AP State Syllabus AP Board 8th Class Maths Solutions Chapter 11 Algebraic Expressions Ex 11.1 Textbook Questions and Answers.

## AP State Syllabus 8th Class Maths Solutions 11th Lesson Algebraic Expressions Exercise 11.1

Question 1.

Find the product of the following pairs:

(i) 6, 7k

(ii) – 31, – 2m

(iii) -5t^{2} – 3t^{2}

(iv) 6n, 3m

(v) – 5p^{2}, – 2p

Solution:

The product of 6, 7k = 6 × 7k = 42k

ii) The product of – 3l, – 2m = (- 3l) × (- 2m) = 6/m

iii) The product of – 5t^{2}, – 3t^{2} = (- 5t^{2}) × (- 3t^{2}) = 15t^{4}

iv) The product of 6n, 3m = 6n × 3m = 18mn

v) The product of – 5p^{2}, – 2p = (- 5p^{2}) × (- 2p) = 10p^{3}

Question 2.

Complete the table of the products.

Solution:

Question 3.

Find the volumes of rectangular boxes with given length, breadth and height in the following table.

Solution:

Question 4.

Find the product of the following monomials

(i) xy, x^{2}y , xy, x

(ii) a, b, ab, a^{3} b, ab^{3}

(iii) kl, lm, km, klm

(iv) pq ,pqr, r

(v) – 3a, 4ab, – 6c, d

Solution:

i) The product of xy, x^{2}y, xy, x = xy × x^{2}y × xy × x

= x^{5} × y^{3}= x^{5}y^{3}

ii) The product of a, b, ab, a^{3}b, ab^{3} = a × b × ab × a^{3}b × ab^{3}

= a^{6} × b^{6} = a^{6} b^{6}

iii) The product of kl, lm, km, klm = kl × lm × km × klm

k^{3} × l^{3} × m^{3} =k^{3}l^{3}m^{3}

iv) The product of pq, pqr, r = pq × pqr × r

= p^{2} × q^{2} × r^{2} – p^{2}q^{2}r^{2}

v) The product of – 3a, 4ab, – 6c, d = (- 3a) × 4ab × (- 6c) x d

= + 72a^{2} × b × c × d

= 72a^{2}bcd

Question 5.

If A = xy,B = yz and C = zx, then find ABC=

Solution:

ABC = xy × yz × zx = x^{2}y^{2}z^{2}

Question 6.

If P = 4x^{2}, T = 5x and R = 5y, then \(\frac{\mathrm{PTR}}{100}\) =

Solution:

\(\frac{P^{\prime} \Gamma R}{100}=\frac{4 x^{2} \times 5 x \times 5 y}{100}=\frac{100 x^{3} y}{100}\) = x^{3} y

Question 7.

Write some monomials of your own and find their products.

Solution:

The product of,some monomials is given below :

i) abc × a^{2}bc = a^{3}b^{2}c^{2}

ii) xy × x^{2}z × yz^{2} = x^{3}y^{2}z^{3}

iii) p × q × r = p^{3}q^{3}r^{3}