SCERT AP 7th Class Maths Solutions Pdf Chapter 1 Integers Review Exercise Questions and Answers.
AP State Syllabus 7th Class Maths Solutions 1st Lesson Integers Review Exercise
Question 1.
Represent the following statements with a suitable integer.
(i) Sneha deposited ₹ 2000 in her savings account.
Answer:
+ 2000 Rupees.
(ii) A submarine is in the depth of 350 feet in the sea level.
Answer:
– 350 feet.
(iii) The height of Mount Everest is 8848 m J 3 above the sea level.
Answer:
+ 8848 m.
(iv) Temperature of 14 degrees below 0° C.
Answer:
– 14°C.
Question 2.
Fill the missing integers on the number line.
Answer:
Question 3.
Represent the following additions and subtractions on number line.
(i) 7 + 4
(ii) – 8 + 3
(iii) 9 – 11
(iv) 13 – 5
Answer:
Question 4.
Write the following integers in descending order and ascending order.
(i) -9, -1, 0, -10, -6
Answer:
Ascending order: -10, -9, -6,- 1, 0
Descending order: 0, -1, -6, -9,-10
(ii) -6, 6, -9, 5, 10, -3
Answer:
Ascending order: -9, -6, -3, 5, 6, 10
Descending order: 10, 6, 5, -3, -6, -9
(iii) 15, -20, -35, 0, 2
Answer:
Ascending order: -35, -20, -15, 0, 2
Descending order: 2, 0, -15, -20, -35
Question 5.
Calculate the following.
(i) – 2 + 3
Answer:
– 2 + 3 = +1
(ii) – 6 + (- 2)
Answer:
– 6 + (- 2) = – 6 – 2 = – 8
(iii) 8 – (- 6)
Answer:
8 – (-6) = 8 + 6 = + 14
(iv) – 9 + 4
Answer:
– 9 + 4 = – 5
(v) – 23 – (- 30)
Answer:
– 23 – (- 30) = – 23 + 30 = + 7
(vi) 50 – 153
Answer:
50 – 153 = + 50 – 153 = – 103
(vii) 71 + (- 10) – 8
Answer:
71 + (-10) – 8 = + 71 – 10 – 8
= + 71 – 18 = + 53
(viii) – 30 + 58 – 38
Answer:
-30 + 58 – 38 = – 30 – 38 + 58
= – 68 + 58 = – 10
Question 6.
The temperature in Siachen at 5 a.m. was 10 degrees below 0°C. Six hours later, it had increased to 14°C. What is the temperature at 11 a.m. ?
Answer:
Temperature at 5 a.m. = 10 degrees below 0°C = – 10°C
Six hours later increased temperature = + 14°C
Temperature at 11 a.m. = -10°C + 14°C
= +4°C
∴ Temperature at 11 a.m. in Siachen is + 4°C.
Question 7.
A fish was at 16 feet below the surface of sea and went down another 17 feet. What is its position now from the surface of sea?
Answer:
Place of the fish in the beginning = 16 feet below surface = -16 feet
Place of the fish at last from the beginning = – 17 feet
∴ Position of fish now = – 16 + (-17)
= – 16 – 17
= – 33 feet
Question 8.
A green grocer had a profit of ₹ 250 on Monday, a loss of ₹ 120 on Tuesday and loss of ₹ 180 on Wednesday. Find total profit or loss after 3 days.
Answer:
Profit on Monday = + ₹ 250
Loss on Tuesday = – ₹ 120
Loss on Wednesday = – ₹ 180
Total loss two days = – 120 + (- 180)
= – 120 – 180 = – 300
Loss is greater than profit. So, he will get loss.
∴ Total loss on three days = + 250 + (-300)
= + 250 – 300
= – 50
= – ₹ 50
Question 9.
Fill the empty boxes in first diagram by doing addition of two integers and in second diagram by doing subtraction of two integers.
(i)
Answer:
(ii)
Answer:
