AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.1

AP State Board Syllabus AP SSC 10th Class Maths Textbook Solutions Chapter 13 Probability Ex 13.1 Textbook Questions and Answers.

AP State Syllabus SSC 10th Class Maths Solutions 13th Lesson Probability Exercise 13.1

10th Class Maths 13th Lesson Probability Ex 13.1 Textbook Questions and Answers

Question 1.
Complete the following statements:
i) Probability of an event E + Probability of the event ‘not E’ =.
ii) The probability of an event that cannot happen is zero.
Such an event is called an impossible event.
iii) The probability of an event that is certain to happen is  such an event is called sure or certain event.
iv) The sum of the probabilities of all the elementary events of an experiment is .
v) The probability of an event is greater than or equal to zero and less than or equal to .

AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.1

Question 2.
Which of the following experiments have equally likely outcomes? Explain.
i) A driver attempts to start a car. The car starts or does not start.
Answer:
Equally likely. Since both have the same probability \(\frac{1}{2}\).

ii) A player attempts to shoot a basket-ball. She/he shoots or misses the shot.
Answer:
Equally likely. Since both have the same probability \(\frac{1}{2}\).

iii) A trial is made to answer a true-false question. The answer is right or wrong.
Equally likely. Since both have the same probability \(\frac{1}{2}\).

iv) A baby is born. It is a boy or a girl.
Equally likely. Since both the events have the same probability \(\frac{1}{2}\).

Question 3.
If P(E) = 0.05, what is the probability of not E?
Answer:
Given: P(E) = 0.05
Hence, P(E) + P(\(\overline{\mathrm{E}}\)) = 1, where P(\(\overline{\mathrm{E}}\)) is the probability of ‘not E’
0.05 + P(\(\overline{\mathrm{E}}\)) = 1
∴ P(\(\overline{\mathrm{E}}\)) = 1 -0.05 = 0.95.

AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.1

Question 4.
A bag contains lemon flavoured candies only. Malini takes out one candy without looking into the bag. What is the probability that she takes out
i) an orange flavoured candy?
ii) a lemon flavoured candy?
Answer:
Bag contains only lemon flavoured candies.
i) Taking an orange flavoured candy is an impossible event and hence the probability is zero.
ii) Also taking a lemon flavoured candy is a sure event and hence its probability is 1.

Question 5.
Rahim removes all the hearts from the cards. What is the probability of
i. Picking out an ace from the remaining pack.
ii. Picking out a diamond.
iii. Picking out a card that is not a heart.
iv. Picking out the Ace of hearts.
Answer:
Total number of cards in the deck = 52.
Total number of hearts in the deck of cards =13.
When Hearts are removed, remaining cards = 52 – 13 = 39.
i)Picking out an Ace:
Number of outcomes favourable to Ace = 3 [∵ ♦ A, ♥ A, ♠ A, ♣ A]
Total number of possible outcomes from the remaining cards = 39
– after removing Hearts.
Probability = P(A)
= \(\frac{\text { No. of favourable outcomes }}{\text { Total no. of outcomes }}\)
= \(\frac{3}{39}\) = \(\frac{1}{13}\)

AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.1

ii) Picking out a diamond:
Number of favourable outcomes to diamonds (♦) = 13
Total number of possible outcomes = 39
∴ p(♦) = \(\frac{13}{39}\) = \(\frac{1}{3}\)

iii) Picking out a card that is ‘not a heart’:
As all hearts are removed, the remain-ing cards are all non-heart cards. So the picked card will be definitely a non-heart card. So this is a sure event.
Hence its probability is one
P(E) = \(\frac{39}{39}\) = 1

iv) Picking out the Ace of Hearts:
a) As all the heart cards are removed the left over cards will have three suits (i) spades, (ii), clubs, (iii) dia¬monds of each 13.
Hence total outcomes = 3 × 13 = 39 But among them there is no Ace of heart. So number of favourable outcomes for picking Ace of heart = zero.
∴ Probability P(E) = \(\frac{0}{39}\) = 0
So it is an impossible event.

b) If picking from the rest of the cards, it is an impossible event and hence probability is zero.
It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992.

AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.1

Question 6.
What is the probability that the 2 students have the same birthday?
Answer:
Let P(E) = The probability that two students not having the same birthday = 0.992
Then P(\(\overline{\mathrm{E}}\)) = The complementary event of E, i.e., two students having the same birthday Also, P(E) + p(\(\overline{\mathrm{E}}\)) = 1
∴ The probability that two students have the same birthday P(\(\overline{\mathrm{E}}\)) = 1 – P(E)
= 1 – 0.992 = 0.008

Question 7.
A die is thrown once. Find the probability of getting
(i) a prime number;
(ii) a number lying between 2 and 6;
(iii) an odd number.
Answer:
i) When a die is thrown for one time, total number of outcomes = 6
No. of outcomes favourable to a prime number (2, 3, 5) = 3
∴ Probability of getting a prime = \(\frac{\text { No. of favourable outcomes }}{\text { Total no. of outcomes }}\)
= \(\frac{3}{6}\) = \(\frac{1}{2}\)

ii) No. of outcomes favourable to a number lying between 2 and 6 (3, 4, 5) = 3
∴ Probability of getting a number between 2 and 6
= \(\frac{\text { No. of favourable outcomes }}{\text { Total no. of outcomes }}\)
= \(\frac{3}{6}\) = \(\frac{1}{2}\)

iii) Number of outcomes favourable to an odd number (1, 3, 5) = 3
∴ Probability of getting an odd number P(odd)
= \(\frac{\text { No. of favourable outcomes }}{\text { Total no. of outcomes }}\)
= \(\frac{3}{6}\) = \(\frac{1}{2}\)

AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.1

Question 8.
What is the probability of drawing out a red king from a deck of cards?
Answer: Number of favourable outcomes to red king (♥ K, ♦ K) = 2.
Number of total outcomes = 52
(∵ Number of cards in a deck of cards = 52)
∴ Probability of getting a red king P (Red king)
= \(\frac{\text { No. of favourable outcomes }}{\text { Total no. of outcomes }}\)
= \(\frac{2}{52}\) = \(\frac{1}{26}\)

Question 9.
Make 5 more problems getting probability using dice, cards or birthdays and discuss with friends and teacher about their solutions.
Answer:
Class-room activity.

AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.4

AP State Board Syllabus AP SSC 10th Class Maths Textbook Solutions Chapter 14 Statistics Ex 14.4 Textbook Questions and Answers.

AP State Syllabus SSC 10th Class Maths Solutions 14th Lesson Statistics Exercise 14.4

10th Class Maths 14th Lesson Statistics Ex 14.4 Textbook Questions and Answers

Question 1.
The following distribution gives the daily income of 50 workers of a factory.
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.4 1
Convert the distribution above to a less than type cumulative frequency distribution, and draw its ogive.
Answer:
Since the curve is a less than type graph the data changes to
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.4 2
X – axis – upper limits 1 cm = 50 units.
Y – axis – less than c.f. 1 cm = 5 units.
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.4 3

AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.4

Question 2.
During the medical check-up of 35 students of a class, their weights were recorded as follows:
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.4 4
Draw a less than type ogive for the given data. Hence obtain the median weight from the graph and verify the result by using the formula.
Answer:
Given: Upper limits of the classes and less than cumulative frequencies. Therefore required points are (38, 0), (40, 3), (42, 5), (44, 9), (46, 14), (48, 28), (50, 32) and (52, 35)
X – axis – upper limits 1 cm = 2 units.
Y – axis – less than c.f. 1 cm = 4 units.
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.4 5

AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.4

Number of observations = 35
∴ \(\frac{N}{2}\) = \(\frac{35}{2}\) = 17.5
Locate the point on the ogive whose ordinate is 17.5.
The x – coordinate of this point is the required median.
From the graph, median = 46.5.
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.4 6
Number of observations = n = 35
∴ \(\frac{N}{2}\) = \(\frac{35}{2}\) = 17.5
17.5 belongs to the class 46 – 48
∴ Median class = 46-48
l – lower boundary of class = 46
f – frequency of the median class =14
c.f = 14
Class size = 2
Median = \(l+\frac{\left[\frac{\mathrm{n}}{2}-\mathrm{cf}\right]}{\mathrm{f}} \times \mathrm{h}\)
= 46 + \(\frac{17.5-14}{14}\) × 2
= 46 + \(\frac{3.5}{14}\) × 2
= 46 + \(\frac{7}{14}\)
= 46 + \(\frac{1}{2}\)
= 46.5
Here median is 46.5 by either by ways.

AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.4

Question 3.
The following table gives production yield per hectare of wheat of 100 farms of a village.
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.4 7
Change the distribution to a more than type distribution, and draw its ogive.
Answer:
The given data is to be changed to more than frequency distribution type.
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.4 8
A graph is plotted by taking the lower limits on the X – axis and respective of Y – axis.
Scale:
X – axis: 1 cm = 5 units
Y – axis: 1 cm = 5 units
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.4 9

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

AP State Board Syllabus AP SSC 10th Class English Textbook Solutions Chapter 2B The Dear Departed Part 2 Textbook Questions and Answers.

AP State Syllabus SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

10th Class English Chapter 2B The Dear Departed Part 2 Textbook Questions and Answers

Comprehension

I. Answer the following questions.

Question 1.
Justify the view that the husbands of Mrs. Slater and Mrs. Jordan are men with no individuality.
Answer:
Henry and Ben are men with no individuality. They simply follow their wives’ instructions. When Mrs. Slater asks Henry to wear the old man’s slippers, he wears them even they are smaller in size. When she asks him to shift the bureau from her father’s room, he obeys her and does as she likes. He doesn’t say even a word against her will. In the same way, Ben too is a man with no individuality. Both Henry and Ben try to stop the quarrel between their wives but fail. Though they have concern for their father-in-law, they can’t express it.

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

Question 2.
Discuss the irony in the title ‘The Dear Departed’.
Answer:
Irony is the use of words to express something other than what is said or meant and especially the opposite of the literal meaning. The title “The Dear Departed” conveys just the opposite as the main character of the play (Abel Merry weather) does not seem to be “dear” to his own daughters. The old man is not dear to anyone. They only want his property.

Question 3.
List the arguments the two sisters gave to keep their father in their care.
Answer:
Mrs. Slater tells her father that it is quite time he comes to live with them again and they will make him very comfortable if he comes. But Mrs. Slater argues that he has not been with them as long as he was with the Jordans. Mrs. Jordan replies that she does not think their father will fancy living on with the Slaters after their stealing his things. They even say sorry for what they have done. Thus, both the sisters argue to keep their father in their care.

Question 4.
How does the spat between the old man’s daughters lead to father discovering the truth?
Answer:
The spat happens between the two sisters when their father Abel asks Mrs. Slater why his bureau and clock are brought downstairs. Mrs. Jordan understands that her sister tries to steal those things before their arrival. This leads to a quarrel between the two sisters. Mrs. Jordan tells her father that Mr. and Mrs. Slater have shifted the bureau and the clock from his room to the sitting room because they think he is dead. They have shifted the things so as Mrs. Jordan can’t lay a claim on them. After discovering the truth, Abel becomes angry because he feels that his daughters don’t even wait till his funeral and have tried to divide things between them.

Question 5.
List the comic elements in the play ‘The Dear Departed’.
Answer:
There are certain elements that make the play a comedy. The title itself is a comic one. A single person doesn’t make a comedy. It requires several who are in action and counter action. The main characters of the play, Abel Merry weather, Mrs. Slater, Mrs. Jordan, Henry and Ben all cause the comedy. The main comic thing is that both the sisters think that their father is dead. The other comic scenes in the play are :

  1. Following his wife’s instructions, Henry wears the old man’s new slippers.
  2. The Slaters hurry to steal the old man’s bureau and clock, thinking that the Jordans will arrive.
  3. The Slaters and the Jordans are shocked to see Abel coming into the room.
  4. Ben skips back and retreats with Mrs. Jordan to a safe distance when Abel thrusts his hand at Ben.
  5. Abel announces that he will change his will and marry John Shorrocks.
  6. Both the sisters argue that Abel should stay with them. (They want to own his property).

A termination must be made which springs necessarily from the preceding elements and this gives the comic solution. The arrival of Abel into the sitting room and his announcement of changing his will and marrying^ woman etc. produce such a comedy.

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

Question 6.
In what way is the play ‘The Dear Departed’ a commentary on the hollowness of human relationships?
Answer:
Stanley Houghton, in his one act play, tries to bring out the qualities of the two daughters, Mrs. Slater and Mrs. Jordan towards their father. The author tries to show how the sisters are interested in the property of their father rather than their care and affection towards him. When the two sisters think that their father is dead they are complaining of what a burden he is to them. The moment Abel announces about his new will in which he will leave everything to the person he is living with when he dies, they both fight for him to live with them. Thus, this play shows us the hollowness of human relationships. This is a social play on the condition of the old people who are being neglected and abandoned by their own children. Here we see the degradation of moral values in respect and care within the members of the family itself.

Question 7.
What are the three things that the father plans to do on Monday next? What effect does it have on his daughters?
Answer:
The three things that the father plans to do on Monday next are:

  1. At first, he wants to go to the lawyer and alter his will.
  2. Then he wants to go to the insurance office and pay his premium.
  3. Finally he wants to go to St. Philip’s Church and get married.

If Mr. Abel does all these three things, the daughters will lose the chance of getting their share in their father’s assets.

II. Arrange the following sentences in sequence so that a continuous narrative of the story of ‘The Dear Departed’ could be made.
1. One day Mrs. Slater felt that Abel Merryweather had died.
2. Suddenly Victoria came into the room telling that grandfather was moving.
3. The Slaters and the Jordans wanted to ascertain if Abel Merryweather had paid his insurance premium.
4. Abel Merryweather found fault with the two daughters and wanted to change his will.
5. Before the arrival of the Jordans, the Slaters had pinched Abel’s bureau and clock.
6. Victoria was sent to Abel Merryweather’s room to bring the key bunch of the bureau.
7. Abel Merryweather informed that he was going to marry Mrs. John Shorrocks.
8. The Slaters sent a telegram to the Jordans about the death of Abel Merryweather.
Answer:
The sequential order is:
1. One day Mrs. Slater felt that Abel Merry weather had died.
8. The Slaters sent a telegram to the Jordans about the death of Abel Merry weather.
5. Before the arrival of the Jordans, the Slaters had pinched Abel’s bureau and clock.
3. The Slaters and the Jordans wanted to ascertain if Abel Merry weather had paid his insurance premium.
6. Victoria was sent to Abel Merry weather’s room to bring the key bunch of the bureau.
2. Suddenly Victoria came into the room telling that grandfather was moving.
4. Abel Merry weather found fault with the two daughters and wanted to change his will.
7. Abel Merry weather informed that he was going to marry Mrs. John Shorrocks.

The narrative: One day Mrs. Slater felt that Abel Merry weather had died. The Slaters sent a telegram to the Jordans about the death of Abel Merry weather. The Slaters wanted to steal the old man’s things before the arrival of the Jordans. So, they had pinched Abel’s bureau and wall clock before their arrival. The Jordans arrived soon and they all thought about the announcement of the old man’s death in the papers. Then the Slaters and the Jordans wanted to ascertain if Abel Merry weather had paid his insurance premium. Victoria was sent to Abel Merry weathers room to bring the key bunch of the bureau. Victoria went into’the old man’s room and saw him moving and getting up. Being frightened, Victoria came into the room telling that grandfather was moving. Abel Merry weather came into the sitting room and both the sisters and their husbands were shocked. He found fault with the two daughters and wanted to change his will. He informed them that he was going to change his will leaving all bits of his things to whoever he was living with when he would die. He also declared that he was going to marry Mrs. John Shorrocks.

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

III. Here is a list of traits of a personality. Tick (✓) the traits that describe Mrs. Slater’s character.
a) Greedy
b) Overpowering
c) Honest
d) Sensitive
e) Dominating
f) Blunt
g) Straight talking
h) Humble
i) Impolite
j) Insensitive

Answer:

a) Greedy (✓)
b) Overpowering (✓)
c) Honest
d) Sensitive
e) Dominating (✓)
f) Blunt (✓)
g) Straight talking (✓)
h) Humble
i) Impolite (✓)
j) Insensitive (✓)

The traits that describe Mrs. Slater’s character are:
Greedy: Mrs. Slater’s pinching her father’s bureau and clock before the arrival of her sister Elizabeth Jordan and her husband; her asking Henry to wear her father’s slippers.
Overpowering: Mrs. Slater’s asking Victoria to close the door if her aunt Elizabeth and uncle Ben come.
Dominating: Her dominating attitude towards her husband Henry.
Blunt: Her saying to her sister, “Be quiet, Elizabeth”; her asking Victoria to change her dress.
Straight talking: When Victoria says that perhaps grandpa didn’t go to pay his insurance premium, Mrs. Slater snubs her saying “He went out”.
Impolite:
i) Mrs. Slater’s talking to Henry, “Henry, why shouldn’t we bring that bureau down here now ? We can do it before they come,
ii) When Henry says to her, “I wouldn’t care to,” she says to him, “Don’t look so daft. Why not ?”
Insensitive:
i) When Victoria says to her, “That’s grandpa’s clock,” she replies, “Be quiet! It’s ours now.”
ii) When Mrs. Jordan says to her, “I’ll tell you what’s been going on in this house, father. Nothing short of robbery,” she says, “Be quiet, Elizabeth”.

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

IV. The following are the features of a one act play. Which of the following characteristics does the play ‘The Dear Departed’ have? Justify.
a) Minimal characters
b) Single setting or unity of place
c) One act with one or more scenes
d) Focus on one incident
e) Limited time
f) Twist ending
Answer:
“The Dear Departed” is a one act play; so it naturally has all the above mentioned characteristics.

a) Minimal characters: The total number of characters we see in this play is only six. They are Mrs. Amelia Slater, Mrs. Elizabeth Jordan, Henry Slater, Ben Jordan, Victoria Slater and Abel Merry weather. Hence, the play has the feature of “Minimal characters.”

b) Single setting or unity of place: All the story takes place in the house of Mrs. Slater particularly in the sitting room and Abel’s bedroom. Hence, the play has the characteristic of “Single setting.”

c) One act with one or more scenes: All the story happens in one act and only one scene. Hence, it has this feature.

d) Focus on one incident: All the story moves around the death of Abel Merry weather. Hence, the play’s focus is on one incident only.

e) Limited time: The story lasts for only one or two hours. Hence, it has the feature of “limited time.”

f) Twist ending: In the end of the play, Abel announces that he will change his will and marry Mrs. John Shorrocks. This announcement was a real shock for the two sisters and their husbands. It is really an unexpected thing for them. Hence, it has the feature of “Twist ending”. Audience too can t guess this twist.

Vocabulary

I. Irregular Plurals

Now write the plural forms of the following nouns given in the table and say whether each of them is ‘Latin’ or ‘Greek’ word.

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2 1
Answer:
AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2 2
* Phenomenon – It is borrowed from Greek and ended in a’ in the plural in Latin.

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

II. Exclamations/Interjections

Now observe the sentences and decide which emotion is ex¬pressed in each context. Put a tick (✓) in the appropriate box. The first one has been done for you.

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2 3
Answer:
AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2 4

III. Compound Adjectives

Make compound adjectives choosing one word from list ‘A’ and another word from list ‘B’ and fill in the blanks with them.
AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2 5
Answer:
AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2 6

1. Sindhu is very clear-sighted about her choice.
2. The headmaster suggested a ______________________ trip to Hyderabad.
3. The _______________________________ girl who is under the tree is my sister.
4. All the people were shocked at the sight of this _______________ murder.
5. After the terrible tempest, the _____________________ sailing boat was unusable.
6. Prasad booked a room in a ____________________ hotel for Srikanth.
7. Every week, ____________________ eggs are used by my mother to make some wonderful cakes.
8. This ______________________ coat is too large for me.
9. It was a _______________________ war between the English and the French.
10. I like to correspond with this ____________________ teacher. She speaks about interesting topics.
Answer:
2. four-day
3. curly-headed
4. cold-blooded
5. half-sunk
6. five-star
7. new-laid
8. peacock-blue
9. long-lasting
10. well-read

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

IV. Words Often Confused

A. Write words that are likely to be confused with the words given. Find their mean¬ings and use them in sentences of your own to show the difference in meaning.

1. alter-
2. principal-
3. gait –
4. canvas –
5. check –
6. ceiling –
7. complement –
8. stationary –
9. all read –
10. advice –

Answer:

1. alter (v) – altar (n)
alter (v) : to change, or to make someone or something change e.g.: No one can alter the rules and regulations of this society, altar (n) : a holy table or surface used in religious ceremonies e.g.: The priest reached the altar to perform a religious ceremony.

2. principal (n) – principle (n)
principal (n) : someone who is incharge of a university/college e.g.: Mr. Chaitanya is the principal of St. John’s College, principle (n) : a moral rule or belief e.g.: Vinoba is a man of high principles.

3. gait (n) – gate (n)
gait (n) : the way someone walks e.g.: She has an awkward gait.
gate (n) : the part of a fence or outside wall that you can open and close so that you can enter or leave a place
e.g.: They locked the front gate and went out.

4. canvas (n) – canvass (v)
canvas (n) : strong cloth used to make bags, tents, shoes etc. e.g.: I bought a bag made of canvas.
canvass (v) : to try to persuade people to support a political party, politician etc. e.g.: Mr. Varun is very busy canvassing for votes.

5. check (v) – cheque (n)
check (v) : to do something in order to find out whether something really is correct, true or in good condition
e.g.: The guards had checked him thoroughly before he came out.
cheque (n) : a printed piece of paper that you write an amount of money on, sign and
use instead of money to pay for things
e.g.: He issued me a cheque for Rs. 25,000.

6. ceiling (n) – sealing (n)
ceiling (n) : the inner surface of the top part of a room e.g.: All the rooms in our house are built with high ceilings, sealing (n) : the activity of hunting or catching seals e.g.: Sealing is his hobby.

7. complement (n) – compliment (v)
complement (n) : someone or something that emphasizes the good qualities of an¬other person or thing
e.g.: The cashew nuts were an excellent complement for the sweets, compliment (v) : to say something nice to someone in order to praise them e.g.: Our headmaster complimented me when I saved the little girl.

8. stationary (adj) – stationery (n)
stationary (adj) : standing still instead of moving
e.g.: The teacher ordered his students to remain stationary.
stationery (n) : materials that we use for writing, such as paper, pens, pencils etc.
e.g.: I went into the shop to buy stationery.

9. all ready (phrase) – already (adv)
all ready (phrase) : completely ready e.g.: We are all ready for the test.
already (adv) : used to say something has happened before the expected time e.g.: Is it 6 o’ clock already?

10. advice (n) – advise (v)
advice (n) : an opinion about what could or should be done about a situation or problem
e.g.: He gave me a good piece of advice.
advise (v) : to give advice
e.g.: My aunt advised me to join navy.

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

B. Read the following paragraph. It contains errors in words often confused. Correct them and rewrite the paragraph replacing them with the right words.

It was one of those October daze when it was a pleasure to be alive. The sky was blew and the heir was cold and sharp with a cent of wet earth as the mourning sun warmed the chilled countryside. And then I caught site of a lonely be struggling to find the pollen of a final flour. Wear had he bean, this sad worker , doomed so soon to dye? I marvelled at his energy as he climbed along so many bear stalks. Finding nothing, he flue on and disappeared from cite. I continued my walk to a country in where, sitting outside, I contentedly sipped my beer, musing all the wile on the mixed fortunes of life.
Answer:
It was one of those October days when it was a pleasure to be alive. The sky was blue and the air was cold and sharp with a scent of wet earth as the morning sun warmed the chilled countryside. And then I caught the sight of a lonely bee struggling to find the pollen of a final flower. Where had he been, this sad worker, doomed so soon to die? I marvelled at his energy as he climbed along so many bare stalks. Finding nothing, he flew on and disappeared from sight. I continued my walk to a country inn where, sitting outside, I contentedly sipped my beer, musing all the while on the mixed fortunes of life.

V. Idiomatic Expressions

Here is a list of idioms and idiomatic expressions used in the play, ‘The Dear Departed’. Guess their meanings. Then look them up in a dictionary, note down their meanings and use them in your sentences.

1. get one’s own way
2. for ages
3. set foot
4. drive a hard bargain
5. get rid of
6. give way
7. at length
8. on purpose
9. took by surprise
10. at a loss
Answer:
1. get one’s own way: persuade other people to allow you to do what you want e.g.: Parents want to get their children into their own way.

2. for ages: for a long time
e.g.: I haven’t seen you for ages.

3. set foot: to enter some place
e.g.: I would not like to set foot in your house.

4. drive a hard bargain : work hard to negotiate agreements in one’s own favour e.g.: Although he has driven a hard bargain, he couldn’t get what he wants.

5. get rid of: to throw away or destroy something you do not want any more e.g.: Finally, Sekhar got rid of his old shoes.

6. give way: to stop agreeing or fighting against someone or something ; to abandon oneself.
e.g.: Don’t give way to your fears.

7. at length: in detail
e.g.: At length, they have discussed the matter.

8. on purpose: intentionally
e.g.: He entered the sitting room on purpose.

9. took by surprise: to surprise someone (took someone by surprise)- e.g.: I took my friend by surprise presenting a gold watch to him.

10. at a loss: unable to speak, unable to know how to act or what to do. e.g.: When Rahul faced the interviewers, he felt totally at a loss.

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

Grammar

I. Read the following sentences from the play and notice the underlined words.

Let us read the following sentences.

  1. She’ll come fast enough after her share of what our father has left.
  2. Mrs. Slater doesn’t have enough money to buy the bureau.

In both the sentences ‘enough’ is underlined. ‘Enough’ means ‘sufficient’.
In a sentence, ‘enough’ is used after adjectives, adverbs or verbs as an adverb, and before nouns as a determiner.

A. Now decide whether ‘enough’ in the following sentences is used as an ‘adjective’ or an ‘adverb’.
1. This house is not big enough for me.
2. We didn’t leave early enough.
3. I was not trained enough for the game.
4. Is there enough room for me?
5. I do not have enough clothes for my journey.
Answer:
1) This house is not big enough for me.
‘enough’ is used as an adverb.

2) We didn’t leave early enough.
‘enough’ is used as an adverb.

3) I was not trained enough for the game.
‘enough’ is used as an adverb.

4) Is there enough room for me?
’enough’ is used as an adjective.

5) I do not have enough clothes for my journey.
’enough’ is used as an adjective.

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

B. Complete the following sentences using ‘enough’ / ‘not enough’ and one of the words given in the list below.

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2 7

1. Harish wants to be a great wrestler but he is ____________________.
2. I want to sit and watch TV but I just don’t have ____________________.
3. He tried to win the race but he came third as he was not ____________________.
4. This bath is freezing. The water is ____________________.
5. We had to sleep on the floor as there were ____________________.
6. There is ____________________ to make a cup of tea! What is wrong with the pipes?
7. If Sujatha does not have ____________________ , I can lend her.
8. Vasavi is not ____________________ to become a member of this club. She must be at least 18 years of age to join.
9. Is this coffee ____________________ for you? Would you like some more sugar?
10. Do you think he has studied ____________________ to pass the entrance exam?
Answer:
1. not strong enough
2. enough time
3. fast enough
4. not warm enough
5. not enough beds
6. not enough water
7. enough money
8. old enough
9. sweet enough
10. hard enough

II. We generally use articles (a, an and the) before common nouns. But in some cases articles are not used before them. Read the following sentences from the play ‘The . Dear Departed’ and notice the underlined common nouns.

1. He went out soon after breakfast to pay his insurance.
2. And when we’d finished dinner I thought I’d take up a bit of something on a tray.
In the above sentences the underlined common nouns ‘breakfast and dinner’ refer to the names of meals and food. In primary and general sense we don’t use articles before the words that refer to the names of meals and food i.e. breakfast, dinner, lunch, supper, pizza, fish fry and omelette.

Write the following paragraphs, inserting a, an, and the where needed.

A. Horse knows when he is going to race. How does he know? His breakfast is scanty. (He is angry about that.) He does not have saddle on his back. He is being led, not ridden, to grandstand. He is led under grandstand into unusual, special stall. Horse is nervous. Sometimes he does not know what to do when starting gate flies open and track is before him. If he does not begin to run instantly, other horses are already ahead of him. During race, when he sees another horse just ahead of him, he will try to pass him. Sometimes jockey holds him back to save his energy for last stretch. Eventu¬ally horse gets to run as fast as he can. Exercise boy, watching owner’s favourite jockey riding horse he has exercised day after day, says nothing. Secretly, he is planning for day when he.will be jockey himself, and his horse will be first to cross finish line.

B. I have horse of my own. I call her Pretty Girl. She is intelligent animal, but she is not thoroughbred horse. I could never enter her in race, even if I wanted to. But I do not want to. She is companion, for my own pleasure. I took her swimming day or two ago.

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

Answer:
A. A/The horse knows when he is going to race. How does he know? His breakfast was scanty. (He is angry about that.) He does not have a saddle on his back. He is being led, not ridden, to the grandstand. He is led under the grandstand into an unusual, special stall. The horse is nervous. Sometimes he does not know what to do when the starting gate flies open and the track is before him. If he does not begin to run instantly, the other horses are already ahead of him. During the race, when he sees another horse just ahead of him, he will try to pass him. Sometimes the jockey holds him back to save his energy for the last stretch. Eventually the horse gets to run as fast as he can. The exercise boy, watching the owner’s favourite jockey riding the horse he has exercised day after day, says nothing. Secretly, he is planning for the day when he will be a jockey himself, and his horse will be the first to cross the finish line.

B) I have a horse of my own. I call her Pretty Girl. She is an intelligent animal, but she is not a thoroughbred horse. I could never enter her in a race, even if I wanted to. But I do not want to. She is a companion, for my own pleasure. I took her swimming a day or two ago.

III. Compound Prepositional Phrases

Read the following sentences from the play ‘The Dear Departed’ and notice the underlined words.
1. Victoria dressed according to her mother’s instructions.
2. You both say that because of what 1 have told you about leaving my money.
3. It was here instead of in his room.
The underlined phrases are compound prepositional phrases. The following are some more important compound prepositional phrases. Their meanings are given in brackets.
along with (together with)
on account of (because of)
by means of (through the agency of)
apart from (separate from)
ahead of (earlier than somebody/something)
in front of (located before)
in place of (as a substitute for)
in spite of (disregarding the difficulty)
in case of (in the event of)
by way of (via)
due to (on account of)
for the sake of (for the good of)
in addition to (added to)
in accordance with (in agreement with)

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

A. Use the above compound prepositional phrases in sentences of your own.

Answer:
1. along with:
a) Ramu went along with Somu.
b) I put scale along with books in my bag.
c) Mr. Nagesh bought a TV along with a computer.

2. on account of:
a) She visited the doctor on account of her illness.
b) They cancelled their programme on account of rain.
c) On account of Prabhu’s late-coming, he was beaten severely.

3. by means of:
a) He will succeed by means of sheer determination.
b) 1 was able to buy a flat by means of a bank loan.
c) The blocks are raised by means of pulleys.

4. apart from:
a) Apart from minor injuries, he was safe after an accident.
b) We have a Maruthi car apart from our Ford car.
c) We don’t see anyone in the theatre apart from two women.

5. ahead of:
a) Mr. Rao arrived there ahead of his boss.
b) The results show that Aam Admi’ party is ahead of other parties.
c) He had got ahead of me.

6. in front of:
a) There is a pole in front of our house.
b) The fountain is in front of the building.
c) We sit in front of the TV and watch programmes.

7. in place of:
a) Mr. John came to teach in place of Mr. Robert, who was transferred.
b) She bought a red car in place of the blue car, her old one.
c) Mr. Vasan was appointed as chairman in place of Mrs. Sharma, the former chairman.

8. in spite of:
a) In spite of heavy rain, the football match was continued.
b) In spite of the pain in his leg, he played and won the match.
c) In spite of the fact that he had worked hard, he didn’t get through his exam.

9. in case of:
a) In case of heavy rains, you should postpone your trip.
b) Break the glass in case of fire.
c) In case of floods, take the help from helpline.

10. by way of:
a) We go to school by wav of market.
b) My father came home by way of Rampura.
c) They reached the place by wav of the canal.

11. due to:
a) Due to illness, she didn’t go to school.
b) The game was cancelled due to heavy rain.
c) There was a heavy loss due to improper management.

12. for the sake of:
a) The government implemented a new programme for the sake of women.
b) She had done it for the sake of you.
c) The king acquitted the criminal for the sake of justice.

13. in addition to:
a) Mr. Suraj learnt Karate in addition to Kungfu.
b) She used to teach English in addition to Social Studies.
c) You have to add sugar to the dish in addition to ghee.

14. in accordance with:
a) The boss did this in accordance with his request.
b) I designed this plan in accordance with our discussion.
c) They have tried to root out corruption in accordance with rules that have been framed recently.

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

B. Fill in each blank with the correct compound prepositional phrase from the options given under each sentence.

1. I finished my project work several days ________________ the deadline.
a) instead of
b) ahead of
c) in spite of
Answer:
b) ahead of

2. Sravani goes to school ______________________ Yamuna daily.
a) according to
b) in spite of
c) along with
Answer:
c) along with

3. My house stands _______________ all the other houses in the street as it is big in size.
a) apart from
b) in accordance with
c) in addition to
Answer:
a) apart from

4. Madhu got a good job ____________________ his own abilities and skills.
a) in addition to
b) instead of
c) by means of
Answer:
c) by means of

5. She was unable to attend the party ______________ her marriage engagement.
a) in spite of
b) in addition to
c) due to
Answer:
c) due to

6. ______________ fire, ring the alarm bell.
a) In spite of
b) In case of
c) In addition to
Answer:
b) In case of

7. Sriram continued his batting carefully ________________ his team though he was hungry.
a) for the sake of
b) in addition to
c) in front of
Answer:
a) for the sake of

8. You should complete your B.Ed. _____________________ your B.Sc to get a teacher job.
a) in addition to
b) according to
c) in spite of
Answer:
a) in addition to

9. The physical director of our school selected me ____________________ my friend, Ganesh for tomorrow’s match.
a) in spite of
b) in place of
c) ahead of
Answer:
b) in place of

10. ________________ his poverty, he completed his Ph.D. in English.
a) In place of
b) For the sake of
c) In spite of
Answer:
c) In spite of

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

IV. Language Function (It’s time + Simple Past Verb …)

Read the following contexts and express them using expressions it’s quite time’, it’s high time’, it’s time’ or it’s about time’.

1. Bhavani usually wakes up at 6 a.m. daily. It is 6.15 a.m. now. Bhavani has not woken up yet. You feel it is already late. Express your idea using it’s high time’.
Answer:
It’s high time Bhavani woke up.

2. You and your friend have spent more time than you spend daily in the playground. You feel it is late and better to go home. What would you say to your friend? Use the expression ‘It’s time’.
Answer:
It’s time we went home as it is already late.

3. You to your friend: ‘You have not thought seriously about what you want to do in your life.’ How would you express this idea using ‘It’s high time’.
Answer:
It’s high time you thought about your life seriously.

4. Your friend promised you to make a phone call at 7 a.m. But you haven’t received any phone call from him yet. Now it is 7.30 a.m. How would you express this idea using ‘It’s time’?
Answer:
It’s time my friend made me a call.

5. Your friend has been working on a project for 5 months. But he has not completed it yet. You feel that your friend should take your help to complete the project fast. Give him/her advice using ‘It’s time.’
Answer:
It’s time you took my help in order to complete the project fast.

V. The following passage has ten errors of grammar. Identify and rewrite them with necessary corrections.
Varanasi is locate on the north eastern part of India. Hindu pilgrims go to there to purify their souls. To the Hindus Varanasi is a holiest pilgrimage center to all.
Thousands of pilgrims visit this wholly city every year.
As early as four o’clock at the morning the pilgrims are seen make their way to the famous bathing steps knowed as Gatz. From there they board row boats to the holy river ganges to take bath. In doing this the pilgrims believe that their sins would be wash away.
Answer:
Varanasi is located in the north eastern part of India. The Hindu pilgrims go there to purify their souls. To the Hindus Varanasi is the holiest pilgrimage centre of all.
Thousands of pilgrims visit this holy city every year.
As early as four o’clock in the morning the pilgrims are seen making their way to the famous bathing steps known as Ghats. From there they board row boats to the holy river Ganges to take a bath. By doing this the pilgrims believe that their sins would be washed away.

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

Read the following sentences. Complete the conversations with the appropriate forms of the verbs. Then say why you chose simple past/present perfect forms.

1. “Is your brother in?”
“No, he isn’t. He __________________(go) to Chennai.”
“When _________ he ________________________(go) to Chennai?”
“Yesterday.”
Answer:
“Is your brother in ?”
“No, he isn’t. He has gone to Chennai”.
“When did he go to Chennai ?”
“Yesterday”.

2. “I ________ (lose) my pencil. __________you ________________________(see) it anywhere?”
“No, I________ . When ___________ you last _________(use) the pencil?”
“I ________________________(use) it when I was in the class.”
“Perhaps you ________________________(leave) it in the class.”
Answer:
“I lost my pencil. Have you seen it anywhere ?”
“No, I haven’t. When did you last use the pencil?”
“I used it when I was in the class.”
“Perhaps you have left (must have left) it in the class.”

3. A: _____________ Madhu ________________________( not arrive) yet ?
B: No, he ________________________ .
C: But he ________________already ________________________(arrive).
B: _______________ you ________________________(talk) to him?
C: No, I ____________ . I merely _______________(see) him.
B: That cannot be Madhu. He may have been somebody else.
Answer:
A : Hasn’t Madhu arrived yet?
B : No. He hasn’t.
C : But he has already arrived.
B : Have you talked to him ?
C : No, I haven’t. I merely saw him.
B : That cannot be Madhu. He may be somebody else.

4. A: ________________ you _______________(call) me, mother?
B: Yes, I_______________. ________ you _______________(see) my diary today?
I _______________(put) it on the table last night. I _______________(look) all over the house for it. But I _______________( not, find) it anywhere.
A: I _______________(see) it on the table this morning, if I remember right. Maybe father _______________(take) it with him by mistake.
Answer:
A: Have you called me. mother ?
B : Yes, I have. Have you seen my diary today ?
I put it on the table last night. I have looked all over the house for it. But I have not found it anywhere.
A : I have seen it on the table this morning, if I remember right. May be father has taken it with him by mistake.

5. “Do you know Mrs.Geetha ?”
“Yes, I do. I _______________(know) her for nearly four years. It ______________(be) at a high school that I first _______________(see) her in 2009. I ___________(work) with her for several years. Recently we _______________(meet) at the wedding of a mutual friend of us.”
Answer:
“Do you know Mrs. Geetha ?
“Yes. I do. I have known her for nearly four years. It was at a high school that I first saw her in 2009. I have worked with her for several years. Recently we have met at the wedding of a mutual friend of us.”

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

Writing

I. Imagine that you are the grandfather in the play. Write a letter to your Mend, Mr. Tattersall inviting him to your marriage at ‘Ring-o-Bells with Mrs. John Shorrocks. Don’t forget to say why you are going to get married at this age.

You can include the following :
a) Time of wedding
b) Place of wedding
c) Details of the bride
d) Behaviour of the daughters
e) Reason for-marrying at this age
f) Cordial invitation.
Answer:

22-222-A45,
Trafalgar Square,
Manchester City.
28th March, 20xx.

My dear Tattersall,

How are you? I am keeping quite well and hope to hear the same from you. It is a long time since I received a letter from you. What are the things with you ? Here is a surprising news for you. I am glad to write to you that I am going to get married to Mrs. John Shorrocks at twelve o’ clock at St. Philip’s Church on Monday, 7th April, 20xx. Mrs. John Shorrocks is a good woman and is the owner of ‘Ring-o-Bells’. We know each other very well. She is a famous business person in the city. Hence, I cordially invite you to attend our marriage ceremony without fail.

Now, I think that you are very much surprised to hear the news of my marriage at this age. I had to take this decision because of the the evil intentions of both my daughters Amelia and Elizabeth. You know that I have been with Amelia’s family for the last few months. A few days ago, Amelia thought me ‘dead’ and her foolish husband sent this message to my second daughter Elizabeth. Before Elizabeth and her husband’s arrival, Amelia shifted my bureau to the sitting room. She also tried to steal my clock and my slippers for her husband. After the arrival of the Jordans, both my daughters concentrated on grabbing my things. No one bothered about me. They don’t deserve to be called ‘daughters’ at all. When I understood their nature, I wanted to teach them a lesson. I announced that I would change my will the next Monday, pay my insurance premium and get married. I think that this decision is a slap on the faces of my greedy and deceitful daughters.

I hope that you will understand my feelings. I shall be very glad to see you at the ceremony on Monday. I am awaiting your arrival. Convey my best wishes to your wife.

Your loving friend,
Abel Merryweather

Address on the envelope :
To
Mr. K. Tattersall,
5-262-6/A, Joseph Towers,
Dovinci Street, Liverpool,
England.

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

II. Convert the play, ‘The Dear Departed’ into a story.

To adapt the story to your culture, you may make changes in the following:
a) The names of the characters
b) Description of costumes
c) Things stolen by the daughter
d) The names of the villages/towns the daughters lived in
Answer:
Mr. Rao is a seventy-two-year old man. He is living with his daughter Mrs. Sarojini and her husband Prakash. Their daughter is Sushma, who loves her grandpa very much. Mr. Rao’s another daughter is Mrs. Aruna and her husband Rajesh.

One day Mrs. Sarojini thinks that her father is dead. She tells her daughter to change her dress before her aunt Aruna and her husband come. Mrs. Sarojini’s husband Prakash has sent them the message to come home. When Prakash wonders if they will come at all, Mrs. Sarojini replies that Aruna will come at once for her share of the old man s things. Mrs. Sarojini asks her husband to wear the new shoes of her father. She also wants to pinch the old man’s TV set, computer and his bracelet too. She wants to do it before her sister’s arrival. When she tells the same, her husband agrees after some hesitation.

Mrs. Sarojini fastens the door and she and her husband shift the TV set and com¬puter and put the radio in their place. Their daughter Sushma understands that they are pinching the grandpa’s TV set and computer and asks them if they are pinching them. Mr. Prakash replies that her grandpa has given them those things before his death. Mrs. Sarojini and her husband carry them downstairs and put them in the parlour.
She asks her husband to wear her father’s bracelet round his wrist and he obeys. At the same time Mrs. Aruna and her husband come. Mrs. Sarojini tells them that the old man is found dead that morning when she takes up a bit of something for him on tray.

Mrs. Aruna and Mr. Rajesh don’t want to look at the old man. They prefer to have tea. Then they talk about how to announce the old man’s death in the papers. Then Mrs. Sarojini and Mrs. Aruna come to talk about dividing their father’s belongings. Mrs. Aruna tells that the old man has promised his gold ring for Srikar. This news amazes Mrs. Sarojini. Mr. Rajesh calls the old man “The drunken old beggar” when Sushma tells that grandpa hasn’t paid his insurance. Both the sisters complain that they have to put up with their father for all those years. Then Mrs. Sarojini asks Sushma to go and bring the bunch of keys from grandpa’s room. After some time, Sushma gets back scared and tells them that grandpa is getting up. All are amazed as they all think he is dead. Mr. Rao enters their room after a few minutes and is surprised to see Mrs. Aruna and her husband. He asks them why they are in mourning dress. Sushma tells her grandpa that she is very happy that he is not dead. Grandpa asks them who is dead. Mrs. Sarojini lies that Rajesh’s brother is dead. Mrs. Rao sees his shoes being worn by Prakash and says it is not good. Then he looks at the gold bracelet and understands that they have stolen it. He also understands that Mrs. Sarojini and her husband have stolen his TV set and computer.

Mr. Rao doesn’t want to stay with either of his daughters anymore. He declares that he is going to change his will leaving all his property to whoever he is living with when he dies. Mrs. Sarojini and Mrs. Aruna fight with each other to keep their father in their care. Both the sisters try to persuade him to keep him with them but he refuses to stay with them. Then the old man shocks them with his announcement. He announces that he has got to do three things the next Monday. He has got to go to the lawyer and change his will, to pay the insurance premium and to go to Tirumala to get married to Mrs. Laxmi, the owner of ’Komala Vilas’. He invites them all to the marriage ceremony. He thanks Mrs. Sarojini for bringing the TV set and computer downstairs as it will be easier to carry them across to his house after his marriage.

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

Study skills

Health is a major concern during old age. Maintaining health is very important for the elderly, particularly in rural areas, who must continue to work for a living even when they become aged. Good health is central to their ability to work, and support themselves and families. However, many poor rural elderly people have severe problems of health

Here is the data collected in January 2013 by ‘Help Age India’, a research and development journal on common health problems of the rural elderly in Andhra Pradesh. The data is collected from 150 male and 150 female rural elderly people of above 60 years old.

Common Health Problems of the Rural Elderly in Andhra Pradesh
AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2 8

Read, understand and analyse the data given in the above table and write a report on it to present on the World Grandparents’ Day.

You should include the following points in your report:

  • Introduction
  • The type of diseases old people suffer from below 10%, between 10-20, 21-30, 31- 40 and 41-50.
  • Which diseases have more or less effect on the health of the old people.

Answer:
This is a report based on the data collected in January 2013 by ’Help Age India’, a research and development journal on common health problems of the rural elderly in Andhra Pradesh. The data is collected from 150 male and 150 female rural elderly of above 60 years old. Health is a major concern of old age all over the world. Maintaining health is very important for the elderly who must continue to work for a living even when they become aged particularly in rural areas. However, many poor rural elderly have severe problems of health. Now, we have a look at the health problems being faced by the elderly of rural areas.

At first we see the health problems being faced by the males and the females of rural areas separately. Below 10% of males are suffering from urinary problems and piles. Between 10% and 20% of males are suffering from bowel complaints, ear problems, B.P./hypertension, mental depression, respiratory problems and diabetes. Between 21% and 30% of males are suffering from sleep disorders, digestive problems, dental problems and cold and cough. Between 31% and 40% of males are suffering from fatigue/general weakness. Between 41% and 50% of males are suffering from body/joint pains, and eye problems.

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

As far as women are concerned, below 10% of them are suffering from diabetes. Between 10% and 20% of females are suffering from dental problems, cold and cough, ear problems, B.P./hypertension, respiratory problems, urinary problems and piles. Between 21% and 30% of females are suffering from digestive problems and bowel complaints. Between 31% and 40% of females are suffering from fatigue/general weakness, sleep disorders and mental depression. Between 41% and 50% of females are suffering from eye problems. 55.33% of females are suffering from body/joint pains.

When we consider both males and females, below 10% of elderly people are suffering from diabetes and piles. Between 10% and 20% of them are suffering from cold and cough, ear problems, B.P./hypertension, respiratory problems and urinary problems. Between 21% and 30% of elderly people are suffering from mental depression, digestive problems, dental problems and bowel complaints. Between 31% and 40% of elderly people are suffering from fatigue/general weakness and sleep disorders. 45.33% of elderly people are suffering from eye problems and 52% of them are suffering from body/joint pains.

When we observe the data, we can understand that the health problems such as body/joint pains, eye problems, fatigue, sleep disorders, mental depression, digestive problems, dental problems and bowel complaints have more effect on the health of the old. When we compare with the above problems, the problems such as cough and cold, ear problems, B.P./hypertension, respiratory problems, urinary problems, diabetes and piles have less effect on their health. Good health is essential to their ability to work, to support themselves and families. They must get rid of their health problems to lead an active and happy life.

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

Listening

Listen to an interesting anecdote and say whether the following statements are true or false.

1. The woman was a stranger to Hyderabad.
2. In the beginning of the incident, the woman was at the Charminar.
3. The woman in this event might be a villager.
4. The woman knows that the buses in city have numbers.
5. The woman misunderstood the direction given by the police officer.
6. The police officer gave a wrong direction.
Answer:
1. True
2. False
3. True
4. False
5. True
6. False

Oral Activity

Work in groups. Tell your group any funny incident you may have witnessed/listened to.

Answer:
My friend Rahul told me this funny incident which he himself experienced. One evening he was returning home after watching a movie. It was very dark. He was all alone and very scared. The wind was blowing very hard. He even heard the cry of an owl.

On his way, he had to pass by a burial ground. When he was nearing it, he remem-bered horror serials he had watched on television. His mind was full of horror scenes. There was a thorny bush on the side of the road. It was so dark that nothing was visible to the naked eye. He was at his wit s end. He thought that there was something in the bush. He plucked up courage and took a step forward. He heard the sound again. There was something greyish in that bush. There were two glowing spots in the bush. He stood rooted to the spot, staring at them. He could neither go forward nor back. He thought that the glowing spots were the eyes of a skull. Suddenly, there was a ear¬splitting cry, and a huge grey form jumped out of the bush and ran away. “Aaaaaah….”

It was a donkey! He could breathe again, a donkey after all He laughed aloud for a long time. He reached his home and narrated the incident to the members of his family. They too laughed aloud.

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

The Dear Departed Part 2 Summary in English

When Abel Merryweather enters their room, he is surprised to see his daughter and son-in-law, Mrs. and Mr. Jordan. The two sisters and their husbands can’t believe their eyes. Abel comes forward to shake hand with his son-in-law, Mr. Ben Jordan. Ben retreats with Mrs. Jordan to a safe distance. Mrs. Slater pokes Abel with her hand to see if he is solid. Abel reveals that he is well enough but has a bit of a headache. Then Abel asks for his new slippers. When he observes Henry wearing his slippers, Mrs. Slater snatches them from Henry and gives them to Abel. He puts them on and sits in an armchair.

Abel asks them why they all are in mourning. Mrs. Jordan makes up some story to pacify him. She tells that Ben’s brother has died. Abel tells them to sit down and take tea. He suggests that they all should be jolly. Then he notices his bureau there in that room. He asks Mrs. Slater and Henry what they have been doing with his bureau. At the same time he hears a clock striking six. He looks at it and questions them why it is there. He grumbles and scolds for her deceitful acts. Mrs. Jordan blames her sister of robbing their father. The two sisters start quarrelling. Abel understands his daughters’ dishonesty. He comes to know about the reality.

Abel doesn’t want to stay with either of his daughters anymore. He addresses his daughters directly and declares that he is going to change his will leaving all his property to whoever he is living with when he dies. Mrs. Slater and Mrs. Jordan fight with each other to keep their father in their care. Both the sisters try to persuade him to make him live with them but he refuses to stay with them. Then Abel makes an announcement which shocks everyone. He announces that he has got to do three things the next Monday He has got to go to the lawyer and change his will and he has got to go to the insurance office to pay the premium and then he has got to go to St. Philip’s Church and get married. Everyone is shocked. Abel reveals that he has at last found someone who is happy to keep him. When he leaves the room, he invites them all to his marriage with Mrs. John Shorrocks who keeps the ‘Ring-o-Bells’. He thanks Mrs. Slater for bringing the bureau downstairs as it will be easier to carry it across to the Ring-o-Bells.’

The Dear Departed Part 2 About the Author

William Stanley Houghton (1881 – 1913) was a famous English dramatist. He was one of the best of a group of realistic playwrights often called the Manchester School. In every play he sought to present an idea. He had a remarkable gift for dialogue that is evident in ‘The Dear Departed’. The Dear Departed was first produced in Manchester in 1908. Here Houghton satirizes the degradation of moral values in the British middle-class.

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

The Dear Departed Part 2 Glossary

thrust (v): to push something somewhere quickly

skip (v): move with quick steps and jumps

smartly (adj): elegantly / stylishly

retreat (v): move back

approach (v): come near to somebody

gingerly (adv): in a careful way

poke (v): push

solid (adj): firm

what the devil (phrase): old fashioned way of showing annoyance or displeasure; (This phrase is always used in questions.)

tomfoolery (n): foolish or silly behaviour

took by surprise (idiom): happened unexpectedly so that somebody was slightly shocked

eh? (Intj): a request for repetition or confirmation of what was just said.

what the dickens (idiom): (old-fashioned and informal) used in questions instead of ‘devil’ to show that you are annoyed or surprised

hearth (n): the area of floor around a fireplace in a house

snatch (v): to take away something from someone with a quick, often violent movement

‘em (pro): them

put on (phr.v): wear

haste (n): speed in doing something, especially because you do not have enough time

Oh (Inter): used to express surprise, fear, joy, etc.

vindictive whisper (n.phr.) : talking about someone in a harsh, hasty manner

ab (Interject): used to express pleasure, admiration or sympathy hold your tongue (phrase): to tell someone to stop talking

chuckle (v): to laugh quietly

AP SSC 10th Class English Solutions Chapter 2B The Dear Departed Part 2

at a loss (Idiom): puzzled

er (intj): used to express hesitation or uncertainty

prompting (v): reminding the dialogue or words

ay (interjection): used to express distress or regret

drat (interjection): a fairly mild expression of slight annoyance nothing short of (Idiom): as bad as

double-faced (adj): hypocritical/deceitful/dishonest

damn it (Intellect.): an expression of displeasure annoyance

sneak: to go somewhere secretly and quietly in order to avoid being seen or heard

resume : to start doing something again alter stopping or being interrupted

thumping (v): hitting hard

gaze: look fixedly

oho (interject): used for showing that you are surprised in a happy way

sobbing (v): crying noisily. taking sudden sharp breaths

bits of things (phr): property

will (n): legal document that says what is to happen to somebody’s property alter his/her death

strike (v): come into somebodys mind suddenly

It’s quite time you came: it Is the right time to come

fancy (v): want/feel like

put up with (phr.v): bear / look after

out of senses (phr.): silly and senseless

consternation (n): a worried. sad feeling

Ring-o-Bells (n): the name of a restaurant

a good while (Idm): for quite sometime

handier (adj): easier

AP SSC 10th Class English Solutions Chapter 1B Every Success Story is Also a Story of Great Failures

AP State Board Syllabus AP SSC 10th Class English Textbook Solutions Chapter 1B Every Success Story is Also a Story of Great Failures Textbook Questions and Answers.

AP State Syllabus SSC 10th Class English Solutions Chapter 1B Every Success Story is Also a Story of Great Failures

10th Class English Chapter 1B Every Success Story is Also a Story of Great Failures Textbook Questions and Answers

Comprehension

I. Answer the following questions.

Question 1.
‘To Lincoln, defeat was a detour and not a dead end.’ Justify this statement from the life of Lincoln.
Answer:
Abraham Lincoln was elected President of the United States at age 52. Before he became President, he faced many setbacks. He failed in business, lost in legislative, senatorial and congressional races. He lost his sweetheart when he was 22. Thus, Lincoln had failed many times before he got the big success. He proved that defeat was a detour and not a dead end.

AP SSC 10th Class English Solutions Chapter 1B Every Success Story is Also a Story of Great Failures

Question 2.
What did Socrates suggest as the secret to success? Do you agree or disagree with it? Give reasons for your answer.
Answer:
Socrates suggested that burning desire is the only secret to one’s success. I agree with this statement. If we don’t have a desire, we can’t achieve anything. A burning desire is the starting point of all accomplishments. A weak desire can’t produce great results. The motivation to get the success comes from the burning desire to achieve a purpose.

Question 3.
Complete the following table about the failures and successes of the great personalities mentioned in the lesson you have just read. The first one is done for you.
AP SSC 10th Class English Solutions Chapter 1B Every Success Story is Also a Story of Great Failures 1
Answer:

Person Failures/Rejections he faced Final success
1. Abraham Lincoln Failed in business, defeated in legislative elections, had nervous breakdown, lost congressional race and senatorial race Elected President of the United States of America
2. Lee de Forest Charged by the district attorney Invented the triodes tube
3. Wright Brothers A New York Times editorial questioned the wisdom of the Wright Brothers Took their famous flight at Kitty Hawk
4. Colonel Sanders Knocked many doors before he got the first order Became famous as a busi­nessman and restaurateur who founded the Ken­tucky Fried Chicken chain restaurants.
5. Walt Disney Newspaper editors rejected him by saying that he had no talent. Created some of the world’s most well-known fictional characters inclu­ding Mickey Mouse. He was well known as an ani mator, film producer, di­rector, screenwriter, voice actor, entrepreneur, entertainer, international icon and philanthropist.
6. Thomas Edison As a child, he was considered to be a stupid, lost his factory to fire. Grew up to be a great scientist.
7. Henry Ford Forgot to put the reverse gear in his first car, broke at the age of 40. Established cars company
8. Lee lacocca Fired by Henry Ford 11 Well known for engineer­ing the Ford Mustang and Ford Pinto cars and became one of the most famous business people in the world.
9. Ludwig van Beethoven He was told that he had no talent for music. Gave some of the best music to the world.

AP SSC 10th Class English Solutions Chapter 1B Every Success Story is Also a Story of Great Failures

Study skills

Read the following story.

An elderly carpenter was ready to retire. He told his employer-contractor of his plans to leave the house-building business to live a more leisurely life with his wife and enjoy his extended family. He would miss the paycheck each week, but he wanted to retire. They could get by.

The contractor was sorry to see his good worker go and asked if he could build just one more house as a personal favour. The carpenter agreed. But over time it was easy to see that his heart was not in his work. He resorted to shoddy workmanship and used inferior materials. It was an unfortunate way to end a dedicated career.

When the carpenter finished his work, his employer came to inspect the house. Then he handed the front-door key to the carpenter and said, “This is your house… my gift to you.”
The carpenter was shocked!

What a shame! If he had only known that he was building his own house, he would have done it all so differently.
So it is with us. We build our lives, a day at a time, often putting less than our best into the building. Then, with a shock, we realize we have to live in the house we have built. If we could do it over, we would do it much differently.

But, you cannot go back. You are the carpenter, and every day you hammer a nail, place a board, or erect a wall. Someone once said, “Life is a do-it-yourself project.” Your attitude, and the choices you make today, help build the “house” you will live in tomorrow. Therefore, build wisely!

I. Complete the table given below.

AP SSC 10th Class English Solutions Chapter 1B Every Success Story is Also a Story of Great Failures 2AP SSC 10th Class English Solutions Chapter 1B Every Success Story is Also a Story of Great Failures 3
Answer:

Point to be observed Observation/Point of view
1. The setting/location in which the story took place (A building) Retirement of a carpenter
2. The main characters A contractor and a carpenter
3. The main events a. The carpenter decided to retire.
b. He told his employer (contractor) about his decision.
c. The contractor requested the carpenter to build one more house as a personal favour.
d. The carpenter agreed and finished his work.
e. The contractor gave the very house to the carpenter as a gift.
4. The turning point in the story The contra.ctor inspected the house, handed the front-door key to the carpenter and told him to take the house as a gift.
5. The irony in the story The carpenter thought that the house was for the contractor. As he had already decided to retire, he didn’t do the work with good workmanship. But he was shocked to know that the house was for him.
6. The message in the story “Build your life with good attitude.”
7. Possible title “Building One’s Life.”

AP SSC 10th Class English Solutions Chapter 1B Every Success Story is Also a Story of Great Failures

II. Extended Writing

Rewrite the above story by giving another ending.

Answer:
An elderly carpenter was ready to retire. He told his employer-contractor of his plans to leave the house-building business to live a more leisurely life with his wife and enjoy his extended family. He would miss the paycheck each week, but he wanted to retire. They could get by.

The contractor was sorry to see his good worker go and asked if he could build just one more house as a personal favour. The carpenter agreed. He wanted to build the house using all his skill. He knew that his employer had confidence and faith in him. He began his work and completed with determination. He gave the final touch to the house and invited his employer. The employer came to inspect the house.

The contractor was amazed to see the house with all its fine work. He praised the carpenter for building such a beautiful house. He thanked the carpenter and gave him a big amount of money. The carpenter felt very happy thanked his employer and went away.

Listening

Listen to the story about a farmer.

Just now you have listened to a story about a farmer. Here are some sentences that describe the events in the story. However, they are not in the order in which they occur in the story. Listen to the story and arrange them in the order in which they occur. Put 1 after the event that occurs first, 2 against the next and so on.

He threw himself into the Barcelona River and committed suicide.
The wise man said, “Because that is a diamond.”
He picked up the stone and put it in the living room.
He looked all through Europe and couldn’t find any.
They found that the farm was indeed covered with acres and acres of diamonds.
That night the farmer couldn’t sleep.
The person who had bought his farm was watering the camels at a stream.
He made arrangements to sell off his farm and went in search of diamonds.
He was unhappy and he was discontent.
A wise man told him about the glory of diamonds.
Answer:
A wise man told him about the glory of diamonds.
That night the farmer couldn’t sleep.
He was unhappy and he was discontent.
He made arrangements to sell off his farm and went in search of diamonds.
He looked all through Europe and couldn’t find any.
He threw himself into the Barcelona River and committed suicide.
The person who had bought his farm was watering the camels at a stream.
He picked up the stone and put it in the living room.
The wise man said, “Because that is a diamond.”
They found that the farm was indeed covered with acres and acres of diamonds.

AP SSC 10th Class English Solutions Chapter 1B Every Success Story is Also a Story of Great Failures

Oral Activity

After listening to the story, work in pairs and discuss the advantages and disadvantages of travelling abroad. You may use the hints given in the box for your understanding.

AP SSC 10th Class English Solutions Chapter 1B Every Success Story is Also a Story of Great Failures 4

Answer:

Advantages and Disadvantages of Travelling Abroad
Nowadays we see many students, educated people and some others going abroad everywhere due to several reasons. Students go for studies. Educated people go for jobs. Other people go for touring. Going abroad has not only advantages but also disadvantages.
Advantages:

  1. As far as merits are concerned while travelling abroad you will come to know about the other cultures and rituals. It will definitely add to one’s knowledge.
  2. Students go abroad for their studies. Educated people go abroad for getting better opportunities.
  3. By going abroad they can get good and quality education.
  4. They can study and get jobs abroad.
  5. They can settle in their lives by getting better earning. Thus they can improve their social status.
  6. They can get more opportunities and more income.
  7. They can learn new languages.
  8. They can make friends with people from different countries.
  9. They can know about recent technological developments.
  10. The new environment can allow us to see the world and create memories that will last forever.

Disadvantages:

  1. People who go abroad would cut off themselves from their roots from the native country.
  2. They should forget their own environment which is friendly and lively.
  3. They should live away from their culture, rituals and religions.
  4. They should face difficulties in adapting other cultures.
  5. They would miss the native food and tastes.
  6. They would miss the nearness of their parents.
  7. They should live far away from their parents. They miss the sacred love their parents.
  8. Their parents would suffer from old age problems as there is nobody to take care of them.

AP SSC 10th Class English Solutions Chapter 1B Every Success Story is Also a Story of Great Failures

Every Success Story is Also a Story of Great Failures Summary in English

All stories of success are also stories of great failures. Failures are the stepping stones to success. We all know that Abraham Lincoln was the President of the United States, It was not an easy thing for him to reach such a great height in his life. He faced major setbacks in business as well as politics before he was elected President of the United States at age 52. He didn’t lose hope and give up his efforts.

Lee De Forest was the inventor of the triodes tube. In 1913, he was charged for using dishonest means to mislead the public. Though he was publicly humiliated, he didn’t stop his efforts and made so many inventions.

The Wright Brothers successfully took their flight after their wisdom was questioned by a New York Times editorial.

Colonel Sanders was the founder of KFC chain restaurants. He, at age 65* worked hard and succeeded in selling food items. He had knocked on more than a thousand doors before he got his first order.

Walt Disney, the famous cartoonist faced many rejections before his getting the success. He created Mickey Mouse when he was working out of a small mouse infested shed near the church.

Thomas Edison, who was partially deaf, failed 10,000 times while he was working on the light bulb. He didn’t give up and got the success finally. He was the man with great attitude. Though he lost his factory to fire, he went on inventing the phonograph. He didn’t lose hope at any stage of his life.

Henry Ford forgot to put the reverse gear in the first car he made and went broke at the age of 40. He succeeded later and reached top position in selling of cars.

Ludwig van Beethoven was a German composer and pianist. Though he was told that he had no talent for music, he gave some of the best music.

All these persons succeeded in spite of their problems. A setback can act as a driving force and teach us humility. We have to find courage and faith to overcome the setback. We must get rid of fear and doubt. We need to try to become victors. We need to have burning desire to achieve our task. A burning desire is the key to one’s success. We can’t get great results with a weak desire.

IF YOU THINK

If you think you are beaten, you are.
If you think you dare not, you don’t!
If you like to win, but think you can’t,
It’s almost a cinch you won’t.
If you think you’ll lose, you’re lost;
For out in the world we find
Success begins with a fellow’s will;
It’s all in the state of mind.
If you think you are outclassed, you are,
You’ve got to think high to rise,
You’ve got to be sure of yourself before
You can ever win a prize.
Life’s battles don’t always go
To the stronger and faster man,
But sooner or later the man who wins
Is the man who thinks he can.

IF YOU THINK Summary
Success, failure, win, defeat – these ail depend upon the man’s thinking. Success begins with a fellow’s will. If one thinks he is beaten or lost, it certainly happens. If one thinks one is outclassed, one is outclassed. So, one needs to be positive in one’s thoughts. One needs to think high to get success. The person who thinks can easily win in the end. ‘ Victory is not always on the side of the stronger and faster man.

AP SSC 10th Class English Solutions Chapter 1B Every Success Story is Also a Story of Great Failures

Every Success Story is Also a Story of Great Failures About the Author

Shiv Khera is an Indian author of self-help books and activist.
While working in the United States, he was inspired by a lecture delivered by Norman Vincent Peale and followed his motivational teachings. Khera has written several books including You Can Win.
His mission is “to ensure freedom through education and justice.”

Shiv Khera was born in a business family who used to have coal mines Kendua in Dhanbad, India. Soon after the nationalisation of coal mines by the Indian government, he had to search for his own living. In his early years he worked as a car washer, a life insurance agent, and a franchise operator before he became a motivational speaker.

Every Success Story is Also a Story of Great Failures Glossary

overcome(v): to defeat or succeed in controlling or dealing with something

detour(n): a road or route that is used when the usual one is closed

triodes tube (n): A triode is an electronic amplification tube having three active electrodes. Invented in 1906, the triode vacuum tube was the first electronic amplification device. This invention founded the electronic age, making possible amplified radio technology and long-distance telephony.

Lee de Forest: an American inventor with over 180 patents to his credit. He invented the Audion, a vacuum tube that takes relatively weak electrical signals and amplifies them. He is one of the fathers of the “electronic age,” as the Audion helped to usher in the widespread use of electronics. He is also credited with one of the principal inventions that brought sound to motion pictures.

fraudulent (adj): intended to cheat someone, usually in order to make money illegally

attorney (n): a lawyer

humiliate (v): to make someone feel ashamed or stupid

Colonel Sanders: Colonel Harland David Sanders was an American business man and restaurateur who founded the Kentucky Fried Chicken (KFC) chain restaurants

beat-up (adj): old and damaged

quit (v): to leave ; to stop doing something

recipe (n): set of instructions for cooking a particular type of food

Walt Disney: an American animator, film producer, director, screenwriter, voice actor, entrepreneur entertainer, international icon and philanthropist, well known for his influence in the field of entertainment during the 20th century. He created some of the world’s most well-known fictional characters including Mickey Mouse.

rejection (n): the act of not accepting

Infest(v): to exist in large numbers in a particular place, often causing damage or disease (especially of insects or animals such as rats)

Henry Ford: an American industrialist, the founder of the Ford Motor company, and sponsor of the development of the assembly line technique of mass production. He did not Invent the automobile but he developed and manufactured the first automobile that many middle class Americans could afford to buy.

disaster (n): a sudden event such as a flood, storm or accident

Lee Iacocca: an American Business man known for engineering the Ford Mustang and Ford Pinto cars. He was the former chairman of the Chrysler Corporation. He was one of the most famous business people in the world. He is the author (or coauthor) of several books, including Iacocca.

Ludwig van Beethoven: a German composer and pianist. He was a crucial figure in the transition between the Classical and Romantic eras in Western art music. He remains one of the most famous and influential of all composers. His best known compositions include 9 symphonies. 5 concertos, 2 piano sonatas and 16 string quartets. He also composed other chamber music, choral works (Including the celebrated Missa Solemnis and songs).

inevitable (adj): certain to happen : that you cannot avoid or prevent

setback (n): a problem that delays or prevents progress

humility (n): the quality of not being too proud about oneself.

victor (n): the winner

stumbling block (n): a problem or difficulty that stops oneself from achieving something

Napoleon Hill: an American author in the area of the new thought movement who was one of the earliest producers of the modern genre of personal-success literature. He is widely considered to be one of the great writers on success.

conceive(n): to form an idea, a plan, etc. In your mind; to imagine something

AP SSC 10th Class English Solutions Chapter 1B Every Success Story is Also a Story of Great Failures

Socrates (469 BC – 399 BC): a classical Greek Athenian philosopher credited as one of the founders of Western Philosophy; He is an enigmatic figure known chiefly through the accounts of later classical writers, especially the writings of his students Plato and Xenophon and the plays of his contemporary Aristopanes. Many would claim that Plato’s dialogues are the most comprehensive accounts of Socrates to survive from antiquity. Socrates has become renowned for his contribution to the field of ethics.

ducked(v): pushed somebody under water and held them there for a short time

gasp (v): to breathe quickly in a way that can be heard because one is having difficulty in breathing .

accomplishment (n): something successful or impressive that is achieved after a lot of effort and hard work

cinch(n): a thing that is certain to happen

outclassed (v): overcame

will (n): determination to do something that one has decided to do

AP SSC 10th Class Maths Solutions Chapter 12 Applications of Trigonometry Ex 12.1

AP State Board Syllabus AP SSC 10th Class Maths Textbook Solutions Chapter 12 Applications of Trigonometry Ex 12.1 Textbook Questions and Answers.

AP State Syllabus SSC 10th Class Maths Solutions 12th Lesson Applications of Trigonometry Exercise 12.1

10th Class Maths 12th Lesson Applications of Trigonometry Ex 12.1 Textbook Questions and Answers

Question 1.
A tower stands vertically on the ground. From a point which is 15 meter away from the foot of the tower, the angle of elevation of the top of the tower is 45°. What is the height of the tower?
Answer:
AP SSC 10th Class Maths Solutions Chapter 12 Applications of Trigonometry Ex 12.1 1Let the height of the tower = h m
Distance of the point of observation from the foot of the tower =15 cm.
Angle of elevation of the top of the tower = 45°
From the figure tan θ = \(\frac{\text { opp. side }}{\text { adj. side }}\)
tan 45° = \(\frac{h}{15}\)
⇒ 1 = \(\frac{h}{15}\)
∴ h = 1 × 15 = 15 m

AP SSC 10th Class Maths Solutions Chapter 12 Applications of Trigonometry Ex 12.1

Question 2.
A tree breaks due to storm and the broken part bends so that the top of the tree touches the ground by making 30° angle with the ground. The distance between the foot of the tree and the top of the tree on the ground is 6 m. Find the height of the tree before falling down.
Answer:
AP SSC 10th Class Maths Solutions Chapter 12 Applications of Trigonometry Ex 12.1 2Distance between the foot of tree and the point of contact of the top of the tree on the ground = 6 cm.
Let the length of the remaining part be = h m.
Let the length of the broken part be = x m.
Angle made by the broken part with the ground = 30°.
From the figure
tan 30° = \(\frac{h}{6}\)
⇒ \(\frac{1}{\sqrt{3}}\) = \(\frac{h}{6}\)
∴ h = \(\frac{6}{\sqrt{3}}=\frac{3 \times 2}{\sqrt{3}}\) = 2√3 m
Also cos 30° = \(\frac{6}{x}\)
⇒ \(\frac{\sqrt{3}}{2}\) = \(\frac{6}{x}\)
⇒ x = \(\frac{6 \times 2}{\sqrt{3}}\) = \(\frac{3 \times 2 \times 2}{\sqrt{3}}\) = 4√3
∴ Height of the tree = broken part + remaining part
= x + h
= 2√3 + 4√3 = 6√3 m
= 6 × 1.732
≃ 10.392 m.

AP SSC 10th Class Maths Solutions Chapter 12 Applications of Trigonometry Ex 12.1

Question 3.
A contractor wants to set up a slide for the children to play in the park. He wants to set it up at the height of 2 m and by making an angle of 30° with the ground. What should be the length of the slide?
Answer:
AP SSC 10th Class Maths Solutions Chapter 12 Applications of Trigonometry Ex 12.1 3Height of slide = 2 m
Let the length of the slide = x m.
Angle made by the slide with the ground = 30°
From the figure
sin 30° = \(\frac{2}{x}\)
⇒ \(\frac{1}{2}\) = \(\frac{2}{x}\)
⇒ x = 2 × 2 = 4 m
Length of the slide = 4 m.

Question 4.
Length of the shadow of a 15 meter high pole is 5√3 meters at 7 o’clock in the morning. Then, what is the angle of elevation of the Sun rays with the ground at the time?
Answer:
AP SSC 10th Class Maths Solutions Chapter 12 Applications of Trigonometry Ex 12.1 4Height of the pole = 15 m
Length of the shadow = 5√3 m
Let the angle of elevation be ‘θ’.
Then from the figure
tan θ = \(\frac{15}{5 \sqrt{3}}=\frac{5 \times \sqrt{3} \times \sqrt{3}}{5 \times \sqrt{3}}\) = √3
tan θ = √3 = tan 60°
∴ θ = 60°
∴ Angle of elevation of Sun rays with the ground = 60°.

AP SSC 10th Class Maths Solutions Chapter 12 Applications of Trigonometry Ex 12.1

Question 5.
You want to erect a pole of height 10 m with the support of three ropes. Each rope has to make an angle 30° with the pole. What should be the length of the rope?
Answer:
Height of the pole = 10 m
Let the length of each rope = x
Angle made by the rope with the pole = 30°
AP SSC 10th Class Maths Solutions Chapter 12 Applications of Trigonometry Ex 12.1 5
From the figure
cos 30° = \(\frac{10}{x}\)
\(\frac{\sqrt{3}}{2}\) = \(\frac{10}{x}\)
⇒ x = \(\frac{10 \times 2}{\sqrt{3}}=\frac{20}{\sqrt{3}}\)
∴ Length of each rope = \(\frac{20}{\sqrt{3}}\)m
= 11.546 m.

∴ Total length of the rope = 3 × \(\frac{20}{\sqrt{3}}\)
= 20√3
= 20 × 1.732
≃ 34.64 m.

Question 6.
Suppose you are shooting an arrow from the top of a building at a height of 6 m to a target on the ground at an angle of depression of 60°. What is the distance between you and the object?
Answer:
AP SSC 10th Class Maths Solutions Chapter 12 Applications of Trigonometry Ex 12.1 6Height of the building = 6 m
Angle of depression = Angle of elevation at the ground = 60°
Let the distance of the target from the shooting point = x m
Then from the figure
sin 60° = \(\frac{6}{x}\)
\(\frac{\sqrt{3}}{2}\) = \(\frac{6}{x}\)
⇒ x = \(\frac{6 \times 2}{\sqrt{3}}=\frac{2 \times \sqrt{3} \times \sqrt{3} \times 2}{\sqrt{3}}\) = 4√3
∴ Distance = 4√3 m or
4 × 1.732 = 6.928 m.

AP SSC 10th Class Maths Solutions Chapter 12 Applications of Trigonometry Ex 12.1

Question 7.
An electrician wants to repair an electric connection on a pole of height 9 m. He needs to reach 1.8 m below the top of the pole to do repair work. What should be the length of the ladder which he should use, when he climbs it at an angle of 60° with the ground? What will be the distance between foot of the ladder and foot of the pole?
Answer:
AP SSC 10th Class Maths Solutions Chapter 12 Applications of Trigonometry Ex 12.1 7Height of the pole = 9m
Height of the point from the ground where he reaches the pole = 9 – 1.8 = 7.2 m
Angle of elevation = 60°
Angle of depression = Angle of elevation at the ground = 60°
Let the distance of the target from the shooting point = x m
Then from the figure
sin 60° = \(\frac{7.2}{x}\)
\(\frac{\sqrt{3}}{2}\) = \(\frac{7.2}{x}\)
⇒ x = \(\frac{7.2 \times 2}{\sqrt{3}}=\frac{3 \times 2.4 \times 2}{\sqrt{3}}=\frac{\sqrt{3} \times \sqrt{3} \times 4.8}{\sqrt{3}}\)
⇒ x = 1.732 × 4.8
≃ 8.31 m
Also tan 60° = \(\frac{7.2}{d}\)
√3 = \(\frac{7.2}{d}\)
⇒ d = \(\frac{7.2}{\sqrt{3}}=\frac{2.4 \times 3}{\sqrt{3}}\) = 2.4 × √3 = 2.4 × 1.732
∴ d ≃ 4.1568 m

Question 8.
A boat has to cross a river. It crosses the river by making an angle of 60° with the bank of the river due to the stream of the river and travels a distance of 600 m to reach the another side of the river. What is the width of the river?
Answer:
AP SSC 10th Class Maths Solutions Chapter 12 Applications of Trigonometry Ex 12.1 8Let the width of the river = AB = x m
Angle made by the boat = 60°
Distance travelled = AC = 600 m
From the figure
cos 60° = \(\frac{x}{600}\)
\(\frac{1}{2}\) = \(\frac{x}{600}\)
⇒ x = \(\frac{600}{2}\) = 300 m.
AP SSC 10th Class Maths Solutions Chapter 12 Applications of Trigonometry Ex 12.1 9In the figure
A = Boat’s place
C = Reach place of another side (or) Point of observation.
AC = Travelling distance of the boat ∠AC = 60°
AB = width of the river AB
In △ABC, sin 60° = \(\frac{AB}{AC}\)
⇒ \(\frac{\sqrt{3}}{2}\) = \(\frac{AB}{600}\)
⇒ AB = 600 × \(\frac{\sqrt{3}}{2}\) = 300√3

AP SSC 10th Class Maths Solutions Chapter 12 Applications of Trigonometry Ex 12.1

Question 9.
An observer of height 1.8 m is 13.2 m away from a palm tree. The angle of elevation of the top of the tree from his eyes is 45°. What is the height of the palm tree?
Answer:
Height of the observer = 1.8 m
Distance of the observer from the palm tree = 13.2 m
AP SSC 10th Class Maths Solutions Chapter 12 Applications of Trigonometry Ex 12.1 10From the figure
tan 45° = \(\frac{x}{13.2}\)
⇒ 1 = \(\frac{x}{13.2}\)
⇒ x = 13.2 m
∴ Height of the palm tree = 13.2 + 1.8 = 15 m.

Question 10.
In the given figure, AC = 6 cm, AB = 5 cm and ∠BAC = 30°. Find the area of the triangle.
AP SSC 10th Class Maths Solutions Chapter 12 Applications of Trigonometry Ex 12.1 11Answer:
AP SSC 10th Class Maths Solutions Chapter 12 Applications of Trigonometry Ex 12.1 12Draw a perpendicular BD to AC
∴ BD ⊥ AC
Now let AD = 6 – x and DC = x
Given AB = 5 cm and ∠BAD = 30° then in △ABD
sin 30° = \(\frac{BD}{AB}\) = \(\frac{BD}{5}\) = \(\frac{1}{2}\)
⇒ BD = \(\frac{5}{2}\) = 2.5 cm
and cos 30° = \(\frac{AD}{AB}\) = \(\frac{6-x}{5}\) = \(\frac{\sqrt{3}}{2}\)
⇒ 6 – x = \(\frac{5 \sqrt{3}}{2}\)
⇒ x = 6 – \(\frac{5 \sqrt{3}}{2}\) = 6 – \(\frac{5(1.732)}{2}\)
∴ x = 1.67
∴ Area of △ABC = \(\frac{1}{2}\)bh
= \(\frac{1}{2}\) × AC × BD
= \(\frac{1}{2}\) × 6 × 2.5
= 7.5 cm2

AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2

AP State Board Syllabus AP SSC 10th Class Maths Textbook Solutions Chapter 8 Similar Triangles Ex 8.2 Textbook Questions and Answers.

AP State Syllabus SSC 10th Class Maths Solutions 8th Lesson Similar Triangles Exercise 8.2

10th Class Maths 8th Lesson Similar Triangles Ex 8.2 Textbook Questions and Answers

Question 1.
In the given figure, ∠ADE = ∠B
i) Show that △ABC ~ △ADE
ii) If AD = 3.8 cm, AE = 3.6 cm, BE = 2.1 cm, BC = 4.2 cm, find DE.
AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2 1
Answer:
i) Given: △ABC and ∠ADE = ∠B
R.T.P: △ABC ~ △ADE.
Proof: In △ABC and △ADE
∠A = ∠A [∵ Common]
∠B = ∠ADE [∵ Given]
∴ ∠C = ∠AED [∵ By Angle Sum property of triangles] △ABC ~ △ADE by AAA similarity condition.]

ii) AD = 3.8 cm, AE = 3.6 cm, BE = 2.1 cm, BC = 4.2 cm, find DE.
To find DE; △ABC ~ △ADE
Hence,
\(\frac{AB}{AD}\) = \(\frac{BC}{DE}\) = \(\frac{AC}{AE}\)
[∵ Ratios of corresponding sides are equal]
AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2 2

AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2

Question 2.
The perimeters of two similar triangles are 30 cm and 20 cm respectively. If one side of the first triangle is 12 cm, determine the corresponding side of the second triangle.
Answer:
AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2 3
Given: △ABC ~ △PQR
Perimeter of △ABC = 30 cm.
Perimeter of △PQR = 20 cm.
AB = 12 cm.
To find: \(\overline{\mathrm{PQ}}\)
Ratio of perimeters = 30 : 20 = 3 : 2
Let the length of the side corresponding to the side with length 12 cm be x.
Then 30 : 20 : : 12 : x
30x = 20 x 12
\(x = \frac{20 \times 12}{30}\) = 8 cm

Question 3.
A girl of height 90 cm is walking away from the base of a lamp-post at a speed of 1.2 m/sec. If the lamp-post is 3.6 m above the ground, find the length of her shadow after 4 seconds.
Answer:
AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2 4
Given:
A lamp-post \(\overline{\mathrm{AB}}\) of height = 3.6 m
= 360 cm.
Speed of the girl = 1.2 m/sec.
Distance travelled in 4 sec = Speed x Time = 1.2 × 4 = 4.8 m = 480 cm.
\(\overline{\mathrm{CD}}\), height of the girl = 90 cm.
Let the length of the shadow at a distance of 4.8 m from the lamp post = x cm.
From the figure,
△ABE ~ △DCE
[∵ ∠B = ∠C = 90°
∠E = ∠C common
(A.A. similarity)]
Hence,
\(\frac{AB}{DC}\) = \(\frac{BE}{CE}\) = \(\frac{AE}{DE}\)
∴ \(\frac{360}{90}\) = \(\frac{480+x}{x}\)
⇒ 4 = \(\frac{480+x}{x}\)
⇒ 4x = 480 + x
⇒ 4x – x = 480
⇒ 3x = 480
⇒ x = 160 cm = 1.6 m
∴ Length of the shadow = 1.6 m

AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2

Question 4.
CM and RN are respectively the medians of similar triangles △ABC and △PQR. Prove that
i) △AMC ~ △PNR
ii) \(\frac{CM}{RN}\) = \(\frac{AB}{PQ}\)
iii) △CMB ~ △RNQ
AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2 5
Answer:
Given : △ABC ~ △PQR
CM is a median through C of △ABC.
RN is a median through R of △PQR.
R.T.P:
i) △AMC ~ △PNR.
Proof: In △AMC and △PNR,
\(\frac{AC}{PR}\) = \(\frac{AM}{PN}\) and ∠A = ∠P [∵ In △ABC, △PQR AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2 6 and M, N are the mid-points of AB and PQ]
∴ △AMC ~ △PNR
[∵ SAS similarity condition]

ii) \(\frac{CM}{RN}\) = \(\frac{AB}{PQ}\)
Proof: From (i) we have
△AMC ~ △PNR
Hence \(\frac{AC}{PQ}\) = \(\frac{AM}{PN}\) = \(\frac{CM}{RN}\)
[∵ Ratio of corresponding sides of two similar triangles are equal]
Thus, \(\frac{CM}{RN}\) = \(\frac{AM×2}{PN×2}\)
[Multiplying both numerator and the denominator by 2]
\(\frac{CM}{RN}\) = \(\frac{AB}{PQ}\) [2AM = AB; 2PN = PQ]

iii) △CMB ~ △RNQ
Proof: In △CMB and △RNQ
∠B = ∠Q [Corresponding angles of △ABC and △PQR]
Also, \(\frac{BC}{RQ}\) = \(\frac{BM}{QN}\)
AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2 7
Thus, △CMB ~ △RNQ by S.A.S similarity condition.

AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2

Question 5.
Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at the point ‘O’. Using the criterion of similarity for two triangles, show that \(\frac{OA}{OC}\) = \(\frac{OB}{OD}\).
Answer:
AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2 8
Given : □ ABCD, AB || DC
The diagonals AC and BD intersect at ‘O’.
R.T.P: \(\frac{OA}{OC}\) = \(\frac{OB}{OD}\)
Construction: Draw EF || AB, passing through ‘O’.
Proof: In △ACD, OE || CD [∵ Construction]
Hence \(\frac{OA}{OC}\) = \(\frac{EA}{ED}\) …….. (1)
(∵ Line drawn parallel to one side of a triangle divides other two sides in the same ratio – Basic proportionality theorem)
Also in △ABD, EO || AB [Construction] Hence,
\(\frac{EA}{ED}\) = \(\frac{OB}{OD}\) ……… (2)
(∵ Basic proportionality theorem) From (1) and (2), we have
\(\frac{OA}{OC}\) = \(\frac{OB}{OD}\)
∴ Hence proved.

Question 6.
AB, CD, PQ are perpendicular to BD. AB = x, CD = y and PQ = z, prove that \(\frac{1}{x}+\frac{1}{y}=\frac{1}{z}\).
AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2 9
Answer:
Given ∠B = ∠Q = ∠D = 90°
Thus, AB || PQ || CD.
Now in △BQP, △BDC
∠B = ∠B (Common)
∠Q = ∠D (90°)
∠P = ∠C [∵ Angle Sum property of triangles]
∴ △BQP ~ △BDC
(by A.A.A similarity condition)
Hence \(\frac{BQ}{BD}\) = \(\frac{PQ}{CD}\)
[∵ Ratio of corresponding sides is equal] Also in △DQP and △DBA
∠D = ∠D (Common)
∠Q = ∠B (90°)
∴ △DQP ~ △DBA (by A.A. similarity condition)
\(\frac{QD}{BD}\) = \(\frac{PQ}{AB}\)
[ Ratio of corresponding sides is equal]
Adding (1) and (2), we get
AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2 10

AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2

Question 7.
A flag pole 4 m tall casts a 6 m., shadow. At the same time, a nearby building casts a shadow of 24 m. How tall is the building?
Answer:
Given: 4 m length flag pole casts a shadow 6 m.
Let x m length/tall building casts a shadow 24 m.
AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2 11
Let AB be the length of flag pole = 4 m.
Shadow of AB = BC = 6 m.
PQ be the building = x m (say)
QR, the shadow of the building = 24 m
From the figure,
∠A = ∠P
∠B = ∠Q
∴ △ABC ~ △PQR by A.A. similarity condition
Hence \(\frac{AB}{PQ}\) = \(\frac{BC}{QR}\)
[∵ Ratio of corresponding angles is equal]
\(\frac{4}{6}\) = \(\frac{x}{24}\)
x = \(\frac{24 \times 4}{6}\) = 16 m
∴ Height of the building = 16 m.

Question 8.
CD and GH are respectively the bisectors of ∠ACB and ∠EGF such that D and H lie on sides AB and FE of △ABC and △FEG respectively. If △ABC ~ △FEG then show that
i) \(\frac{CD}{GH}\) = \(\frac{AC}{FG}\)
ii) △DCB ~ △HGE
iii) △DCA ~ △HGF
Answer:
AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2 12
Given: △ABC ~ △FEG.
CD is the bisector of ∠C and GH is the bisector of ∠G.
R.T.P.:
i) \(\frac{CD}{GH}\) = \(\frac{AC}{FG}\)
In △ACD and △FGH
∠A = ∠F
[∵ Corresponding angles of △ABC and △FEG]
∠ACD = ∠FGH
[∵ ∠C = ∠G ⇒ \(\frac{1}{2}\)∠C = \(\frac{1}{2}\)∠G ⇒ ∠ACD = ∠FGH]
∴ By A.A. similarity condition, △ACD ~ △FGH
\(\frac{AC}{FG}\) = \(\frac{CD}{GH}\) = \(\frac{AD}{FH}\)
[∵ Ratio of the Corresponding angles is equal]
⇒ \(\frac{AC}{FG}\) = \(\frac{CD}{GH}\) [Q.E.D]

AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2

ii) △DCB ~ △HGE
In △DCB and △HGE,
∠B = ∠E
[∵ Corresponding angles of △ABC and △FEG]
∠DCB = ∠HGE
[∵ ∠C = ∠G ⇒ \(\frac{1}{2}\)∠C = \(\frac{1}{2}\)∠G ⇒ ∠DCB = ∠HGE]
∴ △DCB ~ △HGE . (by A.A. similarity condition)

iii) △DCA ~ △HGF
In △DCA and △HGF
∠A = ∠F
\(\frac{1}{2}\)∠C = \(\frac{1}{2}\)∠G ⇒ ∠DCA = ∠HGF
[∵ Corresponding angles of the similar triangles]
∴ △DCA ~ △HGF
[ A.A. similarity condition]

Question 9.
AX and DY are altitudes of two similar triangles △ABC and △DEF. Prove that AX : DY = AB : DE.
Answer:
AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2 13
Given: △ABC ~ △DEF.
AX ⊥ BC and DY ⊥ EF.
R.T.P.: AX : DY = AB : DE.
Proof: In △ABX and △DEY ∠B = ∠E [∵ Corresponding angles of △ABC and △DEF]
∠AXB = ∠DYE [given]
∴ △ABX ~ △DEY
(by A.A. similarity condition)
Hence \(\frac{AB}{DE}\) = \(\frac{BX}{EY}\) = \(\frac{AX}{DY}\)
[∵ Ratios of corresponding sides of similar triangles are equal]
⇒ AX : DY = AB : DE [Q.E.D.]

Question 10.
Construct a triangle shadow similar to the given △ABC, with its sides equal to \(\frac{5}{3}\) of the corresponding sides of the triangle ABC.
Answer:
AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2 14
Steps of construction :

  1. Draw a △ABC with certain measures.
  2. Draw a ray \(\overrightarrow{\mathrm{BX}}\) making an acute angle with BC on the side opposite to vertex A.
  3. Locate 8 points (B1, B2, …., B8) on \(\overrightarrow{\mathrm{BX}}\) such that BB1 = B1B2 = B2B3 = B3B4 = B4B5 = B5B6 = B6B7 = B7B8.
  4. Join B5, C.
  5. Draw a line parallel to B5C through which it intersects BC extended at C’.
  6. Draw a line parallel to AC through ‘C’ which meets \(\overrightarrow{\mathrm{BA}}\) produced at A’.
  7. △A’BC’ is the required triangle.

AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2

Question 11.
Construct a triangle of sides 4 cm, 5 cm and 6 cm. Then, construct a triangle similar to it,whose sides are 2/3 of the corresponding sides of the first triangle.
Answer:
AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2 15
Steps of construction:

  1. Draw △ABC with AB = 4 cm, BC = 5 cm and CA = 6 cm.
  2. Draw a ray BX making an acute angle with BC on the side opposite to vertex A.
  3. Mark three points B1, B2 and B3 on \(\overrightarrow{\mathrm{BX}}\) such that BB1 = B1B2 = B2B3.
  4. Join B3, C.
  5. Draw a line parallel to B3C through B2 meeting BC at C’.
  6. Draw a line parallel to BA through C’ meeting BA at A’.
  7. △A’BC’ is the required triangle.

Question 12.
Construct an isosceles triangle whose base is 8 cm and altitude is 4 cm. Then, draw another triangle whose sides are 1\(\frac{1}{2}\) times the corresponding sides of the isosceles triangle.
Answer:
AP SSC 10th Class Maths Solutions Chapter 8 Similar Triangles Ex 8.2 16
Steps of construction:

  1. Draw AABC in which BC = 8 cm and altitude AD = 4 cm.
  2. Draw a ray BX making an acute angle with BC on the side opposite to vertex A.
  3. Mark three points B1, B2 and B3 such that BB1 = B1B2 = B2B3.
  4. Join B2C.
  5. Draw a line parallel to B2C through B3 meeting BC produced C’.
  6. Draw a line paral1e1 to AC through C’ meeting BA produced at A’.
  7. △A’BC’ is the required triangle.

 

AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3

AP State Board Syllabus AP SSC 10th Class Maths Textbook Solutions Chapter 14 Statistics Ex 14.3 Textbook Questions and Answers.

AP State Syllabus SSC 10th Class Maths Solutions 14th Lesson Statistics Exercise 14.3

10th Class Maths 14th Lesson Statistics Ex 14.3 Textbook Questions and Answers

Question 1.
The following frequency distribution gives the monthly consumption of electricity of 68 consumers of a locality. Find the median, mean and mode of the data and compare them.
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3 1
Answer:
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3 2

AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3
Sum of the frequencies = 68
∴ \(\frac{n}{2}\) = \(\frac{68}{2}\) = 34
Hence median class = 125 – 145
Lower boundary of the median class, l = 125
cf – cumulative frequency of the class preceding the median class = 22
f – frequency of the median class = 20
h = class size = 20
Median = \(l+\frac{\left[\frac{\mathrm{n}}{2}-\mathrm{cf}\right]}{\mathrm{f}} \times \mathrm{h}\)
= 125 + \(\frac{[34-22]}{20}\) × 20
∴ Median = 125 + 12 = 137
Maximum number of consumers lie in the class 125 – 145
Modal class is 125 -145
l – lower limit of the modal class =125
f1 – frequency of the modal class = 20
f0 – frequency of the class preceding the modal class =13
f2 – frequency of the class succeeding the modal class =14
h – size of the class = 20
Mode (Z) = \(l+\frac{f_{1}-f_{0}}{\left(f_{1}-f_{0}\right)+\left(f_{1}-f_{2}\right)} \times h\)
Mode (Z) = 125 + \(\frac{20-13}{(20-13)+(20-14)} \times 20\)
= 125 + \(\frac{7}{7+6}\) × 20
= 125 + \(\frac{140}{13}\)
= 125 + 10.76923
∴ Mode = 135.769
Mean \(\overline{\mathrm{x}}=\mathrm{a}+\frac{\Sigma \mathrm{f}_{\mathrm{i}} \mathrm{u}_{\mathrm{i}}}{\Sigma \mathrm{f}_{\mathrm{i}}} \times \mathrm{h}\)
a = assumed mean = 135
∴ \(\overline{\mathbf{x}}\) = 135 + \(\frac{7}{68}\)
= 135 + 0.102941
≃ 135.1
Mean, Median and Mode are approximately same in this case.

AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3

Question 2.
If the median of 60 observations, given below is 28.5, find the values of x and y.
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3 3
Answer:
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3 4
Median = \(l+\frac{\left[\frac{\mathrm{n}}{2}-\mathrm{cf}\right]}{\mathrm{f}} \times \mathrm{h}\)
It is given that ∑f = n = 60
So, 45 + x + y = 60
x + y = 60 – 45 = 15
x + y = 15 ….. (1)
The median is 28.5 which lies be-tween 20 and 30.
Median class = 20 – 30
Lower boundary of the median class ‘l’ = 20
\(\frac{N}{2}\) = \(\frac{60}{2}\) = 30
cf – cumulative frequency = 5 + x
h = 10
Median = \(l+\frac{\left[\frac{\mathrm{n}}{2}-\mathrm{cf}\right]}{\mathrm{f}} \times \mathrm{h}\)
⇒ 28.5 = 20 + \(\frac{30-5-x}{20}\) × 10
⇒ 28.5 = 20 + \(\frac{25-x}{2}\)
\(\frac{25-x}{2}\) = 28.5 – 20 = 8.5
25 – x = 2 × 8.5
x = 25- 17 = 8
also from (1); x + y = 15
8 + y = 15
y = 7
∴ x = 8; y = 7.

AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3

Question 3.
A life insurance agent found the following data about distribution of ages of 100 policy holders. Calculate the median age. [Policies are given only to persons having age 18 years onwards but less than 60 years.
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3 5
Answer:
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3 6
The given distribution being of the less than type, 25, 30, 35, give the upper limits of corresponding class intervals. So the classes should be 20 – 25, 25 – 30, 30 – 35, ………. 55 – 60.
Observe that from the given distribution 2 persons with age less than 20.
i.e., frequency of the class below 20 is 2.
Now there are 6 persons with age less than 25 and 2 persons with age less than 20.
∴ The number of persons with age in the interval 20 – 25 is 6 – 2 = 4.
Similarly, the frequencies can be calculated as shown in table.
Number of observations = 100
n = 100
\(\frac{n}{2}\) = \(\frac{100}{2}\) = 50, which lies in the class 35-40
∴ 35 – 40 is the median class and lower boundary l = 35
cf = 45;
h = 5;
f = 33
Median = \(l+\frac{\left[\frac{\mathrm{n}}{2}-\mathrm{cf}\right]}{\mathrm{f}} \times \mathrm{h}\)
= 35 + \(\frac{50-45}{33}\) × 5
= 35 + \(\frac{5}{33}\) × 5
= 35 + 0.7575
= 35.7575
∴ Median ≃ 35.76

AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3

Question 4.
The lengths of 40 leaves of a plant are measured correct to the nearest millimetre, and the data obtained is represented in the following table:
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3 7
Find the median length of the leaves. (Hint: The data needs to be converted to continuous classes for finding the median, since the formula assumes continuous classes. The classes then change to 117.5 – 126.5, 126.5 – 135.5,…, 171.5 – 180.5.)
Answer:
Since the formula, Median = \(l+\frac{\left[\frac{\mathrm{n}}{2}-\mathrm{cf}\right]}{\mathrm{f}} \times \mathrm{h}\) assumes continuous classes assumes continuous class, the data needs to be converted to continuous classes.
The classes then changes to 117.5 – 126.5; 126.5 – 133.5, …… 171.5 – 180.5.
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3 8
∑fi = n = 40
\(\frac{n}{2}\) = \(\frac{40}{2}\) = 20
\(\frac{n}{2}\)th observation lie in the class 144.5- 153.5
∴ Median class = 144.5 – 153.5
Lower boundary, l = 144.5
Frequency of the median class, f = 12
c.f. = 17
h = 9
∴ Median = \(l+\frac{\left[\frac{\mathrm{n}}{2}-\mathrm{cf}\right]}{\mathrm{f}} \times \mathrm{h}\)
= 144.5 + \(\frac{20-17}{12}\) × 9
= 144.5 + \(\frac{3}{12}\) × 9
= 144.5 + \(\frac{9}{4}\)
= 144.5 + 2.25
∴ Median length = 146.75 mm.

AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3

Question 5.
The following table gives the distribution of the life-time of 400 neon lamps.
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3 9
Find the median life-time of a lamp.
Answer:
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3 10
Total observations are n = 400
\(\frac{n}{2}\)th observation i.e \(\frac{400}{2}\) = 200
200 lies in the class 3000 – 3500
∴ Median class = 3000 – 3500
Lower boundary l = 3000
frequency of the median class f = 86
c.f = 130
Class size, h = 500
Median = \(l+\frac{\left[\frac{\mathrm{n}}{2}-\mathrm{cf}\right]}{\mathrm{f}} \times \mathrm{h}\)
= 3000 + \(\frac{200-130}{86}\) × 500
= 3000 + \(\frac{70}{86}\) × 500
= 3000 + 406.977
= 3406.98
∴ Median life ≃ 3406.98 hours

AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3

Question 6.
100 surnames were randomly picked up from a local telephone directory and the frequency distribution of the number of letters in the English alphabet in the surnames was obtained as follows.
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3 11
Determine the median number of letters in the surnames. Find the mean number of letters in the surnames ? Also, find the modal size of the surnames.
Answer:
Number of letters in the surnames.
Also find the modal size of the surnames.
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3 12
Total observations are n = 100
\(\frac{n}{2}\) = \(\frac{100}{2}\) = 50
50 lies in the class 7 – 10
∴ Median class = 7 – 10
l – lower boundary = 7
f – frequency of the median class = 40
cf = 36
Class size h = 3
Median:
Median = \(l+\frac{\left[\frac{\mathrm{n}}{2}-\mathrm{cf}\right]}{\mathrm{f}} \times \mathrm{h}\)
= 7 + \(\frac{50-36}{40}\) × 3
= 7 + \(\frac{14}{40}\) × 3
= 7 + \(\frac{42}{40}\)
= 7 + 1.05
= 8.05
∴ Median = 8.05.

Mean:
Assumed mean, a = 8.5
Mean \(\overline{\mathrm{x}}=\mathrm{a}+\frac{\Sigma \mathrm{f}_{\mathrm{i}} \mathrm{d}_{\mathrm{i}}}{\Sigma \mathrm{f}_{\mathrm{i}}}\)
= 8.5 + \(\frac{(-18)}{100}\)
= 8.5 – 0.18
= 8.32
∴ Mean = 8.32.

Mode:
Maximum number of surnames = 40
∴ Modal class = 7-10
l – lower boundary of the modal class = 7
Mode (Z) = \(l+\frac{f_{1}-f_{0}}{\left(f_{1}-f_{0}\right)+\left(f_{1}-f_{2}\right)} \times h\)
l = 7; f1 = 40, f0 = 30, f2 = 16, h = 3
Mode (Z) = 7 + \(\frac{40-30}{(40-30)+(40-16)}\) × 3
= 7 + \(\frac{10}{10+24}\) × 3
= 7 + \(\frac{30}{34}\)
= 7 + 0.882
= 7.882

Median = 8.0.5; Mean = 8.32; Modal size = 7.88.

AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3

Question 7.
The distribution below gives the weights of 30 students of a class. Find the median weight of the students.
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3 13
Answer:
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.3 14
Number of observations (n) = ∑fi
\(\frac{n}{2}\) = \(\frac{30}{2}\) = 15
15 lies in the class 50 – 55
∴ Median class = 50-55
l – lower boundary of the median class = 55
f – frequency of the median class = 8
c.f = 5
Class size h = 6
Median = \(l+\frac{\left[\frac{\mathrm{n}}{2}-\mathrm{cf}\right]}{\mathrm{f}} \times \mathrm{h}\)
= 50 + \(\frac{15-5}{8}\) × 6
= 50 + 7.5
= 57.5
= 50 + 7.5 = 57.5
∴ Median weight = 57.5 kg.

AP SSC 10th Class Physics Important Questions Chapter 1 Heat

AP State Board Syllabus AP SSC 10th Class Physical Science Important Questions Chapter 1 Heat.

AP State Syllabus SSC 10th Class Physics Important Questions 1st Lesson Heat

10th Class Physics 1st Lesson Heat 1 Mark Important Questions and Answers

Question 1.
What is humidity? (AP March 2015)
Answer:
Humidity :
The amount of water vapour present in air is called humidity.

Question 2.
Define latent heat of Fusion. (AP Morch 2016)
Answer:
Latent heat of Fusion :
At constant temperature, the heat energy required to convert one gram of solid completely into liquid is called latent heat of Fusion.

AP SSC 10th Class Physics Important Questions Chapter 1 Heat

Question 3.
While drinking water, Rama spilled some water on the floor. After some time, the water disappeared from the floor. What happened to the water? (TS June 2015)
Answer:

  • The water disappeared due to evaporation because we know that as the surface area increases rate of evaporation also increases.
  • So water molecules escape from the floor to air.

Question 4.
Give an example to explain that evaporation is a cooling process. (TS March 2016)
Answer:
The examples to explain that evaporation is a cooling process are

  1. Drying of wet clothes
  2. When the floor is washed with water, the water on the floor disappears.
  3. Sweating, etc.

Question 5.
Let heat is not lost by any other process between two objects in thermal contact, “Net heat lost (by hot body) = Net heat gain (by cold body).” above statement indicates a principle. Write the name of that principle. (AP March 2019)
Answer:
Principle of method of mixtures.

Question 6.
Convert 25°C into Kelvin scale. (AP SCERT: 2019-20)
Answer:
25°C = (273 + 25) K = 298 K

Question 7.
Given a beaker with water, a thermometer and a stand, draw the arrangement of an experiment to measure boiling point of water. (AP SA-1:2019-20)
Answer:
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 1

Question 8.
Define heat.
Answer:
Heat: Heat is a form of energy which is transferred from one body to the other body due to the difference in their temperature.

Question 9.
What is meant by thermal equilibrium?
Answer:
Thermal Equilibrium :
Two bodies are at the same temperature then they are said to be in thermal equilibrium.

AP SSC 10th Class Physics Important Questions Chapter 1 Heat

Question 10.
Define dew.
Answer:
Dew :
The water droplets condensed on surface are known as dew.

Question 11.
What is boiling?
Answer:
Boiling is a process in which the substance changes from liquid to gas.

Question 12.
What is melting?
Answer:
Melting :
The process in which the substance changes from solid to liquid state is called melting.

Question 13.
What are the different energies possessed by system (body or material)?
Answer:

  1. Linear kinetic energy
  2. Rotational kinetic energy
  3. Vibrational energy
  4. Potential energy and Internal energy (I.E).

Question 14.
Why does samosa seem to be cool but hot when we eat?
Answer:
Because the curry inside samosa contains ingredients with higher specific heats.

Question 15.
On which factors does rate of evaporation depend?
Answer:

  1. Surface area
  2. temperature
  3. the amount of vapour already present in the surrounding air.

Question 16.
What is the value of latent heat of vapourization of water?
Answer:
Latent heat of vapourization of water = 540 cal/gm. (or) 2.26 × 106 J/kg

Question 17.
What is the value of latent heat of fusion of ice?
Answer:
Latent heat of fusion of ice is 80 cal/gm. (or) 3.26 × 105 J/kg

Question 18.
Give some liquids which solidify (convert into solid) in winter season.
Answer:
Coconut oil, ghee are some liquids which solidify in winter season.

Question 19.
What is freezing?
Answer:
Freezing :
The process in which the substance changes from liquid to solid state by losing some energy from it is called freezing.

AP SSC 10th Class Physics Important Questions Chapter 1 Heat

Question 20.
Which will have lower temperature when we take out a wooden piece and a metal piece from a fridge?
Answer:
The metal piece will have lower temperature as compared to the wooden piece when they are taken out of the fridge.

Question 21.
When do you say there is thermal equilibrium between two bodies?
Answer:
It is said that there is thermal equilibrium between two bodies when there is no transfer of heat energy between them.
(OR)
When temperature between two bodies is same it is said that there is thermal. equilibrium between them.

Question 22.
What is absolute temperature?
Answer:
Temperature measured in Kelvin scale is called absolute temperature.

Question 23.
What is latent heat of vapourisation?
Answer:
At constant temperature the heat energy required to change one gram of liquid into gaseous state.

Question 24.
What is boiling point?
Answer:
The temperature at which the substance changes from liquid to gaseous state at the fixed temperature is called boiling point.

Question 25.
What is melting point?
Answer:
Melting point :
The temperature at which the substance changes from solid to liquid state at constant temperature is called melting point.

Question 26.
How is aquatic animal able to live at poles?
Answer:
The ice has less density compared to water. So it forms a layer on the top of water which prevents the solidification of water.

Question 27.
What are the phases of water present at 0° C?
Answer:
Two phases namely, ice and water.

Question 28.
What happens if external pressure of liquid increases?
Answer:
The boiling point of the liquid will increase.

Question 29.
Does ice melt below 0° C?
Answer:
Yes, if the external pressure increases it melts at low temperature.

AP SSC 10th Class Physics Important Questions Chapter 1 Heat

Question 30.
What happens when two objects of same temperature are in contact with each other?
Answer:
Heat does not flow between two objectives.

Question 31.
What is the principle involved in pressure cooker?
Answer:
Boiling point of liquid increases with external pressure.

Question 32.
What happens to kinetic energy of particles if we increase the temperature?
Answer:
Kinetic energy of particles increases with increase of temperature.

Question 33.
Why does transfer of heat energy take place between systems?
Answer:
When heat energy gives to the system, internal energy increases. Similarly, internal energy decreases when heat energy flows out of the system.

Question 34.
What is internal energy?
Answer:
Internal energy :
It is the energy possessed by the system by virtue of its molecular motion and molecular configuration. It is a stored energy. It depends on the temperature of the system.

Question 35.
What is transit energy?
Answer:
Transit energy:
Energy possessed by a system which can cross its boundary is called transit energy. Heat and work are transit energies.

Question 36.
Where does air get? vapour from?
Answer:
The vapour may come from evaporation of water from the surfaces of rivers, lakes, ponds, and from the drying of wet clothes, sweat, and so on.

Question 37.
Why do pigs toil in the mud during hot summer days?
Answer:
They do not have sweat glands for evaporation process. So pigs toil in the mud.

Question 38.
Why is it easy to cook food in a pressure cooker?
Answer:
We know as the atmospheric pressure increases the boiling point of water increases. So we can increase the boiling point of water to 120°C in a pressure cooker. So it is \ easy to cook in a pressure cooker.

AP SSC 10th Class Physics Important Questions Chapter 1 Heat

Question 39.
Why is water used as coolant?
Answer:
Water has the highest specific heat. So it takes lot of time to become hot. So it is used as coolant.

Question 40.
How is fog formed?
Answer:
The water molecules present in vapour condense on the dust particles in air and form small droplets of water which form a thick mist called fog.

Question 41.
Equal amounts of water is kept in a cup and in a disc. Which will evaporate faster? Why?
Answer:
The water present disc evaporates faster because of greater surface area.

Question 42.
Explain why dogs pant during hot summer days using the concept of evaporation.
Answer:
Dog does not have pores on its body. The only place where a dog can sweat is on its foot pads and the rest of the body is covered in a fur coat. So it cannot sweat; that’s why dogs pant to keep cool themselves.

Question 43.
Same amount of heat is supplied to two liquids A and B. The liquid A shows a greater rise in temperature. What can you say about the specific heat of A?
Answer:
The specific heat of A is less than that of B because rise in temperature is inversely proportional to temperature.

Question 44.
What is the specific heat of-water at boiling point?
Answer:

  1. Generally, the specific heat of water is 1. (or) 4.187 KJ / Kg K
  2. Specific heat of water at 100° C = 4.219 KJ / KgK

Question 45.
What is the equation of heat energy when change the state?
Answer:
Q = mL
Where m = mass of body, L = latent heat.

Question 46.
Convert 212°F into Kelvin scale.
Answer:
212°F= 100°C. So 100 + 273 = 373 K.

Question 47.
Convert 310 K into centigrade system.
Answer:
310-273 = 37°C.

AP SSC 10th Class Physics Important Questions Chapter 1 Heat

Question 48.
Are the processes of evaporation and boiling the same?
Answer:
No. Evaporation takes place at any temperature, while boiling occurs at a definite temperature called the boiling point.

Question 49.
Define latent heat of vaporization?
Answer:
The heat energy required to change one unit mass of liquid to gas at constant temperature is called latent heat of vaporization.
\(L=\frac{Q}{m}\)
The value of latent heat of vapourization of water is 540 cal/gm.

Question 50.
What is meant by internal energy?
Answer:
Combination of linear kinetic energy, rotational kinetic energy, vibrational energy, and potential energy of molecules is known as internal energy of the system.

Question 51.
Write the formula for resultant temperatures of a mixture, when V1 ml of water at T1°C is mixed with V2 ml of water at T2° C.
Answer:
Resultant temperature \(T=\frac{V_{1} T_{1}+V_{2} T_{2}}{V_{1}+V_{2}}\)

Question 52.
Write the equation of heat energy when change the temperature.
Q = mS∆T
m == mass, S = specific heat, AT = change in temperature

Question 53.
The figure shows change in state of ice from – 5°C to 110°C with temperature. What are the melting and vaporization curves?
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 2
Answer:
BC = melting
DE = vaporization curve.

Question 54.
Write principle of method of mixtures.
Answer:
When two or more bodies are brought into thermal contact, then heat lost by hot body is equal to heat gain by cold body. Until they attain thermal equilibrium.

Question 55.
Evaporation is a cooling process. Why?
Answer:
During evaporation process, the energy of the molecules inside the liquid decreases and they slow down.

AP SSC 10th Class Physics Important Questions Chapter 1 Heat

Question 56.
Which factors are influence the rate of evaporation of a liquid?
Answer:
Rate of evaporation of a liquid depends on surface area, temperature, pressure, and amount of vapour present in surrounding air.

Question 57.
What is meant by fog?
Answer:
The droplets keep floating in the air and form a thick mist which restricts visibility. This thick mist is called fog.

Question 58.
Why do we sweat while doing a work?
Answer:
When we work our body produces heat. As a result, the temperature of the skin becomes higher and the water in the sweat glands starts evaporating. This evaporation cools the body.

Question 59.
A samosa appears to be cool when touched outside but it is hot when we eat it. Why?
Answer:
A samosa appears to be cool outside but it is hot when we eat it because the curry inside the samosa contain ingredients with higher specific heats. Hence they remain hot for a long time.

Question 60.
Equal amounts of water are kept in a cup and in a dish. Which will evaporates faster? Why?
Answer:
Dish evaporates faster, because dish has large surface area. Evaporation of liquids depends on surface area.

Question 61.
Why water is used as coolant in the cooling system of automobile engines?
Answer:
Due to high specific heat, water absorbs large amount of heat and temperature does not rise quickly. So water used as coolant in cooling system of automobile engines.

Question 62.
Why do pigs toil around in the mud?
Answer:
Pigs do not have sweat glands. Water in the mud evaporates and helps the pig to be cool from heat. So pigs toil in the mud during summer.

AP SSC 10th Class Physics Important Questions Chapter 1 Heat

Question 63.
Take small glass bottle with a tight lid. Fill it with water completely without any gaps and fix the lid tightly in such a way that water should not come out of it. Put the bottle into the deep freezer for a few hours. Take it out from the fridge. You observe the glass bottle is broken. Why?
Answer:
We know, the volume of the water poured into the glass bottle is equal to the volume of the bottle. When the water freezes to ice, the bottle is broken. Because the volume of the ice is greater than the volume of the water filled in bottle.

Question 64.
From the given figure, in which the thermometer mercury level is increases and decreases?
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 3
Answer:
Thermometer A(in oil) is increases.
Thermometer B(water) is decreases.

Question 65.
What are the materials are used in to find the specific heat of solid?
Answer:
Calorimeter, thermometer, stirrer, water steam heater, wooden box, and lead shots.

Question 66.
What is the value of following temperatures in Kelvin scale?
(a) 30° C b) 70° C
Answer:
a) 30° C = 30 + 273 = 303 K
b) 70° C = 70 + 273 = 343 K

Question 67.
How much heat energy is required to raise the temperature of unit mass of material by 1° C?
Answer:
1 cal/g – °C = lk cal / kg – K = 4.2 x J/kg – K = 4.2 kJ/kg – K.

Question 68.
How much energy is required to turn 1 g of ice of 0°C into 1 gm of water at 0°C?
Answer:
The energy required to convert 1 g of ice at 0°C into lg of water at 0°C is latent heat of fusion that is 80 cal/g.

Question 69.
What is the temperature of mixture if 10 g of steam at 100°C is mixed with 50 g of ice at 0°C?
Answer:
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 4

Question 70.
Boiling water at 100°C and cold water at t°C are mixed in the ratio of 3 : 5 and the resultant temperature is 40°C. Find the value of t.
Answer:
Suppose the quantities of water is 3x and 5x.
Given that
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 5

Question 71.
What amount of ice can be melted by 4000 cal of heat?
Answer:
Latent heat of fusion of ice Lf = 80 cal/g
Given that Q = 4000 cal
Q = mLf ⇒ 4000 = m × 80
∴ m = \(\frac{4000}{80}\) = 50 g

Question 72.
5 gm of ice is at (J°C. It is converted into water at same temperature. How much heat energy is required?
Answer:
In change the state Q = mL
m = 5 gm, L = Latent heat of fusion = 80 Cal/gm
Q = mL = 5 × 80 = 400 cal.

AP SSC 10th Class Physics Important Questions Chapter 1 Heat

Question 73.
What would be the final temperature of mixture 50 g. of water at 20°C and 50 gm of water at 40°C?
Answer:
If masses are equal, then resultant temperature of mixture = \(\frac{\mathrm{T}_{1}+\mathrm{T}_{2}}{2}\)
∴ T = \(\frac{20+40}{2}\) ⇒ T =30

10th Class Physics 1st Lesson Heat 2 Marks Important Questions and Answers

Question 1.
Observe the following table regarding the values of specific heat of substances and answer the following questions : (AP SA-I: 2018-19)
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 6
i) Which material is suitable as the base of the cooking vessel?
Answer:
Copper. Because, it has low specific heat value.

ii) Why do we prefer water as a coolant?
Answer:
Due to high specific heat value of water, it can take more time to heat itself and acts as a coolent.

Question 2.
Why do water drops (dew) form on flowers and grass during morning hours of winter season? (AP March 2016)
Answer:
During winter nights, the atmospheric temperature goes down. The flowers, grass, etc. become still colder. The air near them becomes saturated with vapour and condensation begins. The water droplets condensed on such surfaces are known as dew.

Question 3.
Temperatures of two cities at different times are given as follows : (AP March 2019)
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 7
On the basis of above table, answer the following questions.
1) In which city, the morning temperature at 6 O’clock is relatively high?
Answer:
In ‘B’ city, the morning temperature at 6 O’clock is relatively high.

2) At what time, both cities are having the equal temperature?
Answer:
At 11 : 30 AM, both cities are having the equal temperature.

Question 4.
A student took the same quantity of water and petrol in two different tumblers. He kept them on a table. When observed after a day there was water in a glass but petrol was completely evaporated. Give reasons why water was not evaporated completely but petrol was completely evaporated.
Answer:
Petrol has a lower vapour point than water. And evaporation depends on the nature of the liquid so petrol evaporates quickly than water at room temperature.

AP SSC 10th Class Physics Important Questions Chapter 1 Heat

Question 5.
What are the differences between dew and fog?
Answer:

Dew Fog
1) Dew is the droplets that appear on the exposed objects in the morning or evening. 1) Fog is nothing but cloud on ground.
2) Dew does not effect visibility. 2) Due to fog visibility is greatly effected.
3) Dew is formed when relative humidity higher than temperature. 3) Fog is formed when island area is warmer than the ocean or large body of water.

Question 6.
Why is spirit evaporated in petri dish quickly under a fan when compared to that kept in closed room?
Answer:

  • The blowing air increases the rate of evaporation.
  • This is because any molecule escaping from the surface is blown away from the vicinity of the liquid.
  • This increases the rate of evaporation.
  • This is the reason why the spirit in petri dish evaporates quickly when compared to that kept in closed room.

Question 7.
Does the temperature of water rise continuously if heat is supplied continuously?
Answer:
Yes. If heat is supplied to water its temperature rises continuously till it reaches 100°C. At 100°C there would be no further rise of temperature, because the heat is sterilized to convert water to water vapour. So if heat is supplied beyond 100°C, all the water is converted into vapour.

Question 8.
Why does the mercury level of thermometer rise up when it is placed in hot water and fall down when it is placed in cold water?
Answer:

  • We know that bodies which are in contact achieve thermal equilibrium due to transfer of heat energy.
  • If we keep thermometer in hot water, its mercury level rises because heat is transformed from hot body to cold body.
  • Similarly, we observe that mercury level comes down when it is placed in cold water.

Question 9.
When we place thermometer in hot water, there is a rise in mercury level, thereafter it stops. What is the reason for steadiness of mercury level? What does reading of thermometer give at that time?
Answer:

  • The steadiness of the mercury column of the thermometer indicates that, flow of heat between the thermometer liquid (mercury) and water has stopped and thermal equilibrium has been attained between the water and thermometer liquid.
  • The reading of thermometer gives thermal equilibrium state that is temperature.

AP SSC 10th Class Physics Important Questions Chapter 1 Heat

Question 10.
What is the relationship between temperature and kinetic energy?
Answer:

  • The average kinetic energy of molecules/particles of the hotter body is more than the colder body.
  • So we can say that the temperature of a body is an indicator of the average kinetic energy of molecule of that body.
  • So the average kinetic energy of molecules is directly proportional to the absolute temperature. [KE<sub>avg</sub> ∝ T]

Question 11.
What is the relationship between rise in temperature and specific heat of material?
Answer:

  • Temperature depends on nature of the material, hence the specific heat depends on its nature.
  • If the specific heat, is high, the rise in temperature is low. [Q = mSΔt]
  • It gives us an idea of degree of reluctance of a material to rise in temperature.

Question 12.
What is the principle of method of mixtures?
Answer:
When two or more bodies at different temperatures are mixed with each other, then net heat lost by the hot bodies, is equal to net heat gained by the cold bodies until they attain thermal equilibrium or equal temperature.

Net heat lost = Net heat gained

This is known as principle of method of mixtures.

Question 13.
Why is evaporation of a liquid faster under a fan?
Answer:

  • If air is blown over the liquid surface in an open petri dish, a number of molecules evaporate from the surface of liquid.
  • Because any molecule escaping from the surface is blown away from the vicinity of liquid.
  • This increases the rate of evaporation.
  • So evaporation of a liquid is faster under a fan.

Question 14.
Why do we get dew on the surface of a cold soft drink bottle kept in open air?
Answer:

  • The temperature of surrounding air is higher than the temperature of cold soft drink.
  • Air contains water molecules in the form of water vapour which tend to condense by losing their kinetic energy to form water droplets.

Question 15.
Why does water take more time to become hot and take more time to become cool?
Answer:
Water has the highest specific heat among all liquids. So it takes more time to become hot and takes more time to become cool.

AP SSC 10th Class Physics Important Questions Chapter 1 Heat

Question 16.
What is calorimeter? Name the material of which it is made of. Give two reasons for using the material stated by you.
Answer:

  • The vessel used for measurement of heat is calorimeter.
  • It is made of thin sheet of copper.
  • The reason is that the specific heat of copper is low and by making the vessel thin, its thermal capacity becomes low so that it takes a negligible amount of heat from its contents to attain the temperature of contents.

Question 17.
Why are burns caused by steam at 100°C more painful than that of water at 100°C?
Answer:

  • Water at 100°C takes additional heat energy to convert from liquid state to vapour (steam) state. This energy is called latent heat of vapourisation.
  • Hence, steam at 100°C contains more heat energy than that of water at 100°C.
  • So, burns caused by steam at 100°C are more painful than that of water at 100°C.

Question 18.
Why is cooking fast in a pressure cooker compared to open vessel?
Answer:

  • Boiling point of liquid increases with external pressure.
  • Pressure cooker gives external pressure to the water in it.
  • So, while cooking in pressure cooker it increases boiling point of water more than 100°C.
  • So that, cooking is fast in pressure cooker compared to open vessel.

Question 19.
What happens to the water when wet clothes dry?
Answer:
When wet clothes dry, the water molecules from wet clothes, after evaporation, change into water vapour and mix with water molecules present in surrounding air, in the form of water vapour.

Question 20.
Why do we use hot water bottles for fomentation?
Answer:
The reason is that water does not cool quickly due to its large specific heat, so hot water bottle provides heat energy for fomentation for a long time.

Question 21.
Why do all plants and animals have a high content of water in their bodies?
Answer:
All plants and animals have nearly 80% to 90% of water in their bodies. So it helps in maintaining the body temperature in all seasons due to high specific heat.

Question 22.
Water is used as an effective coolant. Give reason.
Answer:
1) Water is used as an effective coolant because by allowing water to flow in pipes around the heated parts of machine, heat energy from such parts is removed (e.g. radiators in car and generator are filled with water).
2) Water in pipes extracts more heat from surroundings without much rise in its temperature because of its large specific heat.

Question 23.
Why is the base of cooking pan made thick?
Answer:

  • By making the base of cooking pan thick, its thermal capacity becomes large and it imparts sufficient heat energy at a lower temperature to the food for its proper cooking.
  • Further, it keeps the food warm for a long time, after cooking.

Question 24.
Water in lakes and ponds in cold countries does not freeze all at once. Give reason.
Answer:

  • The latent heat of fusion of ice is sufficiently high.
  • So to freeze water, a large quantity of heat has to be withdrawn, hence it freezes slowly and thus keeps the surroundings moderate.

AP SSC 10th Class Physics Important Questions Chapter 1 Heat

Question 25.
Why do drinks get more quickly cooled by adding pieces of ice at 0°C than ice-cold water at 0°C?
Answer:

  • This is because 1 g of ice at 0°C takes 336 J of heat energy from the drink to melt into water at 0°C.
  • Thus drink loses an additional 336 J of heat energy for 1 g of ice at 0°C than for 1 g ice cold water at 0°C. Therefore cooling produced by 1 g of ice at 0°C is more than that by 1 g of water at 0°C.

Question 26.
When ice in a frozen lake starts melting, its surroundings become very cold? Why?
Answer:
The reason is that the heat energy required for melting the frozen lake is absorbed from the surrounding atmosphere. As a result, the temperature of surroundings falls and it becomes very cold.

Question 27.
Why is it more cold after the hail-storm than during or before the hail-storm?
Answer:
The reason is that after the hail-storm, the ice absorbs the heat energy required for melting from the surroundings, so the temperature of the surroundings falls further down and we feel more cold.

Question 28.
Which of the substances A, B, and C has the least specific heat? The temperature versus time graph as shown below.
Answer:
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 8
The substance ‘A’ has least specific heat because the rise in temperature is more for substance. We know that specific heat and rise in temperature are inversely proportional. So A has the least specific heat.

Question 29.
Why do we need pressure cooker to cook food at higher altitudes?
Answer:

  • At higher altitudes, such as hills and mountains, atmospheric pressure is low, therefore water boils at a temperature lower than 100°C and so it does not provide the required heat energy for cooking.
  • Thus cooking there becomes very difficult and it takes a much longer time.
  • So we require a pressure cooker to cook the food at a faster rate.

Question 30.
Lalitha wants to determine the specific heat of Aluminium shots. What apparatus of material is required to do this experiment?
Answer:
The apparatus required is calorie meter, thermometer, stirrer, water, steam heater, wooden box, and aluminium shots.

AP SSC 10th Class Physics Important Questions Chapter 1 Heat

Question 31.
What are the material required in order to find specific heat of soild?
Answer:
Calorimeter, thermometer, stirrer, water, steam, heater, wooden box, and lead shots.

Question 32.
Your teacher made an experiment to show the formation of dew and frost. Explain how you show the formation of dew and frost.
Answer:
Place a water bottle in a deep fridge of refrigerator. After some time remove bottle from the refrigerator. We can observe ice in the bottle and water droplets are formed outside the bottle. This experiment is useful in formation of dew and frost.

Question 33.
Why a bottle completely filled with water and closed with a tight cap break after freezing?
Answer:

  • Density of ice is less than that of water.
  • This means water expands on freezing and converts into ice.
  • So, excess space is required to expand the water.
  • The bottle completely filled with water and closed with a tight cap has no excess space to expand water.
  • So, bottle breaks while freezing water in it.

Question 34.
Which of the following substances take more time to raise its temperature for a certain degree Celsius? Give reason.
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 9
Answer:
Water takes more time to raise temperature because it has greater specific heat is, i. e., 1 cal/g-°C. As the specific heat of substance increases, it takes more time to raise its temperature.

Question 35.
The graph shows variations of temperature (T) of one kilogram of material with the heat (H) supplied to it.
At ‘O’ the substance is in the solid state. From the graph can conclude that
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 10
i) The melting point of the solid is …………….
Answer:
The melting point of the solid is T1

ii) The latent heat of fusion is …………….
Answer:
The latent heat of fusion is (H2 – H1)

iii) The latent heat of vaporisation is …………….
Answer:
The latent heat of vaporisation is (H4 – H3)

iv) The boiling point of the substance is ……………
Answer:
The boiling point of the substance is T3

Question 36.
Which of the substances A, B, and C has the highest specific heat? The temperature versus time graph as shown given below.
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 11
Answer:

  • The substance ‘C’ has the highest specific heat.
  • Because ‘C’ does not rise its temperature quickly. In other words ‘C’ takes more time to rise its temperature.

Question 37.
Can the average kinetic energy of a body be even zero?
Answer:
The average kinetic energy of a body can be zero.
Reason :
K.E = \(\frac{1}{2}\) mv2
m is never zero
if v = 0; then body is not in the motion.

Question 38.
A slab of ice at -50°C is constantly heated till the steam attains a temperature of 150°C. Draw a graph showing the change in temperature with time. Label the various parts of the graph properly.
Answer:
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 12

Question 39.
Iron of weight 2 kg was supplied with 12000 calories of heat. Initial temperature of iron was 20°C. Its specific heat is 0.1 cal/g-°C. What is the final temperature of iron?
Answer:
Mass of iron (m) = 2 kg = 2 × 1000 g. = 2000 g.
Quantity of heat supplied (Q) = 12,000 cal.
Initial temperature = θ(i) = 20°C
Final temperature = θf = ?
Specific heat of iron (s) = 0.1 cal / g / °C.
Heat = Q = ms∆θ
Q = ms (θf – θi)
θf – θi = Q/ms
θf – 20 = \(\frac{12000}{2000 \times 0.1}=\frac{12}{2 \times 0.1}\) = 60
θf = 60 + 20 = 80°C
∴ The final temperature of iron = θf = 80°C

AP SSC 10th Class Physics Important Questions Chapter 1 Heat

Question 40.
What is the heat energy required to rise 20 kg of water from 25° C to 75° C?
Answer:
Given m = 20 kg = 20,000 gm
t1 = 25° C ; t2 = 75° C ;
S = 1 cal/gm °C.
Q = mS∆T = 20000 × 1 × (75 – 25) = 20000 × 50
Q = 1000000 calories

Question 41.
If you drink 200 ml of water at 20° C, what is the heat gained by water from your body? (Body temperature is 37° C)
Answer:
m = 200 g (1 ml of water = 1 gm of water)
S = 1 cal/gm °C ;
t1 = 20° C; t2 = 37° C
Q = mS∆T (∆T = t2 – t1)
= 200 × 1 × (37 – 20)
= 200 × 17
Q = 3400 calories

Question 42.
What would be the final temperature of a mixture of 60 gm of water at 30°C temperature and 60 gm of water at 60°C temperature?
Answer:
m1 = 60 g ;
T1 = 30°C ;
m2 = 60 g ;
T2 = 60°C
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 13

Question 43.
The quantity of heat which can rise the temperature of ‘x’ gram of a substance through t1°C and the quantity of heat which can rise the temperature of ‘y’ grams of water through t2°C is same. What is ratio of specific heats? What is ratio of specific heats if rise in temperatures are same and if amount of substances are same?
Answer:
Suppose specific heats of substance and water are s1 and s2 respectively.
Heat absorbed by x gram of substance to rise its temperature to t1°C.
Q1 = ms∆T = x × s1 × t1
Heat absorbed by y gram of water to rise its temperature to t2°C.
Q2 = ms∆T2 = y × s2 × t2
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 14

10th Class Physics 1st Lesson Heat 4 Marks Important Questions and Answers

Question 1.
Write the factors that effect the process of evaporation. Explain with suitable examples. (AP March 2017)
Answer:
Process of evaporation is effected by surface area, wind speed, humidity, and temperature.
Ex:

  • The water kept in a china dish evaporates faster than in a cup because of more surface area.
  • Water in wet the clothes are kept under fan evaporates faster than in normal conditions.
  • Water in wet clothes evaporates faster on a less humid day than on a more humid day.

Question 2.
A) Write the principle of method of Mixtures.
B) What would be the final temperature of a mixture of 60 gms of water at 50°C and 50 gms of water at 70°C? (AP March 2018)
Answer:
A) Principle of method of mixtures :
Net heat lost by the hot body = Net heat gain by the cold body.

B) m1 = 60 gms.,
T1 = 50°C ;
m2 = 50 gms.,
T2 = 70°C
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 15

Question 3.
Answer the following questions by using the data given in the table. (AP March 2018)

Substance Specific heat (cal / g°C)
Lead 0.031
Aluminium 0.21
Copper 0.095
Water 1.00
Iron 0.115

a) Write SI units for specific heat.
Answer:
Joule / Kilogram-Kelvin

b) Based on specific heat values, arrange the substances given in the table in ascending order.
Answer:
Lead, Copper, Iron, Aluminium, Water

c) If we supply same quantity of heat, which substance will heat up faster?
Answer:
Lead

d) Calculate the amount of heat required to raise the temperature of 1 kg of Iron through 10°C.
Answer:
Q = mS∆T = 1000 × 0.115 × 10 = 1150 cal.

AP SSC 10th Class Physics Important Questions Chapter 1 Heat

Question 4.
Suggest an experiment to show that when ice is converted into water, its temperature does not change. How much heat is required to convert 5 grams of ice at 0°C to water, at the same temperature? (Latent heat of fusion of ice is 80 cal/gram). (TS June 2015)
Answer:
Procedure :

  1. Take small ice cube in a beaker. Insert the thermometer in the beaker.
  2. Now start heating the beaker and note down readings of thermometer every one minute till the ice completely melts and gets converted into water.
  3. Before heating the temperature of ice is 0° C or less than 0° C.

Observation :

  1. We will observe that the temperature of ice at the beginning is equal to or below 0°C.
  2. If the temperature of ice is below 0°C, it goes on changing till it reaches 0° C.
  3. When ice starts melting, we will observe no change in temperature though you are supplying heat continuously.

Explanation :

  1. Given heat energy is used to break the bonds (H2O) in ice and melts.
  2. So, temperature is constant while melting.

Conclusion :

  1. This process is called melting. In this process heat converts solid phase to liquid phase.
  2. The temperature of the substance does not change until all the ice melts and converts into water.
  3. The heat given to melting is called latent heat of fusion.
  4. The heat required to convert 1 gm of solid completely to liquid at constant temperature is called “latent heat of fusion”.
    m = 5 gm; Lf = 80 cal/g

The amount of heat absorbed Q = MLf = 5 × 80 = 400 cal /g.

Question 5.
The graph shows the values of temperature, when ice is heated till it becomes water vapour. Observe the graph and answer the following questions. (TS March 2016)
(Note that the figure is not completely quantitative and also not to the scale. It is purely qualitative)
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 16
a) At what temperature, ice converts into water?
Answer:
Ice converts into water at 0°C and above.

b) What does \(\overline{\mathrm{DE}}\) represent?
Answer:
\(\overline{\mathrm{DE}}\) represents the latent heat of vapourisation.

c) What is the range of temperature of liquid water?
Answer:
The range of temperature of liquid water is 0°C to 100°C

d) Which part of the graph represents change of state from ice to water?
Answer:
\(\overline{\mathrm{BC}}\) represents the change of state of ice to water.

Question 6.
Write the differences between heat and temperature.
Answer:

Heat Temperature
1) It is a thermal energy. 1) It is the measurement of hotness or coldness.
2) Heat is an extensive property, means it does not depend on amount of the substance that is present. 2) Temperature is an intensive property means that the substance present will not change the specific characteristic.
3) Heat is the amount of energy of the system. 3) Temperature is the measure of the average molecular motions in a system.
4) Its S.I unit is Joules. 4) Its S.I. unit is degrees C or K.
5) Heat is energy itself that flows. 5) It decides the direction of heat flow.

Question 7.
Why is the specific heat different for different substances?
Answer:

  • We know that the temperature of a body is directly proportional to the average kinetic energy of particles of the body.
  • The molecules of the system have different forms of energies. The total energy of the system is called internal energy of the system.
  • When we supply heat energy to the system, the heat energy given to it will be shared by the molecules among the various forms of energy.
  • This sharing will vary from substance to substance.
  • The rise in temperature is high for a substance, if the maximum share of heat energy is utilised for its linear K.E.
  • This sharing of heat energy also varies with temperature. That is why the specific heat is different for different substances.

AP SSC 10th Class Physics Important Questions Chapter 1 Heat

Question 8.
Explain the process of evaporation.
Answer:

  • The molecules of a liquid that kept in a dish, continuously move with random speeds in various directions. As a result, these molecules collide with other molecules.
  • During this collision they transfer energy to other molecules. Hence, the molecules at the surface acquire energy and may fly off from the surface.
  • Some of these escaping molecules may be directed back into liquid when they collide with the particles of air.
  • If the number of escaping molecules is greater than the number returned, then the number of molecules in the liquid decreases.
  • Thus when a liquid is exposed to air, the molecules at the surface keep on escaping from the surface till the entire liquid disappears into air. This process is called evaporation.

Question 9.
Define evaporation. Explain what are the affecting factors of evaporation and how they effect the rate of evaporation.
Answer:
Evaporation :
The process of escaping of molecules from the surface of liquid at any temperature is called evaporation.

The affecting factors of evaporation :

  1. Temperature,
  2. Surface area,
  3. Wind speed,
  4. Humidity.

The affection on the rate of evaporation :
1) Temperature :
As the temperature increases evaporation increases.

2) Surface area :
As the surface area of liquid increases, more molecules tend to leave the surface. So rate of evaporation increases.

3) Wind speed :
As the wind speed increases rate of evaporation increases.

4) Humidity :
As the humidity increases rate of evaporation decreases.

Question 10.
Why is climate near the seashore moderate?
Answer:

  1. The specific heat of water is very high. It is about five times as that of sand.
  2. Hence the heat energy required for the same rise in temperature by certain mass pf water will be nearly five times than that required by same mass of sand.
  3. Similarly, a certain mass of water will give out nearly five times more heat energy than that given by sand of the same mass for the same fall in temperature.
  4. As such, sand (or earth) gets heated or cooled more rapidly as compared to water under similar conditions.
  5. Thus, a large difference in temperature is developed between the land and sea due to which land and sea breezes are formed.
  6. These breezes make the climate near seashore moderate.

Question 10.
Why do farmers fill their fields with water on a cold winter night?
Answer:

  • In the absence of water, if on a cold winter night, the atmospheric temperature falls below 0°C, the water in the fine capillaries of plants will freeze, so the veins will burst due to the increase in volume of water on freezing.
  • As a result, plants will die and the crop will be destroyed.
  • In order to save crop on such cold nights, farmers fill their field with water because water has high specific heat, so it does not allow the temperature in the plants of surrounding area to fall up to 0°C.

AP SSC 10th Class Physics Important Questions Chapter 1 Heat

Question 11.
Explain the factors effecting boiling.
Answer:
The factors effecting boiling are
I) Pressure :

  1. The boiling point of pure water at one atmospheric pressure is 100°C.
  2. Water boils at a temperature higher than 100°C, if the atmospheric pressure is higher than one atmosphere pressure, and boils at a temperature lower than 100°C, if the atmospheric pressure is less than 1 atmosphere.

II) Impurities :
The boiling point of liquid increases by the addition of impurities to it. If a little common salt is added to water, the water boils at a temperature higher than 100°C.

Question 12.
A, B and C are the three liquids at 20°C, 30°C and 40°C respectively. If equal masses of A and B are mixed, the resultant temperature is 26°C. If equal masses of A and C are mixed, the resultant temperature is 33°C. Find the ratio of specific heats of A, B and C.
Answer:
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 17
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 18
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 19

Question 13.
A refrigerator converts 5kg of water at 40°C into ice at 0°C in 20 minutes. Find the power of refrigerator.
Answer:
m = 5kg = 5000gr
∆t = 40°C – 0°C = 40°C
S = 1 (water) .
Q = m.s.∆t = 5000.1.40 = 200000 cal.
We know the relation between heat and work done as
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 20

Question 14.
Snow on mountains does not melt all at once. Why?
Answer:

  • Snow on mountains does not melt all at once because the ice has a high specific latent heat of fusion.
  • It is due to this fact that it changes into water slowly as it gets heat energy from the sun.
  • If latent heat would not have been so high, the snow would have melted quickly even with a small amount of heat energy and there would have been floods in rivers.

Question 15.
Collect specific heats of various substances.
Answer:

Substance Specific heat
In cal/g – °C In J/kg – K
Lead 0.031 130
Mercury 0.033 139
Brass 0.092 380
Zinc 0.093 391
Copper 0.095 399
Iron 0.115 483
Glass(flint) 0.12 504
Aluminium 0.21 882
Kerosene oil 0.50 2100
Ice 0.50 2100
Water 1 4180
Sea water 0.95 3900

Question 16.
The graph given below represents a cooling curve for a substance being cooled from a higher temperature to a lower temperature.
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 21
a) What is the boiling point of the substance?
Answer:
The boiling point of the substance is 150°C (because the part BC represents condensation where the vapour changes into the liquid without the change in temperature).

b) What happens in the region DE?
Answer:
The region DE represents freezing of the substance where the liquid changes into solid at a constant temperature that is 100°C.

c) What is the melting point of the substance?
Answer:
The melting point of substance is 100°C.

Question 17.
You’ve taken water in vessel at 0°C and closed it with a glass vessel as shown in the figure. You used and created a vacuum inside.
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 22
a) Explain what happens.
b) A part of water condenses; what is the amount of water that gest condensed?
Answer:
a) At 0°C also water is available in liquid state (generally at 0°C ice is also available) because the air in vacuum rise the temperature. Here evacuation is possible so it allows evaporation.

b) Let y ml of water is taken at 0°C.
’x’ ml of water is evaporated
Latent heat of vapourisation = Lsteam = 540 Cal/g.
Latent heat of ice = Lice = 80 Cal/g.
After sometime conversion process stops. So equilibrium is possible.
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 23

Question 18.
What are the applications of specific heat capacity?
Answer:
1. The oceans behave like heat store houses for the earth. They absorb large amounts of heat at the equator without rise in temperature due to high specific heat capacity of water. So, oceans moderate the surrounding temperature near the equator. Ocean water transports the heat away from the equator to areas closer to the north and south poles. This transported heat helps moderate the climates in parts of the Earth that are far from the equator.

2. Watermelon brought out from the refrigerator retains its coolness for a long time than any other fruit because it contains a large amount of water (water has greater specific heat).

3. The samosa seems to be cool outside but it is hot when we eat it because the curry inside the samosa contains ingredients with higher specific heats.

AP SSC 10th Class Physics Important Questions Chapter 1 Heat

Question 19.
Some hot water Is added to three times its mass of cold water at 10°C. The resulting temperature is found to be 20°C. Find the initial temperature of hot water.
Answer:
Let the initial temperature of hot water be t°C.
Mass of hot water = mg
Mass of cold water = 3 mg
Initial temperature of cold water = 10°C
And resultant temperature = 20°C
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 24
∴ Initial temperature of hot water = 50°C.

Question 20.
40 g of water at 60°C is poured into vessel of 200 g mass containing 50 g of water at 20°C. The final temperature of mixture is 30°C. Calculate the specific heat of vessel.
Answer:
Mass of hot water at 60°C = 40 g
Mass of cold water at 20°C = 50 g
Mass of vessel = 200 g
Suppose the specific heat of vessel is Sv
Heat energy given by hot water = mSw∆T
= 40 × 1 × (60 – 30) [∵ T1 = 60°C, T2 = 30°C]
= 40 × 30 = 1200 cal
Heat energy taken by cold water = mSw∆T
= 50 × 1 × (30 – 20) = 50 × 10 = 500 cal
Heat energy taken by vessel = mSv∆T = 200 × Sv × (30 – 20) = 2000 Sv
According to the principle of method of mixtures,
Heat lost by hot water = heat gained by cold water + heat gained by vessel 1200 = 500 + 2000 Sv
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 25

Question 21.
A, B and C are three liquids at 20°C, 30°C and 40°C respectively. If equal masses of A and B are mixed, the resultant temperature is 29°C. The equal masses of A and C are mixed, the resultant temperature is 33°C. Find the specific heats of A, B and C.
Answer:
Suppose specific heats of liquids A, B and C are s1, s2 and s3 respectively.
Given that the temperatures of liquids are 20°C, 30°C and 40°C.
Given that equal mass of A and B are mixed, the resultant temperature is 29°C.
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 26

Further given that equal masses of A and C are mixed, the resultant temperature is 33°C.
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 27

Question 22.
A refrigerator converts 5 kg of water at 40°C into ice at 0°C. Find the total energy released in Joules.
Answer:
m = 5 kg = 5000 g
The heat energy released to convert 5 kg of water at 40°C to 5 kg of water at 0°C.
Q1 = ms∆T
= 5000 × 1 × (40 – 0) = 5000 × 40 = 200000 cal [s = 1 cal/g-°C for water]
The heat energy released to convert 5 kg of water at 0°C to 5 kg of ice at 0°C.
Q2 = mLf
= 5000 × 80 = 400000 cal [∵ Lf = 80 cal/g]
Total energy released = 200000 + 400000
= 600000 cal
= 600 kcal
= 142.86 kJ.

Question 23.
The quantity of heat which can rise the temperature ‘x’ grams of a substance through t1°C can rise the temperature of ‘y’ grams of water through t2°C is same.
What is the ratio of specific heats?
Answer:
Given,
AP SSC 10th Class Physics Important Questions Chapter 1 Heat 28

AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1

AP State Board Syllabus AP SSC 10th Class Maths Textbook Solutions Chapter 14 Statistics Ex 14.1 Textbook Questions and Answers.

AP State Syllabus SSC 10th Class Maths Solutions 14th Lesson Statistics Exercise 14.1

10th Class Maths 14th Lesson Statistics Ex 14.1 Textbook Questions and Answers

Question 1.
A survey was conducted by a group of students as a part of their environment awareness programme, in which they collected the following data regarding the number of plants in 20 houses in a locality. Find the mean number of plants per house.
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1 q1
Answer:
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1 q2
Since fi and xi are of small values we use direct method.
∴ \(\overline{\mathrm{x}}=\frac{\Sigma \mathrm{f}_{\mathrm{i}} \mathrm{x}_{\mathrm{i}}}{\Sigma \mathrm{f}_{\mathrm{i}}}\)
= \(\frac{162}{20}\)
= 8.1

AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1

Question 2.
Consider the following distribution of daily wages of 50 workers of a factory.
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1 3
Find the mean daily wages of the workers of the factory by using an appropriate method.
Answer:
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1 4
Here the xi are of large numerical values.
So we use deviation method then,
\(\overline{\mathbf{x}}=\mathbf{a}+\frac{\Sigma \mathbf{f}_{\mathbf{i}} \mathbf{d}_{\mathbf{i}}}{\Sigma \mathbf{f}_{\mathbf{i}}}\)
Here the assumed mean is taken as 275.
∴ \(\overline{\mathrm{x}}=\mathrm{a}+\frac{\Sigma \mathrm{f}_{\mathrm{i}} \mathrm{d}_{\mathrm{i}}}{\Sigma \mathrm{f}_{\mathrm{i}}}\)
= 275 + \(\frac{1900}{50}\)
= 275 + 38
= 313.

AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1

Question 3.
The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs. 18. Find the missing frequency f.
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1 5
Answer:
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1 6
\(\overline{\mathrm{x}}=\frac{\Sigma \mathrm{f}_{\mathrm{i}} \mathrm{x}_{\mathrm{i}}}{\Sigma \mathrm{f}_{\mathrm{i}}}\)
xi = 18 (given)
\(\Rightarrow 18=\frac{752+20 \mathrm{f}}{(44+\mathrm{f})}\)
18 (44 + f) = 752 + 20 f
⇒ 20f- 18f= 792-752
⇒ 2f = 40
∴ f = \(\frac{40}{20}\) = 20.

AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1

Question 4.
Thirty women were examined in a hospital by a doctor and their of heart beats per minute were recorded and summarised as shown. Find the mean heart beats per minute for these women, choosing a suitable method.
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1 7
Answer:
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1 8
\(\overline{\mathbf{x}}=\mathbf{a}+\frac{\Sigma \mathbf{f}_{\mathbf{i}} \mathbf{d}_{\mathbf{i}}}{\Sigma \mathbf{f}_{\mathbf{i}}}\)
75.5 + \(\frac{12}{30}\)
= 75.5 + 0.4
= 75.9.

AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1

Question 5.
In a retail market, fruit vendors were selling oranges kept in packing baskets. These baskets contained varying number of oranges. The following was the distribution of oranges.
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1 9
Find the mean number of oranges kept in each basket. Which method of finding the mean did you choose?
Answer:
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1 10
Here we use step deviation method where a = 135, h = 5,a multiple of all di
\(\overline{\mathrm{x}}=\mathrm{a}+\left(\frac{\Sigma \mathrm{f}_{\mathrm{i}} \mathrm{u}_{\mathrm{i}}}{\Sigma \mathrm{f}_{\mathrm{i}}}\right) \times \mathrm{h}\)
= 22 + \(\frac{25}{400}\) × 5
= 22 + 0.31
= 22.31

AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1

Question 6.
The table below shows the daily expenditure on food of 25 households in a locality.AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1 11
Find the mean daily expenditure on food by a suitable method.
Answer:
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1 12
Here a = 125, h = 50, ∑fiui = 43
Now
\(\overline{\mathrm{x}}=\mathrm{a}+\left(\frac{\Sigma \mathrm{f}_{\mathrm{i}} \mathrm{u}_{\mathrm{i}}}{\Sigma \mathrm{f}_{\mathrm{i}}}\right) \times \mathrm{h}\)
= 125 + \(\frac{43}{25}\) × 50
= 125 + (43 × 2)
= 125 + 86
= 211.
NOTE: If we consider first value as “a” then we dont get negative values in ui, fiui columns. Then it becomes easy for calculation.

AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1

Question 7.
To find out the concentration of SO2 in the air (in parts per million, i.e., ppm), the data was collected for 30 localities in a certain city and is presented below:
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1 13
Find the mean concentration of SO2 in the air.
Answer:
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1 14
∴ \(\overline{\mathrm{x}}=\frac{\Sigma \mathrm{f}_{\mathrm{i}} \mathrm{x}_{\mathrm{i}}}{\Sigma \mathrm{f}_{\mathrm{i}}}\)
= \(\frac{2.96}{30}\)
= 0.00986666…….
≃ 0.099

AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1

Question 8.
A class teacher has the following attendance record of 40 students of a class for the whole term. Find the mean number of days a student was present out of 56 days in the term.
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1 15
Answer:
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1 16
Here, a = 51.5
∴ \(\overline{\mathbf{x}}=\mathbf{a}+\frac{\Sigma \mathbf{f}_{\mathbf{i}} \mathbf{d}_{\mathbf{i}}}{\Sigma \mathbf{f}_{\mathbf{i}}}\)
= 51.5 – \(\frac{99}{40}\)
= 51.5 – 2.475
= 49.025
≃ 49 days

AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1

Question 9.
The following table gives the literacy rate (in percentage) of 35 cities. Find the mean literacy rate.
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1 17
Answer:
AP SSC 10th Class Maths Solutions Chapter 14 Statistics Ex 14.1 18
a = 70; h = 10
∴ \(\overline{\mathbf{x}}=\mathbf{a}+\frac{\Sigma \mathbf{f}_{\mathbf{i}} \mathbf{u}_{\mathbf{i}}}{\Sigma \mathbf{f}_{\mathbf{i}}} \times \mathbf{h}\)
\(\Rightarrow \bar{x}=70-\frac{2}{35} \times 10\)
= 70 – \(\frac{2}{35}\) × 10
= 70 – \(\frac{20}{35}\)
= 70 – 0.57142
= 69.4285
≃ 69.43%

AP SSC 10th Class English Solutions Chapter 1A Attitude is Altitude

AP State Board Syllabus AP SSC 10th Class English Textbook Solutions Chapter 1A Attitude is Altitude Textbook Questions and Answers.

AP State Syllabus SSC 10th Class English Solutions Chapter 1A Attitude is Altitude

10th Class English Chapter 1A Attitude is Altitude Textbook Questions and Answers

Look at the pictures and answer the questions.
AP SSC 10th Class English Solutions Chapter 1A Attitude is Altitude 1

AP SSC 10th Class English Solutions Chapter 1A Attitude is Altitude

Question 1.
What qualities have made these persons great?
Answer:
The persons in the above pictures are Sudha Chandran, Stephen Hawking and Helen Keller.
Sudha Chandran is an accomplished Bharatanatyam dancer, Indian film and television actress, who showed great courage even though she had lost her leg in an accident.

Stephen Hawking is one of the famous scientists. Despite his debilitating illness, he has done ground-breaking work in physics.

Helen Keller overcame the adversity of being blind and deaf to become one of the 20th century’s leading humanitarians.
These three great persons showed that anything can be done, if one tries hard enough. From their lives, it is understood that one need not lose hope. Their lives show us that disability need not prevent one from reaching great heights. The qualities such as grit, determination, confidence, will power, dedication, discipline, etc. have made these persons great.

Question 2.
What qualities do you think a person requires to become successful ?
Answer:
The qualities a person requires to become successful are determination, dedication, discipline, grit, courage, faith, positive thinking, responsibility, hard work, commitment, desire, persistence, good character, etc. These qualities make a person highly successful.

AP SSC 10th Class English Solutions Chapter 1A Attitude is Altitude

Comprehension

I. Answer the following questions.

Question 1.
‘I call it my chicken drumstick,’ joked Nick. What does ‘it’ refer to? How does it help him ?
Answer:
‘It’ refers to the small foot that Nick has on his left hip. It helps him balance and enables him to kick. Nick uses his one foot to type, write with a pen and pick things up between his toes.

Question 2.
‘His parents decided not to send him to a special school.’ Was Nick happy about his parents’ decision? Why or why not? What do you think about this decision?
Answer:
Nick’s was not happy with his parents’ decision because there might be the risk of bullying. His companions at mainstream school might tease him.
But later, he realised that his parents’ decision was the best one. I think that this decision was the best one his parents could have made for him as he was able to achieve a degree in Financial Planning and Real Estate. The decision made him independent.

Question 3.
How did Nick’s parents help him to become independent?
Answer:
Right from the start Nick’s parents did their best to make him independent. His father put Nick in the water at 18 months and gave him the courage to learn how to swim. He encouraged Nick to get into football and skating. He taught Nick how to type with his toe at just six years old. Nick’s mother invented a special plastic device that meant Nick could hold a pen and pencil. Despite the risk of bullying, Nick’s parents insisted on his attending mainstream school.

AP SSC 10th Class English Solutions Chapter 1A Attitude is Altitude

Question 4.
Pick out the symptoms of Nick’s depression. Do you think his depression was normal or something unique about him? Give reasons for your opinion.
Answer:
Nick was deeply depressed when he was eight years old. When he was in depression, he went to his mother crying and told her that he wanted to kill himself. He felt cold and bitter. He hated God for doing this to him. He was terrified about his future without his parents. At age ten Nick tried to drown himself in the bath. These were the symptoms of Nick’s depression. I think his depression was normal. Any human being born like Nick might have the same depression.

Question 5.
Which incident in this text is funny? What makes it funny?
Answer:
Once Nick was in a car and a girl at traffic lights was looking at him interestingly. She could only see Nick’s head so he decided to do a 360 in the car seat to freak her out. When she saw the torso, she sped off really quickly. This is the funny incident in the text. The idea of Nick showing the girl his torso makes the scene funny.

Question 6.
What made Nick choose Bethany Hamilton as his teacher to learn surfing?
Answer:
Nick went to Hawaii in 2008 and met surfing master Bethany Hamilton. She had her arm bitten off by a shark when she was 12. Nick chose Bethany Hamilton as she too was a disabled person and still she performed surfing very well. Though she had no arm she did well. As a disabled person, she could know how a disabled person could learn how to surf. She could know the psychological condition of a disabled person.

Question 7.
Which aspect of Nick’s physical condition helps him to do a 360 degree spin?
Answer:
Nick has a very low centre of gravity so he has got pretty good balance. This condition helps Nick to do 360 degree spin.

AP SSC 10th Class English Solutions Chapter 1A Attitude is Altitude

Question 8.
What are the distinct features of this text? List them.
Answer:

  1. It is an autobiography.
  2. Varied sentences are used.
  3. Ideas are arranged in a logical sequence.
  4. Emotive and persuasive language is used.
  5. Ideas are exemplified very well.
  6. Cohesion is found in the text. The sentences are connected with proper linkers.
  7. Unity of ideas is maintained for coherence. The sentences are connected in a clear and reasonable way.
  8. Certain quotations and examples are given.
  9. Proper introduction, development and conclusion are ensured.
  10. The ideas are given formally and precisely.
  11. As far as the content is concerned, it touches the emotions of a reader.
  12. The content is message-oriented.
  13. Physical description of the main character is given properly.
  14. The main character’s attitudes, likes, dislikes, strengths and weaknesses are given effectively.

Question 9.
What do you learn from the life of Nick Vujicic?
Answer:
Nick Vujicic uses his life story to inspire people of all around the world. From the life of Nick, we learn that if we fail, we should try again and again until we succeed. Nick shows us that anything can be done, if we try hard enough. Undoubtedly, I feel that his life is a source of inspiration to everyone of us. He has been able to do all these because of his faith, hope, perseverance and strong will power. Nick proves that disability need not prevent one from reaching great heights. Hence I learn that we shouldn’t lose our faith and hope under any circumstances.

AP SSC 10th Class English Solutions Chapter 1A Attitude is Altitude

II. Given below are some of the statements made by Nick Vujicic. Which of these are substantiated by Nick’s life ?

  • I realised why God had made us like this – to give hope to others.
  • I wanted to concentrate on something good that / had.
  • I tell people to keep on getting up when they fall and to always love themselves.
  • If I can encourage just one person, then my job in this life is done.

Answer:
I think all the above statements are substantiated by Nick’s life.
i) I realised why God had made us like this – to give hope to others:
When Nick was 13, he read a newspaper article about a disabled man who had managed to achieve great things and help others. Nick was inspired very much by the disabled man mentioned in the article. He got a hope from him. Then he decided to use his life to encourage others and give them hope.

ii) I wanted to concentrate on something good that I had:
Nick was not discouraged with his disability. He knew that he had no arms and legs but he thought that they would never take away the beauty of his eyes. With his positive approach, he thought that his eyes were very good ones for him. He wanted to love his positive qualities such as faith, will power and perseverance. Further, he was quite satisfied with what he had, i.e. a small foot on his left hip. He said he would be lost with it.

iii) I tell people to keep on getting up when they fall and to always love themselves: If Nick fails, he tries again and again until he succeeds. When Nick was learning how to surf, he was terrified at first but later he did very well. Though he has no limbs, he always loves himself. I know this by his statement, “I decided to be thankful for what I do have, not get angry about what I don’t.”

iv) If I can encourage just one person, then my job in this life is done:
This statement was substantiated by Nick aptly. He encouraged many people in the world. He used his life story to inspire others. He made many people realise their inner beauty and personality. He was able to rise many people from the state of despair to the state of great hope.

AP SSC 10th Class English Solutions Chapter 1A Attitude is Altitude

Vocabulary

I. Look at the list of adjectives in the box. Which of them describe Nick Vujicic. Tick (✓) them.
AP SSC 10th Class English Solutions Chapter 1A Attitude is Altitude 2
Answer:
AP SSC 10th Class English Solutions Chapter 1A Attitude is Altitude 3

Explanation:

  1. positive: hopeful and confident
  2. negative: harmful, unpleasant or not wanted
  3. optimistic: believing that good things will happen In the future
  4. pessimistic: expecting that bad things will happen in the future
  5. generous: willing to give money, spend time, etc. in order to help people or give them pleasure
  6. nervous: worried or frightened about something
  7. confident: sure that something will happen in the way that you want or expect
  8. smart: fashionable, clever
  9. sociable: friendly and enjoys being with other people
  10. cowardly: not at all brave
  11. courageous: brave
  12. reliable: dependable
  13. Independent: confident and able to do things by oneself in ones own way
  14. dependent: needing someone or something in order to exist, be successful, be healthy, etc.
  15. obedient: always doing what one is told to do
  16.  trusting: willing to believe that other people are good and honest
  17. valiant: very brave in difficult situation
  18. self-centred: paying so much attention to oneself that one doesn’t notice what is happening
  19. arrogant: behaving in an unpleasant or rude way
  20. sarcastic: saying things that are the opposite of what one means, in order to make an unkind joke
  21. quarrelsome: one who quarrels a lot with people
  22. rude: not polite and annoys others
  23. creative: good at using imagination to make things
  24. stubborn: determined not to change one’s mind when people think one is being unreasonable
  25. lazy: not making any effort to do anything
  26. pompous: trying to seem magnificent or very important; fond of display, acting too proudly, self-important.
  27. level-headed: sensible in making judgements

AP SSC 10th Class English Solutions Chapter 1A Attitude is Altitude

Pick out from the text the examples that support these attributes.

Attribute Example from the text
1. Positive In spite of his disability he has become great.
2. Optimistic He always thinks, “If I fail, I try again, and again, and again. If I can encourage just one person, then my job is done.”
3. Generous He spends most of his time delivering motivational speeches all over the world.
4. Confident Though he has no limbs, he gains faith and hope and tries to give them to others.
5. Smart He appears to be smart and shows his cleverness in learning things.
6. Sociable He enjoys being with others by delivering speeches, playing football, golf, surfing, etc.
7. Courageous Despite the absence of his limbs, he didn’t get discouraged. With great courage, he tries again and again and becomes a football player, a swimmer and a surfer.
8. Reliable He is the most reliable person. As an Evangelical Christian he has faith and gives the same to others with his motivational speeches. The people believe his reliability and are attracted towards him.
9. Independent He independently has done the things what he has wanted to do. e.g.: Playing football and golf, swimming, surfing, delivering speeches, etc.
10. Obedient He seems to be obedient in accepting the unlucky birth.
11. Valiant With great determination, he has reached a great position in his life. He becomes an international symbol of triumph over adversity.
12. Creative He also plays golf with a club tucked under his chin.
13. Level-headed He judges well when he says, “The challenges in our lives are there to strengthen our convictions. They are not there to run us over.”

AP SSC 10th Class English Solutions Chapter 1A Attitude is Altitude

II. Given below are words that describe the positive or negative attitude of a person. Discuss them with your partner and put a tick (✓) against the positive qualities and a cross (✕) against the negative qualities.

AP SSC 10th Class English Solutions Chapter 1A Attitude is Altitude 4AP SSC 10th Class English Solutions Chapter 1A Attitude is Altitude 5
Answer:
AP SSC 10th Class English Solutions Chapter 1A Attitude is Altitude 6

Explanation:

  1. sullen: angry and silent (negative quality)
  2. sneaky: doing things in a secret and dishonest way (negative quality)
  3. exuberant: happy and full of energy and excitement (positive quality)
  4. bossy: always telling other people what to do in a way that is annoying (negative quality)
  5. cautious: careful to avoid danger or risk (positive quality)
  6. aggressive: behaving in an angry threatening way (negative quality)
  7. competitive: determined or trying very hard to he more successful than other people (positive quality)
  8. finicky: too concerned with unimportant details and small things that you like or dislike (negative quality)
  9. imaginative: good at thinking of new and interesting ideas (positive quality)
  10. observant: good or quick at noticing things (positive quality)
  11. enthusiastic: showing a lot of interest and excitement about something (positive quality)
  12. outgoing: someone who Is outgoing likes to meet and talk to new people (positive quality)
  13. haughty: behaving in a proud. unfriendly way (negative quality)
  14. intrepid: willing to do dangerous things; fearless, brave (positive quality)
  15. malicious: very unkind and cruel and is trying to do harm to others (negative quality)
  16. meticulous: very careful about small details and always makes sure that everything is done correctly (positive quality)
  17. slovenly: lazy untidy and careless (negative quality)
  18. obnoxious: very offensive, unpleasant or rude (negative quality)
  19. stingy: not generous. especially with money (negative quality)
  20. Idealistic: believing that one should live according to high standards and principles, even when they are very difficult to achieve (positive quality)
  21. affable: friendly and easy to talk to (positive quality)
  22. logical: reasonable and sensible (positive quality)
  23. mean: cruel (negative quality)
  24. cultured: intelligent, polite and interested in art, literature, music etc. (positive quality)

AP SSC 10th Class English Solutions Chapter 1A Attitude is Altitude

III. Tick (✓) the word/expression which is nearest in meaning to the word underlined in each sentence given below.

1. Water sports aren’t Nick’s only thing – he also plays golf with a dub tucked under his chin.
a) kept
b) pulled
c) covered
d) tied
Answer: a

2. His distraught mother couldn’t bring herself to hold him until he was four months old.
a) angry
b) careless
c) shy
d) anxious
Answer: d

3. Despite the risk of bullying, his parents insisted on Nick’s attending mainstream school.
a) discrimination
b) humiliation
c) negligence
d) failure
Answer: b

4. Nick, who was teased and bullied, had an electric wheelchair for mobility, and a team of carers to help him.
a) socialising
b) movement
c) travel
d) safety
Answer: b

5. Nick managed to pull through to become an international symbol of triumph over adversity.
a) disability
b) poverty
c) difficulties
d) opposition
Answer: c

6. The challenges in our lives are there to strengthen our convictions.
a) feelings
b) practices
c) beliefs
d) characters
Answer: c

AP SSC 10th Class English Solutions Chapter 1A Attitude is Altitude

IV. Read the following descriptions about persons and fill in the blanks with the words that match with these descriptions.

AP SSC 10th Class English Solutions Chapter 1A Attitude is Altitude 8

1. Ashok is a very unpleasant and rude fellow. I don’t talk to him. He is ———–.
2. Srinu is very confident, elegant and polite. But sometimes he does not appear to be sincere. He is ———–.
3. Sujatha is quiet and calm. She doesn’t like to spend time with others. She is interested in her thoughts and feelings. So she is an ———–.
4. Ramesh is very sensitive. He always shows sympathy for people who are suffering. He is ———–.
5. My neighbour is such a person that he has a feeling of hatred for others. He desires to hurt others’ feelings. He is ———–.
6. My father pays careful attention to every detail. He makes thorough planning for everything in our home. He is ———–.
7. Prem is an extremely unpleasant person. He always tries to offend people. He is ———–.
8. My mother is very calm and peaceful. She doesn’t get excited or irritated easily. She is ———–.
9. Rahul is a very lively and confident person. He enjoys being with his friends. He is an ———–.
10. Sridhar is always afraid of speaking in the class. He is ———–.
Answers:
1. boorish
2. suave
3. introvert
4. compassionate
5. malicious
6. meticulous
7. obnoxious
8. placid
9. extrovert
10. timid

AP SSC 10th Class English Solutions Chapter 1A Attitude is Altitude

GRAMMAR

I. Read the text again and identify some more Defining and Non-defining Relative Clauses.

1. —————————————————————
2. —————————————————————
3. —————————————————————
4. —————————————————————
5. —————————————————————
Answer:
1. Nick has a small foot, which helps him balance. (Non-defining Relative Clause)
2. Nick, who was born in Melbourne, now lives in Los Angeles. (Non-defining Relative Clause)
3. I read about a disabled man who had managed to achieve great things and help others. (Defining Relative Clause)
4. I decided to give people the courage that the article had given me. (Defining Relative Clause)
5. Nick, who later achieved a degree, says this. (Non-defining Relative Clause)

II. Read the following sentences and circle the Non-defining Relative Clauses and put a comma/a hyphen wherever necessary.

1. The meeting which was held in the town hall was a great success.
2. The people who live in glass houses must not throw stones.
3. The teachers who have taught Abhiram say that he is an exceptionally creative student.
4. Napoleon who won the French honour died at St. Helena.
5. The silk sarees which are made in Banares are popular all over the world.
Answer:
1. The meeting which was held in the town hall was a great success. (Defining Relative Clause)
2. The people who live in glass houses must not throw stones. (Defining Relative Clause)
3. The teachers who have taught Abhiram say that he is an exceptionally creative student. (Defining Relative Clause)
4. Napoleon, who won the French honour, died at St. Helena. (Non-defining Relative Clause)
5. The silk sarees which are made in Benares are popular all over the world. (Defining Relative Clause)

AP SSC 10th Class English Solutions Chapter 1A Attitude is Altitude

III. Complete the sentences with Defining or Non-defining Relative Clauses.

1. This is the peaceful place __________________________ .
2. The Mahaprasthanam’ is a popular book __________________________ .
3. Suresh ____________________________ has left the school just now.
4. Is this the street _______________________________________________ ?
5. The express __________________________________ has just arrived.
6. The place ___________________________ has been closed to traffic.
7. This is a famous engineering college _____________________________ .
8. My sister_______________ has secured ajob as an engineer in BHEL.
9. The theatre _____________________________ was designed by Mr Rao.
10. Viswanath is one of the outstanding directors in Telugu film industry______________________ .
Answer:
1. This is the peaceful place that is liked by every naturalist.
2. The Mahaprasthanam’ is a popular book which I have bought in Hyderabad.
3. Suresh, who is mv cousin, has left the school just now.
4. Is this the street where meat is sold?
5. The express which runs between Delhi and Chennai has just arrived.
6. The place which is behind our house has been closed to traffic.
7. This is a famous engineering college that is founded by Mr. Yashwanth.
8. My sister, who has completed her education in Bengaluru, has secured a job as an engineer in BHEL.
9. The theatre which was built in 2012 was designed by Mr. Rao.
10. Viswanath is one of the outstanding directors in Telugu film industry which produces a number of creative directors.

AP SSC 10th Class English Solutions Chapter 1A Attitude is Altitude

WRITING

I. Writing a biographical sketch

A biographical sketch is an account of the life and activities of an individual. It includes information about the person’s name, place of residence, education, occupation, life and activities and other important details. It is written by another person. If a person writes an account of his/her own life, it is called an autobiography.

Given below in the table is the biographical information about Stephen Hawking. Based on this information write a biographical sketch.

Points to be covered Details of the person
Date and place of birth January 8,1942, Oxford, England
Information about the family
  • Eldest one of four sons
  • Mother: Isobel Hawking
  • Father: Frank Hawking, a medical researcher with a speciality in tropical diseases
Important events in life
  • Early academic life: recognized as a bright student
  • High school years: third from the bottom of his class
  • Pursuits outside of school: loved board games, constructed a computer out of recycled parts at the age of 16, solved rudimentary mathematical equations
  • Marriage: married Jane Wilde
  • Health: Suffered from Amyotrophic Lateral Sclerosis
  • Research: on black holes
  • Discovery: Hawking Radiation
Awards, prizes, honours
  • Fellow of the Royal Society at the age of 32
  • Albert Einstein Award.
  • The Pius XI- Gold Medal for Science from Pope Paul VI in 1975
Contribution to his field and society Contributed to the advancement of science and research

Answer:

Biographical Sketch of Stephen Hawking

Stephen William Hawking is one of the greatest scientists of the world. He was born at Oxford in England on 8 January, 1942 to Isobel Hawking and Frank Hawking. He was the eldest of four sons. His father, Frank Hawking, was a medical researcher with a speciality in tropical diseases.

Hawking was recognised as a bright student. But he was not initially successful academically. During his high school years, Stephen stood the third from the bottom of his class.

Hawking used to remain with a close group of friends with whom he enjoyed board games, the manufacture of fireworks, model aeroplanes and boats. With the help of the mathematics teacher, Dickran Tahta, Hawking and his companions built a computer from clock parts, an old telephone switchboard and other recycled components when he was 16. Hawking solved rudimentary mathematical equations.

He married Jane Wilde on 14 July, 1965. The first years after their marriage were hectic. Hawking has achieved many things in the field of science in spite of his prolonged illness. He has been suffering from an incurable disease, Amyotrophic Lateral Sclerosis (ALS) which has weakened his muscles since he was 17 years old.

Stephen Hawking is known for his work regarding black holes and for authoring several popular science books. In 1974, Hawking’s research turned him into a celebrity within the scientific world when he showed that black holes are not the information vacuums that scientists had thought they were. In simple terms, Hawking demonstrated that matter, in the form of radiation, can escape the gravitational force of a collapsed star. Thus Hawking Radiation was invented.

As a mark of his eminence, Professor Hawking obtained twelve honorary degrees which he deserved. He was named a Fellow of the Royal Society at the age of 32, and later earned the prestigious Albert Einstein Award. In 1975, Hawking journeyed to Rome, where he was honoured with the Pius XI – Gold Medal for science from Pope Paul VI in 1975.

Attitude is Altitude Summary in English

This is the story of a great person, Nicholas James Nick Vujicic, who stands as an inspiration to other people with his great qualities-faith, will power and perseverance- even though he is a disabled person. His disability has not stopped him from doing what he has wanted to do. Nick Vujicic was born on 4 December 1982 in Melbourne, Australia with a rare disability called Phocomelia characterised by the absence of all four limbs. Despite the absence of his limbs, he plays football and golf, swims and surfs. He is an Australian Christian evangelist and motivational speaker. As a child, he struggled mentally and emotionally as well as physically. It was a shock to Nick’s parents that he was born without limbs. His mother was a nurse and his father was a computer programmer and accountant. His parents did their very best when they decided to send him to mainstream school despite the risk of humiliation.

Nick has a small foot on his left hip. It gives him balance and enables him to kick. With his foot, he writes with a pen and picks things up between his toes. He also plays golf with a heavy stick tucked under his chin. He is a huge fan of the English Premier League. His parents did their best to make him independent from the start. His father gave him the courage to learn how to swim by putting him in water at 18 months. His mother invented a special plastic device to enable him to hold a pen and pencil.

At age eight, Nick was deeply depressed and went to his mother crying. He told her that he wanted to kill himself. When he was ten years old, he decided to end his life by drowning himself in a bathtub but luckily he was unsuccessful in his attempt. When Nick was 13, he was inspired when he read about a disabled man who had managed to achieve great things and helped others. He understood that God had given him the life to give hope to others and so he decided to use his life to encourage other people and give them the courage. He believes that challenges strengthen our opinions. With the help of his religion, friends and family, Nick becomes an international symbol of triumph over adversity. Nick won the Australian Young Citizen of the Year award in 1990 for his bravery and perseverance. His persistence made him achieve a degree in Financial Planning and Real Estate. He went to Hawaii in 2008 and was trained in surfing by Bethany Hamilton. Nick was on the cover of Surfer magazine with his feat of doing the 360 degree spins. He is able to do this feat because of his low centre of gravity.
Nick and Kanae Miyahara, whose mother was a Mexican and father was a Japanese, got married on February 12, 2012 and on February 13, 2013 they were blessed with the birth of a healthy baby boy with full body.

Nick has travelled to over 24 countries speaking to groups of up to 110,000 people. He keeps telling the people to keep on getting up when they fall and to always love themselves. He spreads his messages of faith and hope around the world.

Nick uses his story to inspire and inform people all around the world. Nick presents values, principles, attitudes and perspectives that challenge and equip people from all walks of life to overcome their adversities.

Attitude is Altitude Glossary

stretch (v): to straighten one’s arms, legs or body

wrap (v): put ones arms around something

skateboard (n): a short narrow board with small wheels at each end, which you stand on and ride as a sport

torso (n): the main part of the body, not including the head, arms or legs

surf: to take part in the sport of riding on waves on a surfboard

despite (pre): In spite of

limb (n): an arm or leg

hip (n): one of the two parts on each side of one’s body between the top of one’s leg and one’s waist

chicken drumstick (n): the lower part of the leg of a chicken or other bird that is cooked and eaten as food

faith (n): belief or trust in God

virgin (n): someone who has never had sex

modest (adj): shy about attracting sexual interest

publicist (n): someone whose job is to make sure that people know about a new product, film, book, etc.

club (n): a heavy stick with one end thicker than the other

tuck (v): to put something into a space

distraught (adj): so upset and worried

bully (v): to threaten to hurt someone or frighten them

bullying (n): humiliation

carer (n): someone who looks alter an old or ill person at home

wall-mounted (adj): attached to a wall

pump-action (adj): a pump-action piece of equipment is operated by pulling or pressing a part in or out. so that the contents come out in short bursts

drown (v): to die from being under water for too long time

lack: to not have something that one needs

triumph (n): an important success or victory

adversity (n): a difficulty or unpleasant situation

Inspirational (adj): providing encouragement or new ideas for what one should do

conviction (n): a very strong belief or opinion

run over (phr.v.): to hit someone or something with something (a vehicle, challenge, etc.) and drive over them

perseverance (n): the quality of continuing to try to achieve a particular aim despite difficulties

give somebody the eye (n.phrase): to look at someone in a way that shows one thinks they are sexually attractive

freak out (phr.v.): make someone very anxious. upset or afraid

amazing (adj): (here) very good

spin (n): an act of turning around quickly

centre of gravity (n.phrase): the point in any object on which it can balance

AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.2

AP State Board Syllabus AP SSC 10th Class Maths Textbook Solutions Chapter 13 Probability Ex 13.2 Textbook Questions and Answers.

AP State Syllabus SSC 10th Class Maths Solutions 13th Lesson Probability Exercise 13.2

10th Class Maths 13th Lesson Probability Ex 13.2 Textbook Questions and Answers

Question 1.
A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is (i) red ? (ii) not red?
Answer:
i) Total number of balls in the bag = 3 red + 5 black = 8 balls.
Number of total outcomes when a ball is drawn at random = 3 + 5 = 8
Now, number of favourable outcomes of red ball = 3.
∴ Probability of getting a red ball = \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\) = \(\frac{3}{8}\)
ii) If P( E) is the probability of drawing no red ball, then P(E) + P(\(\overline{\mathrm{E}}\)) = 1
P(\(\overline{\mathrm{E}}\)) = 1 – P(E)= 1 – \(\frac{3}{8}\) = \(\frac{5}{8}\)

AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.2

Question 2.
A box contains 5 red marbles, 8 white marbles and 4 green marbles. One marble is taken out of the box at random. What is the probability that the marble taken out will be (i) red? (ii) white? (iii) not green?
Answer:
Total number of marbles in the box = 5 red + 8 white + 4 green = 5 + 8 + 4= 17
Number of total outcomes in drawing a marble at random from the box =17.
i) Number of red marbles = 5
Number of favourable outcomes in drawing a red ball = 5
∴ Probability of getting a red ball P(R) = \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
P(R) = \(\frac{5}{17}\)

ii) Number of white marbles = 8
Number of favourable outcomes in drawing a white marble = 8
∴ Probability of getting a white marble
P(W) = \(\frac{8}{17}\)

iii) Number of ‘non-green’ marbles = 5 red + 8 white = 5 + 8 = 13
Number of outcomes favourable to drawing a non-green marble =13.
∴ Probability of getting a non- green marble
P(non – green) = \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
P(non – green) = \(\frac{13}{17}\)
Probability of getting a green ball = \(\frac{\text { No. of green balls }}{\text { Total no. of balls }}\) = \(\frac{4}{17}\)
Now P(G) = \(\frac{4}{17}\)
and P(G) + P(\(\overline{\mathrm{ G}}\)) = 1
∴ P(\(\overline{\mathrm{G}}\)) = 1 – P(G)
= 1 – \(\frac{4}{17}\)
= \(\frac{13}{17}\)

AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.2

Question 3.
A Kiddy bank contains hundred 50p coins, fifty Rs. 1 coins, twenty Rs. 2 coins and ten Rs. 5 coins. If it is equally likely that one of the coins will fall out when the bank is turned upside down, what is the probability that the coin (i) will be a 50 p coin? (ii) will not be a Rs. 5 coin?
Answer:
i) Number of 50 p coins = 100
Number of Rs. 1 coins = 50
Number of Rs. 2 coins = 20
Number of Rs. 5 coins = 10
Total number of coins = 180
Number of total outcomes for a coin to fall down = 180.
Number of outcomes favourable to 50 p coins to fall down = 100.
∴ Probability of a 50 p coin to fall down = \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{100}{180}\) = \(\frac{5}{9}\)

ii) Let P(E) be the probability for a Rs. 5 coin to fall down.
Number of outcomes favourable to Rs. 5 coin = 10.
∴ Probability for a Rs. 5 coin to fall down = \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{10}{180}\) = \(\frac{1}{18}\)
Then P(\(\overline{\mathrm{E}}\)) is the probability of a coin which fall down is not a Rs. 5 coin.
Again P(E) + P(\(\overline{\mathrm{E}}\)) = 1
∴ P(\(\overline{\mathrm{E}}\))= l-P(E)
= 1 – \(\frac{1}{18}\)
= \(\frac{17}{18}\).

AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.2

Question 4.
Gopi buys a fish from a shop for his aquarium. The shopkeeper takes out one fish at random from a tank containing 5 male fish and 8 female fish (See figure). What is the probability that the fish taken out is a male fish?
AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.2 1Answer:
Number of male fish = 5
Number of female fish = 8
Total number of fish = 5 m + 8 f
= 13 fishes.
∴ Number of total outcomes in taking a fish at random from the aquarium =13.
Number of male fish = 5
∴ Number of outcomes favourable to male fish = 5.
∴ The probability of taking a male fish = \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{5}{13}\)
= 0.38

Question 5.
A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (See figure), and these are equally likely outcomes. What is the probability that it will point at
(i) 8?
(ii) an odd number?
(iii) a number greater than 2?
(iv) a number less than 9?
AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.2 2
Answer:
Number of total outcomes are (1,2,……….., 8) = 8

i) Number of outcomes favourable to 8 = 1.
∴ P(8) = \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{1}{8}\)

ii) Number of ‘odd numbers’ on the spinning wheel = (1, 3, 5, 7) = 4
∴ Number of outcomes favourable to an odd number.
∴ Probability of getting an odd number = \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{4}{8}\) = \(\frac{1}{2}\)

iii) Number greater than 2 are (3, 4, 5, 6, 7, 8)
Number of outcomes favourable to ‘greater than 2’ are = 6.
Probability of pointing a number greater than 2
P(E) = \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{6}{8}\) = \(\frac{3}{4}\)

iv) Number less than 9 are: (1,2, 3, 4, 5, 6, 7, 8 …… 8)
∴ Number of outcomes favourable to pointing a number less than 9 = 8.
∴ Probability of a number less than 9
P(E) = \(\frac{\text { No. of outcomes favourable to less than } 9}{\text { No.of total outcomes }}\)
= \(\frac{8}{8}\) = 1
Note : This is a sure event and hence probability is 1.

AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.2

Question 6.
One card is drawn from, a well-shuffled deck of 52 cards. Find the probability of getting
(i) a king of red colour
(ii) a face card
(iii) a red face card
(iv) the jack of hearts
(v) a spade
(vi) the queen of diamonds.
Answer:
Total number of cards = 52.
∴ Number of all possible outcomes in drawing a card at random = 52.
i) Number of outcomes favourable to the king of red colour = 2(♥ K, ♦ K)
∴ Probability of getting the king of red colour
P(E) = \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{2}{52}\) = \(\frac{1}{26}\)

ii) Number of face cards in a deck of cards = 4 × 3 = 12 (K, Q, J)
Number of outcomes favourable to select a face card = 12.
∴ Probability of getting a face card
= \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{12}{52}\) = \(\frac{3}{13}\)

iii) Number of red face cards = 2 × 3 = 6.
∴ Number of outcomes favourable to select a red face card = 6.
∴ Probability of getting a red face
= \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{6}{52}\) = \(\frac{3}{26}\)

iv) Number of outcomes favourable to the jack of hearts = 1.
∴ Probability of getting jack of hearts
= \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{1}{52}\)

v) Number of spade cards = 13
∴ Number of outcomes favourable to ‘a spade card’ = 13.
∴ Probability of drawing a spade
= \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{13}{52}\) = \(\frac{1}{4}\)

vi) Number of outcomes favourable to the queen of diamonds = 1.
∴ Probability of drawing the queen of diamonds
= \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{1}{52}\)

AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.2

Question 7.
Five cards-the ten, jack, queen, king and ace of diamonds, are well-shuffled with their face downwards. One card is then picked up at random.
i) What is the probability that the card is the queen?
ii) If the queen is drawn and put aside, what is the probability that the second card picked is (a) an ace? (b) a queen?
Answer:
Total number of cards = 5.
∴ Number of total outcomes in picking up a card at random = 5.
i) Number of outcomes favourable to queen = 1.
∴ Probability of getting the queen
= \(\frac{\text { No.of outcomes favourable to the ‘Q’ }}{\text { No.of total outcomes }}\)
= \(\frac{1}{5}\)

ii) When queen is drawn and put aside, remaining cards are four.
∴ Number of total outcomes in drawing a card at random = 4.
a) Number of favourable outcomes to ace 1
Probability of getting an ace
= \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{1}{4}\)

b) Number of favourable outcomes to ‘Q’ = 0 (as it was already drawn and put aside)
∴ Probability that the card is Q = \(\frac{0}{4}\) = 0
After putting queen aside, selecting the queen from the rest is an impossible event and hence the probability is zero.

Question 8.
12 defective pens are accidentally mixed with 132 good ones. It is not possible to just look at a pen and tell whether or not it is defective. One pen is taken out at random from this lot. Determine the probability that the pen taken out is a good one.
Answer:
Number of good pens = 132
Number of defective pens = 12
Total number of pens = 132 + 12 = 144
∴ Total number of outcomes in taking a pen at random = 144.
No. of favourable outcomes in taking a good pen = 132.
∴ Probability of taking a good pen
= \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{132}{144}\) = \(\frac{11}{12}\)

AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.2

Question 9.
A lot of 20 bulbs contain 4 defective ones. One bulb is drawn at random from the lot. What is the probability that this bulb is defective? Suppose the bulb drawn in previous case is not defective and is not replaced. Now one bulb is drawn at random from the rest. What is the probability that this bulb is not defective?
Answer:
Given :
4 out of 20 bulbs are defective
(i.e.) Number of defective bulbs = 4
Number of non-defective bulbs = 20 – 4 = 16
If a bulb is drawn at random, the total outcomes are = 20
Number of outcomes favourable to ‘defective bulb’ = 4
∴ Probability of getting a defective bulb
= \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{4}{20}\) = \(\frac{1}{5}\)
Suppose a non-defective bulb is drawn and not replaced, then the bulbs remaining are = 19
∴ Total outcomes in drawing a bulb from the rest = 19
Number of favourable outcomes in drawing non-defective bulb from the rest = 16 – 1 = 15
∴ Probability of getting a non-defective bulb in the second draw
= \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{15}{19}\)

Question 10.
A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box, find the probability that it bears
(i) a two digit number
(ii) a perfect square number
(iii) a number divisible by 5.
Answer:
Total number of discs in the box = 90
∴ Number of total outcomes in drawing a disc at random from the box = 90.

i) Number of 2-digit numbers in the box (10, 11,….., 90) = 81
i.e., Number of favourable outcomes in drawing a 2 – digit numbers = 81
∴ Probability of selecting a disc bearing a 2 – digit number
= \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{81}{90}\) = \(\frac{9}{10}\) = 0.9

ii) Number of perfect squares in the box (12 = 1, 22 = 4, 32 = 9, 42 = 16, 52 = 25, 62 = 36, 72 = 49, 82 = 64 and 92 = 81) = 9
i.e., Number of favourable out-comes in drawning a disc bearing a perfect square = 9
∴ Probability of drawning a disc with a perfect square
= \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{9}{90}\) = \(\frac{1}{10}\)

iii) Number of multiples of 5 from 1 to 90 are (5, 10, 15, ……….., 90) = 18
i.e., Number of favourable outcomes in drawing a disc with a multiple of 5 = 18
∴ Probability of drawing a disc bearing a number divisible by 5
= \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{18}{90}\) = \(\frac{1}{5}\)

AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.2

Question 11.
Suppose you drop a die at random on the rectangular region shown in figure. What is the probability that it will land inside the circle with diameter 1 m?
AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.2 3
Answer:
3 m.
Length of the given rectangle = 3 m.
and its breadth = 2 m.
Area of the rectangle
= length × breadth = 3 × 2 = 6 m2
∴ Total area of the region for landing = 6 m2.
Diameter of the given circle = 1 m.
Area of the circle = \(\frac{\pi \mathrm{d}^{2}}{4}\)
= \(\frac{22}{7} \times \frac{1 \times 1}{4}\left[\text { or } \pi r^{2}=\frac{22}{7} \times \frac{1}{2} \times \frac{1}{2}\right]\)
= \(\frac{22}{28}\)
∴ Probability of the coin to land on the circle
= \(\frac{\frac{22}{28}}{6}\)
= \(\frac{22}{28×6}\)
= \(\frac{11}{28×3}\)
= \(\frac{11}{84}\)

Question 12.
A lot consists of 144 ball pens of which 20 are defective and the others are good. The shopkeeper draws one pen at random and gives it to Sudha. What is the probability that (i) She will buy it? (ii) She will not buy it?
Answer:
Given : 20 out of 144 are defective i.e., no. of defective ball pens = 20
no. of good ball pens = 144 – 20 = 124
∴ Total outcomes in drawing a ball pen at random = 144.

i) Sudha buys it if it is not defective / a good one.
No. of outcomes favourable to a good pen = 124.
∴ Probability of buying it
= \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{124}{144}\) = \(\frac{31}{36}\)

ii) Sudha will not buy it-if it is a defective pen
No. of outcomes favourable to a defective pen = 20
∴ Probability of not buying it
= \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{20}{144}\) = \(\frac{5}{36}\)

!! (not buying) = 1 – P (buying)
= 1 – \(\frac{31}{36}\) = \(\frac{5}{36}\)

AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.2

Question 13.
Two dice are rolled simultaneously and counts are added
(i) Complete the table given below:
AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.2 4
(ii) A student argues that ‘there are 11 possible outcomes 2, 3, 4, 5, 6, 7, 8, 9, 10, 11 and 12. Therefore, each of them has a probability \(\frac{1}{11}\). Do you agree with this argument? Justify your answer.
Answer:
When two dice are rolled, total number of outcomes = 36 (see the given table).
AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.2 5(i)
AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.2 6(ii) The above (given) argument is wrong [from the above table].
The sum 2, 3, 4, ………… and 12 have different no. of favourable outcomes, moreover total number of outcomes are 36.

AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.2

Question 14.
A game consists of tossing a one rupee coin 3 times and noting its outcome each time. Hanif wins if all the tosses give the same result i.e., three heads or three tails, and loses otherwise. Calculate the probability that Hanif will lose the game.
Answer:
When a coin is tossed for n – times, the total number of outcomes = 2n.
∴ If a coin is tossed for 3 – times, then the total number of outcomes = 23 = 8
Note the following :
TTT
TTH
THT
HTT
HHT
HTH
THH
HHH
Of the above, no. of outcomes with different results = 6.
Probability of losing the game
= \(\frac{\text { No. of favourable outcomes to lose }}{\text { No. of total outcomes }}\)
= \(\frac{6}{8}\) = \(\frac{3}{4}\)

Question 15.
A dice is thrown twice. What is the probability that (i) 5 will not come up either time? (ii) 5 will come up atleast once? [Hint : Throwing a dice twice and throwing two dice simultaneously are treated as the same experiment].
Answer:
If a dice is thrown n-times or n-dice are thrown simultaneously then the total
number of outcomes = 6×6×6….×6
(n – times) = 6n.
No. of total outcomes in throwing a dice for two times = 62 = 36.
AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.2 5i) Let E be the event that 5 will not come up either time, then the favourable outcomes are
(1, 1), (1, 2), (1, 3), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 6), (3, 1), (3/2), (3, 3), (3, 4), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 6) = 25.
AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.2 7∴ P(E) = \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{25}{36}\)

AP SSC 10th Class Maths Solutions Chapter 13 Probability Ex 13.2

ii) Let E be the event that 5 will come up atleast once.
Then the favourable outcomes are (1,5), (2, 5), (3, 5), (4, 5), (5, 5), (6, 5), (5, 1), (5, 2), (5, 3), (5, 4), (5, 6) = 11 No. of favourable outcomes = 11
∴ P(E) = \(\frac{\text { No. of favourable outcomes }}{\text { No. of total outcomes }}\)
= \(\frac{11}{36}\)

AP SSC 10th Class English Solutions Chapter 2A The Dear Departed Part 1

AP State Board Syllabus AP SSC 10th Class English Textbook Solutions Chapter 2A The Dear Departed Part 1 Textbook Questions and Answers.

AP State Syllabus SSC 10th Class English Solutions Chapter 2A The Dear Departed Part 1

10th Class English Chapter 2A The Dear Departed Part 1 Textbook Questions and Answers

Look at the pictures and answer the questions.

AP SSC 10th Class English Solutions Chapter 2A The Dear Departed Part 1

Question 1.
What do you understand from the picture?
Answer:
The rat is pointing a pistol at the cat and intimidating him. I understand that it is a funny picture. One can easily open one’s lips without knowing to smile on seeing this unusual picture.

AP SSC 10th Class English Solutions Chapter 2A The Dear Departed Part 1

Question 2.
Can you recall anything comic associated with these animals?
Answer:
The most popular comic Tom and Jerry’ is associated with them.
‘Tom and Jerry’ is a series of animated cartoon films. We find humour with the rivalry between a cat (Tom) and a mouse (Jerry), Tom’s chasing Jerry and slapstick scenes. “Tom’s making numerous attempts to capture Jerry which leads to destruction” – it creates fun. The scenes such as slicing Tom in half, shutting his head in a window or a door, stuffing Tom’s tail in a mangle, kicking him into a refrigerator, plugging his tail into an electric socket, sticking matches into his feet and lighting them, etc. amuse all the viewers.

(Or)
Yes. I can recall an incident which happened a long time ago in my old house. We used to see many mice in our old house because we stored paddy bags in the house. One day our pet cat jumped on a little mouse which was eating the paddy grains. The little mouse began running. Our cat ran after it. The funny thing was that the mouse did not run away from the place. It began running around the paddy bags. After some time both the cat and the mouse stopped running as they were tired much. At that stage 1 interfered and drove the cat away to save the life of the rat.

Question 3.
Can you imagine, what may be the conversation between the rat and the cat?
Answer:
Conversation between the rat and the cat:
Rat : Hands up!
Cat : Don’t shoot me. I will not eat you.
Rat : No, I don’t believe you. You are cruel.
Cat : Believe me. I decided not to eat rats.
Rat : I don’t believe you. You ran after me yesterday, didn’t you?
Cat : Yes. But not to kill you.
Rat : Then, why?
Cat : I just wanted to tell that I would not kill you thereafter.
Well, how did you get the pistol?
Rat : I stole it from the owner of the house last night.
Cat : Ok. Do you know how to shoot with it?
Rat : I will not tell you.
Cat : Ok. Bye.
Rat : Bye.

AP SSC 10th Class English Solutions Chapter 2A The Dear Departed Part 1

Comprehension

Answer the following questions.

Question 1.
What qualities of Mrs. Slater have you noticed?
Answer:
Mrs. Slater is unscrupulous, greedy, deceitful, dishonest, selfish, impolite and insensitive. She unfairly claims her father s things. This shows her unscrupulous and dishonest manner. She has shifted her father’s bureau and clock from his room before her sister’s arrival. Hence 1 can say Mrs. Slater is greedy. She wants to deceive her sister by pinching their father’s things. 1 can say that she is impolite and insensitive as she doesn’t even wait for her father s funeral and has started dividing things between them (the two sisters).

Question 2.
Why does Mrs. Slater decide to shift the bureau from her father’s room before the arrival of the Jordans? How does Henry react to the suggestion?
Answer:
Mrs. Slater wants to own her father’s bureau as he likes it very much. After her father’s death, she decides to shift the bureau to sitting room before the arrival of the Jordans. She thinks that her sister will lay a claim to it. At first, Henry is shocked at her decision. He feels that the two sisters should amicably divide their father’s things. Henry suggests her that it is not a good thing pinching her father’s things in an unfair way. Moreover, Henry is worried about the arrival of the Jordans while they are shifting the bureau.

Question 3.
Why do the Jordans take a long time to get to the house of the Slaters? What does it show about the two sisters’ attitude towards each other?
Answer:
I think the Jordans are late as they have bought mourning dresses to wear before they come to Slater’s house. They are not sorrowful at their father’s death but they are worried about their appearances and how they can come out to each other. In their relationship, we don’t find any kind of emotions and sisterly love.

Question 4.
Ben appreciates his father-in-law saying, ‘It’s a good thing he did’. Later, he calls him a ‘drunken old beggar’. Why does he change his opinion about his father-in-law?
Answer:
Ben appreciates his father-in-law saying it’s a good thing he did’ when he comes to know from Mrs. Slater that the old man has gone out to pay his insurance premium on the day of his death. Later, he comes to know that he has not paid the premium and therefore calls him a drunken old beggar’. Ben has changed his opinion about his father-in-law when be realises that he hasn’t paid premium because, now after his death, they can t claim the insurance company.

Question 5.
What made Mr.Henry feel shocked to hear Victoria say ‘Are you planning to pinch it ?’?
Answer:
When Victoria asked Slaters “Are you planning to pinch it ?”, Mr. Henry felt shocked. He thought that Victoria was innocent. But when she asked him the above question, Mr. Henry came to know that Victoria had wisdom beyond her age. He actually didn’t expect that question from his little daughter.He came to know that she was a precocious girl and had the ability to distinguish between good and bad.

AP SSC 10th Class English Solutions Chapter 2A The Dear Departed Part 1

The Dear Departed Part 1 Summary in English

The one-act play “The Dear Departed” by William Stanley Houghton is a satirical play that explores family relationships and the falsehood and hypocrisy and greed that often lie beneath it. The story exposes the sad fact that human beings often become dehumanized in the face of greed and minor material gains. This play satirizes the degradation of moral values in respect and care within the members of the family itself. This story clearly reveals how elderly people are mistreated. Stanley Houghton uses various literary devices to criticize basic human characteristics in his play. He uses irony, sarcasm, humour and a twist in the plot to criticize human traits. He tries to bring out the qualities of the two daughters called Mrs. Slater and Mrs. Jordan towards their father. He tries to show how the sisters are interested in the property of their father rather than to show true care and affection towards their father.

The story begins with Mrs. Slater telling her daughter, Victoria to change her dress before the arrival of her sister (Slater’s sister) Elizabeth and Elizabeth’s husband, Ben. Mrs. Slater’s husband, Henry has sent them a telegram with the message of the death of his father-in-law and Elizabeth and Ben are coming to talk over the old man’s affairs. Henry wonders if they would come at all because Elizabeth has said that she would never set foot in their house again. But Mrs. Slater says that her sister will come fast enough after her share of what their father has left. Mrs. Slater asks her husband to wear the new slippers of her father. She also suggests that they should replace their shabby old chest of drawers with the valuable bureau of her father which is in his bedroom. He agrees to do it after some hesitation. Mrs. Slater wants to do it before their arrival.

Mrs. Slater fastens the door and she and her husband carry the old chest of drawers upstairs. Henry is shocked when Victoria asks him if they are pinching grandpa’s bureau. He replies that grandpa has given it to her mother before his death. Mrs. Slater carries a handsome clock and puts it on the mantelpiece. Mrs. Slater and her husband carry the pretty old-fashioned bureau downstairs and put it in the place of the chest of drawers. At the same time Victoria ushers in Mrs. Jordan and Ben. Mrs. Jordan goes straight to Mrs. Slater and kisses her and the men shake hands. Mrs. Jordan remarks that their father has gone at last. Mrs. Slater replies that he is seventy-two a fortnight the previous Sunday. She tells them that the old man has been merry that morning and has gone out to pay his insurance. Ben and Mrs. Jordan remark that it is a good thing on his part.

According to Mrs. Slater, their father is found dead when she takes up a bit of something for him on tray.
Ben and Mrs. Jordan don’t want to look at the old man ; they prefer to have tea and so Mrs. Slater gets tea ready. They think of publishing the announcement of the death of the old man in the papers. Then they decide to look through the old man’s things and make a list of them. Mrs. Jordan tells that the old man has promised his gold watch to their Jimmy. Then Victoria tells them that grandpa hasn’t paid his insurance. Ben calls him “the drunken old beggar”. Both the sisters complain that they have to put up with their father for all those years. Then Mrs. Slater asks Victoria to go and bring the bunch of keys from grandpa’s room. Victoria is afraid to go but she does. After some time, she gets back very scared and tells them that grandpa is getting up. They are transfixed with amazement. The vigorous and well coloured old man Abel Merry weather comes in.

AP SSC 10th Class English Solutions Chapter 2A The Dear Departed Part 1

The Dear Departed Part 1 Glossary

lay (v): (here) to put the cloth, plates, knives, forks etc. on a table, ready for a meal

vigorous (adj): using a lot of energy and strength or determination

plump (adj): slightly fat in a fairly pleasant way

vulgar adj): rude and offensive

get her own way (idiom): persuade other people to allow you to do what you want

D’ye: Do you (used in awkward situations)

amazed (adj): very surprised

ages (n): long time

stooping (adj): bent towards and down

drooping (adj): hanging or bending down

come after (phr.v.): to look for someone to get something from them

worn out (adj): too old or damaged to be used

break down (phr.v.): stop working in a successful way

trifle (n): something unimportant or not valuable

precocious (adj): Intelligent/gifted/talented

bureau (n): a writing desk with drawers

drive a liard bargain (idiom): work hard to negotiate agreements in on&s own favour

startled (v): made someone suddenly surprised or slightly shocked

stupefied (adj): so surprised, tired or bored thai one cant think clearly

daft (adj): stupid/silly

shabby (adj): untidy and bad

fasten (v): to firmly close a window, door etc. so that it will not open

pinch (w): steal

mantelpiece (n): a shelf projecting from the wail over the fireplace

usher (v): lead/show the way/welcome

appeal: be attractive

stagger (v): to walk or move unsteadily, almost falling over

complacent (adj): sell-satisfied/unconcerned

mourning (n): feeling of sadness to miss someone after they have died

fortnight (n): two weeks

chirpily (adv): cheerfully and actively

snug (adj): warm and comfortable

wipe (v): to rub a surface with something in order to remove liquid, dirt, etc.

look through (phr.v.): look for something

overdue (adj): not paid by the expected time

annoy (v): to make someone feel slightly angry and unhappy about something

put up with (phr.v.): to accept an unpleasant situation or person without complaining

swindling (v): cheating somebody for property or money

reluctantly (adv): unwillingly