AP State Syllabus AP Board 6th Class Maths Solutions Chapter 6 Basic Arithmetic Unit Exercise Textbook Questions and Answers.

## AP State Syllabus 6th Class Maths Solutions 6th Lesson Basic Arithmetic Unit Exercise

Question 1.

Draw a four sided closed figure and divide it into some number of equal parts. Shade the figure with any colour so that the ratio of shaded parts to unshaded parts is 1 : 3.

Answer:

Given ratio of shaded parts: unshaded parts = 1 : 3

Total parts of a closed figure = 1 + 3 = 4

Consider a four sided closed figure square.

Divide it into 4 parts and shade one part.

Now, from the figure, shaded parts : unshaded parts = 1 : 3

Question 2.

Ramu spent \(\frac{2}{5}\)th of his money on a story book. Find the ratio of money spent to the money with him at present.

Answer:

Given money spent on story book = \(\frac{2}{5}\) th of his money.

That means from total 5 parts of money he spent 2 parts of money on story book. Then, out of 5 parts remaining parts of money with him is 3 parts.

So, ratio of money spent to the money with him at present

= parts of money spent : parts of money at him = 2 : 3

Question 3.

Divide Rs. 72,000 between Kesav and David in the ratio of 5 : 4.

Answer:

Amount to be divided = Rs. 72,000

Ratio of Kesav and David’s Shares = 5 : 4

Total shares = 5 + 4 = 9

Kesav’s share = \(\frac{5}{9}\) of 72000

\(\frac{5}{9}\) × 72,000 = 40,000/-

David’s share = \(\frac{4}{9}\) of 72,000

\(\frac{4}{9}\) × 72,000 = 32,000/-

Question 4.

The income of Kumar for 3 months is Rs. 15,000. If he earns the same amount for a month,

a) How much will he earn in 5 months?

b) In how many months, will he earn Rs. 95,000?

Answer:

Given Kumar’s 3 months income = Rs. 15,000

Kumar’s one month income = 15,000 ÷ 3

= \(\frac{15000}{3}\) = Rs. 5000

a) Kumar’s one month income = Rs. 5000

Kumar’s 5 months income = 5 × 5000 = Rs. 25,000

b) Time taken by Kumar to earn Rs. 5000 = 1 month

Time taken by Kumar to earn Rs. 95,000 = 95,000 ÷ 5000

= \(\frac{15000}{3}\) = 19 months = 1 year 7 months.

Question 5.

The cost of 16 chairs is Rs. 4,800. Find the number of chairs that can be purchased for Rs. 6,600.

Answer:

Cost of 16 chairs = Rs. 4800

Number of chairs that can be pruchased for Rs. 6600 = x (say)

∴ 16 : 4800 : : x : 6600

So, 16 x 6600 = 4800 x x

x = \(\frac{16 \times 6600}{4800}\) = 22 chairs

(OR)

Given cost of 16 chairs = Rs. 4800

Cost of one chair = 4800 ÷ 16

= \(\frac{4800}{3}\) = Rs. 300

Number of chairs can purchased for Rs. 6600 = 6600 ÷ cost of one chair

= 6600 ÷ 300

= \(\frac{6600}{300}\) = 22 chairs

Question 6.

What percentage of numbers from 1 to 30 has 1 or 9 in the unit’s digit?

Answer:

Total number from 1 to 30 = 30

Numbers ending with 1 or 9 are 1, 9,11, 19, 21, 29 = 6 numbers

Ratio = 6 : 30 = \(\frac{6}{30}\) = \(\frac{1}{5}\)

Percentage = \(\frac{1}{5}\) × 100% = 20%

Question 7.

In a college, 63% of students are less than 20 years of age. The number of students more than 20 years of age is — of number of students of 20 years of age which is 42. What is the total number of students in the college?

Answer:

Let the total number of students be x.

Then, number of students more than 20 years of age = (100 – 63)% of x

= 37% of x

Then, 37% of x = 42 + \(\frac{2}{3}\) of 48

\(\frac{37}{100}\) × x = 74

∴ x = 74 × \(\frac{100}{37}\) = 200