer:

Vani took for 50 skips 1 minute.

Question 2.

How much time did Geetha take for 50 skips ?

Answer:

Geetha took for 50 skips 2 minute.

Question 3.

Who took more time for 50 skips ? By how much ?

Answer:

Reeta took 2 minutes more time, than Vani.

Question 4.

Who took least time for 50 skips ? By how much ?

Answer:

Vasantha took least time for 50 skips less than 1 minute.

Textbook Page No. 150

Do this

Observe second’s hand in between the two numbers then we note the time as given below.

Time : hours ___________ ; minutes __________ ; second ___________

Solution:

hours : 7

Minutes : 5 × 10 + 3 = 53

Seconds : 3 × 5 + 4 = 19

Convert the minutes into seconds. One is done for you.

Solution:

Textbook Page No. 151

Do this

Solution:

Textbook Page No. 152

Do this

Convert 1 hour 10 minutes 12 seconds into seconds.

Solution:

1 hour = 1 × 60 = 60 minutes

= 60 × 60 seconds

= 3600 seconds

10 minutes = 10 × 60 seconds

= 600 seconds

1 hour 10 minutes 125 seconds

= 3600 + 600 + 12

= 4,212 seconds

Try this

Find the number of seconds in

a) A day

Solution:

A day = 24 hours

= 24 × 1 hours

= 24 × 60 minutes

= 24 × 60 × 60 seconds

= 86,400 seconds

b) A week

Solution:

A week = = 7days

= 7 × 1 day

= 7 × 24 hours

= 7 × 24 × 1 hour

= 7 × 24 × 60 minutes

= 7 × 24 × 60 × 60 seconds

= 604, 800 seconds

c) A month

Solution:

A month = 30 days

= 30 × 1 day

= 30 × 24 hours

= 30 × 24 × 1 hour

= 30 × 24 × 60 minutes

= 30 × 24 × 60 × 60

= 2592000 seconds

Calender :

Write your date and month of birth in the given table. Observe the day corresponding to your date of birth in present calender and write the day in the table. Also writes dates of birth of your friends. One is done for you.

Solution:

Exercise – 10.5

Question 1.

Observe present year’s calendar in your class and All in the blanks in the following.

Solution:

Question 2.

Arrange the above mentioned festivals in the order as we see in the calendar.

a. __________

b. __________

c. __________

d. __________

e. __________

f. __________

g. __________

h. __________

Solution:

a) Bhogi

b) Ramzan

d) Teacher’s day

e) Gandhi Jayanthi

f) MildadUnnabi

g) Diwali, Children’s day

h) Christmas, Mukkoti Yekadasi

3. From the above mentioned festivals.

a) Which festival comes at the beginning of the year ?

Solution:

Bhoghi comes at the beginning of the year.

b) Which festival comes at the end of the year ?

Solution:

Christmas and Mukkoti Yekadashi comes at the end of the year.

Question 4.

Suman’s age is 9 years and his father’s age is 25 years more than Suman’s age. Then how old is his father ?

Solution:

Suman’s age is = 9 years

Age of his father = Suman’s age + 25 years

= 9 + 25

= 34 years

Question 5.

Anand’s age is 10 years and the age of his brother is less than 5 years of Anand. Find the age of his brother ?

Solution:

Anand’s age is = 10 years

Age of his brother = Anand’s age – 5 years

= 10 – 5

= 5 years

Question 6.

Rajitha is 9 years old. Her sister’s age is twice that of Rajitha’s. Then how old is Rajitha’s sister ?

Solution:

Rajitha’s age is = 9 years

Age of his sister = 2 × Rajitha’s age

= 2 × 9

= 18 years

Question 7.

Write the short form for the given date. One is done for you.

a) 3^{rd} July 1975 = 03-07-1975

b) 16^{th} August 1945 = ____________

c) 22^{nd} March 1980 = ____________

Solution:

b) 16-08-1945

c) 22-03-1980

Coins with Rajani :

Notes with Rajani :

Solution:

Textbook Page No. 158

Do this

Write the other ways for making 900 rupees with different denominations of currency.

a) ₹ 900 = ____________________

Solution:

₹ 100 + ₹ 100 + ₹ 100 + ₹ 100 + ₹ 500

b) ₹ 900 = ____________________

Solution:

₹ 200 + ₹ 200 + ₹ 200 + ₹ 200 + ₹ 100

Try this

Use notes of Indian currency to make ₹ 900

900 = _______ + _________ + ________ + ________ + _________ + _________ + _________ + 5 + 2 + 2 + 1.

Solution:

900 = ₹ 500 + ₹ 200 + ₹ 100 + ₹ 50 + ₹ 20 + ₹ 10 + ₹ 10 + 5 + 2 + 2 + 1

Textbook Page No. 159

Do this

Paste the dummy currency notes in your note book whose total will be 2000 as in the box shown below.

Solution:

Try this

Use the Indian Currency notes and coins and write denominations for ₹ 2000 in the blank.

₹ 2000 = ₹ 500 + _____________

Solution:

₹ 2000 = ₹ 500 + ₹ 500 + ₹ 500 + ₹ 200 + ₹ 200 + ₹ 100

Textbook Page No. 160

Do this

Rajesh wrote denominations for ₹ 2000 in the above form. Now try to fill the below deposit form in another way for depositing ₹ 2000 in the bank.

Solution:

Textbook Page No. 161

Do this

Question 1.

Govind spent 2585 on seeds and 4850 on fertilizers for growing a crop in his field. How much did he spend altogether?

Solution:

Govind spend amount on seed = ₹ 2585

Govind spent amount on fertilizers = ₹ 4850

Total amount spent altogether = ₹ 7435

Question 2.

Appala Naidu had bought a goat for 8950 and sold it for 9850. How much profit did he get?

Solution:

Selling price of goat = ₹ 9850

Cost price of goat = ₹ 8950

∴ Profit gained = ₹ 900

Question 3.

Ratnalu borrowed ₹ 9000 from Gopal. The interest amount for the money became ₹ 1850. But Ratnalu has only ₹ 4965 with her. How much more money is needed to clear the debt ?

Solution:

Ratnalu borrowed amount = ₹ 9000

Interest amount become = ₹ 1850

Total amount = ₹ 10,850

Amount at Ratnalu = ₹ 4,965

Needed money to clear debt = 5885

Exercise – 10.6

1. Fill in the blanks with suitable denominations for ₹ 2000.

a) ₹ 2000 = __________ + ₹ 500 + ₹ 500 + ₹ 200 + ₹ 200 + ₹ 100

Solution:

₹ 2000 = ₹ 500 + ₹ 500 + ₹ 500 + ₹ 200 + ₹ 200 + ₹ 100

b) ₹ 2000 = ₹ __________ + ₹ __________ + ₹ 500 + ₹ 500 + ₹ 500 + ₹ 200

Solution:

₹ 2000 = ₹ 200 + ₹ 100 + ₹ 500 + ₹ 500 + ₹ 500 + ₹ 200

c) ₹ 2000 = ₹ 500 + ₹ 500 + ₹ 500 + ₹ __________ + ₹ __________ + ₹ 100 + ₹ __________ + ₹ 50

Solution:

₹ 2000 = ₹ 500 + ₹ 500 + ₹ 500 + ₹ 200 + ₹ 100 + ₹ 100 + ₹ 50 + ₹ 50

d) ₹ 2000 = ₹ 200 + ₹ 200 + ₹ 500 + ₹ 100 + ₹ 100 + ₹ __________ + ₹ __________ + ₹ __________ + ₹ 100

Solution:

₹ 2000 = ₹ 200 + ₹ 200 + ₹ 500 + ₹ 100 + ₹ 100 + ₹ 500 + ₹ 200 + ₹ 100 + ₹ 100

2. Count the money.

a)

Solution:

₹ 4210

b)

Solution:

₹ 6500

Question 3.

A fish vendor Komali, bought fishes for ₹ 5620 and sold it for ₹ 4985. How much loss did she get?

Solution:

Cost price of fishes = ₹ 5620

Selling price of fishes = ₹ 4985

Loss gained by Komali = ₹ 635

Question 4.

Sailaja has ₹ 6450 and her mother has ₹ 2530. What is total amount they have ? If they spent ₹ 5645 then how much money will be with them ?

Solution:

Amount at Sailaja = ₹ 6450

Amount at Sailaja’s mother = ₹ 2530

Total amount at them = ₹ 8980

Spent amount at them = ₹ 5645

Amount at them = ₹ 3335

Multiple Choice Questions

Question 1.

1 meter = ___________ cm

A) 50

B) 100

C) 25

D) 50

Answer:

B) 100

Question 2.

Half a meter is equal to in cm.

A) 50

B) 100

C) 40

D) 60

Answer:

A) 50

Question 3.

How many 10 cm strips make a meter ?

A) 10

B) 100

C) 40

D) 50

Answer:

A) 10

Question 4.

Convert form of 754 cm into meter

A) 700 m

B) 540 m

C) 7 m 54 cm

D) 75 m/cm

Answer:

C) 7 m 54 cm

Question 5.

Is centimeter is greater than meter?

A) Yes

B) No

C) both A and B

D)None

Answer:

B) No

Question 6.

Difference of 20m 48 cm to 18 m 23 cm is

A) 12.3

B) 2.25

C) 4.69

D) 2.20

Answer:

B) 2.25

Question 7.

A) 500 gm

B) 1000 gm

C) 250 gm

D) 750gm

Answer:

B) 1000 gm

Question 8.

In half kg how many 100 gms are there ?

A) 3

B) 5

C) 100

D) 10

Answer:

B) 5

Question 9.

2 kg = 500 g + 500 g + 500 + ________ g + _______ g + _________ g

A) 200, 200, 50

B) 100, 200, 50

C) 100, 200, 200

D) 200, 200, 200

Answer:

C) 100, 200, 200

Question 10.

Among 61 and 5500 mi which is lesser ?

A) 61

B) 5500 ml

C) both A and B

D) None

Answer:

B) 5500 ml

Question 11.

In 9 liters __________ ml are there

A) 90

B) 100

C) 9999

D) 9000

Answer:

D) 9000

Question 12.

If minutes hand crosses one division the seconds hand crosses __________

A) 30

B) 40

C) 150

D) 60

Answer:

D) 60

Question 13.

How many divisions did seconds hand crossed in the given picture ?

A) 3

B) 5

C) 10

D) 7

Answer:

C) 10

Question 14.

1 hour = ___________ seconds.

A) 60

B) 3600

C) 180

D) 6

Answer:

B) 3600

Question 15.

2 hours = ____________ minutes.

A) 60

B) 120

C) 180

D) 240

Answer:

B) 120

Question 16.

A day has ___________ seconds.

A) 86640

B) 80,000

C) 86,000

D) 86,400

Answer:

D) 86,400

Question 17.

Short form of 20th November 1980

A) 20-Nov-1980

B) 20-11-1980

C) 20-12-1980

D) 20-10-1980

Answer:

B) 20-11-1980

Question 18.

The money used in a particular country is called its

A) Money

B) Rate

C) Currency

D) All

Answer:

C) Currency

Question 19.

Indian currency is

A) Rupee

B) Paise

C) both A and B

D) None

Answer:

C) both A and B

Question 20.

Symbol of rupee is

A) $

B) ₹

C) RM

D) b

Answer:

B) ₹