SCERT AP 7th Class Maths Solutions Pdf Chapter 2 Fractions, Decimals and Rational Numbers Ex 2.1 Textbook Exercise Questions and Answers.

## AP State Syllabus 7th Class Maths Solutions 2nd Lesson Fractions, Decimals and Rational Numbers Exercise 2.1

Question 1.

In Jagananna Gorumudda (MDM) scheme each student got \(\frac{3}{20}\) kg. rice per day, find the weight of the rice required for 60 students in a class per day.

Answer:

Given quantity of rice each student get per day = \(\frac{3}{20}\) kg.

Quantity of rice 60 students get per day

= \(\frac{3}{20} \times \frac{60}{1}\)

= \(\frac{3 \times 60}{20 \times 1}\)

= \(\frac{180}{20}\) = 9

∴ Quantity of rice required for 60 students per day = 9 kg.

Question 2.

What is a perimeter of an equilateral triangle, if each*side of a triangle is 5\(\frac{3}{10}\)cm?

Answer:

Let the side of an equilateral triangle be x cm.

Perimeter of an equilateral triangle = 3x.

= 3 × 5 \({30}{10}\)

= \(\frac{3}{1} \times \frac{53}{10}\)

= \(\frac{3 \times 53}{1 \times 10}\)

∴ Perimeter of triangle = \(\frac{159}{10}\) or 15\(\frac{9}{10}\) cm

Question 3.

Surya can walk \(\frac{18}{5}\)kilo meters in an hour. How much distance can he walk in 2\(\frac{1}{2}\) hours ?

Answer:

Given, distance walked by Surya in 1 hour = \(\frac{18}{5}\)km.

Distance walked by Surya in 2\(\frac{1}{2}\)hours

∴ Distance walked in 2\(\frac{1}{2}\)hours

= \(\frac{9}{1}\) = 9 km

Question 4.

If the length and breadth of a rectan-gular garden are \(\frac{27}{2}\)m and \(\frac{15}{2}\)m respectively, then find the area of the garden.

Answer:

Given, the length of a garden = \(\frac{27}{2}\)m.

breadth of a garden = \(\frac{15}{2}\)m.

Area of rectangular garden = length × breadth

= \(\frac{27}{2} \times \frac{15}{2}\)

= \(\frac{27 \times 15}{2 \times 2}\)

∴ Area of the garden = \(\frac{405}{4}\) or 101\(\frac{1}{4}\)

Question 5.

Gopal bought 3\(\frac{1}{2}\)kg. of potatoes in the market. If he paid ?84, then find the cost of 1 kg. of potatoes.

Answer:

Given, cost of 3\(\frac{1}{2}\) kgs of potatoes = ₹ 84

Cost of 1 kg of potatoes = 84 ÷ 3\(\frac{1}{2}\)

= 84 ÷ \(\frac{7}{2}\)

= \(\frac{84}{1} \times \frac{2}{7}\)

∴ Cost of one kg of potatoes = \(\frac{168}{7}\)

= ₹ 24

Question 6.

A car travelled 225 km. in 4 \(\frac{1}{2}\) hours with uniform speed. Find the distance travelled in 1 hour.

Answer:

Given, distance travelled in 4\(\frac{1}{2}\) hours = 225 km

Distance travelled in 1 hour

= 225 ÷ 4\(\frac{1}{2}\)

= 225 ÷ \(\frac{9}{2}\)

= \(\frac{225}{1} \times \frac{2}{9}\)

= \(\frac{225 \times 2}{1 \times 9}\)

∴ Distance travelled by car in 1 hour

= \(\frac{450}{2}\) = 50 km

Question 7.

If 24 students share 4\(\frac{4}{5}\)kg. of cake, then how much cake does each one get?

Answer:

Given, quantity of cake shared by 24 students = 4\(\frac{4}{5}\)kg

Quantity of cake each one got

= 4\(\frac{4}{5}\) ÷ 24 .

= \(\frac{24}{5} \div \frac{24}{1}\)

∴ Quantity of cake each one got = \(\frac{1}{5}\)kg (or) 0.2 kg (or) 200 gm.

Question 8.

A drum contains 210 l of water. How many times does the boy get the water for watering die plants with 3\(\frac{1}{2}\) l of full bucket from the drum ?

Answer:

Given, Capacity of water drum = 210 l

Capacity of bucket = 3\(\frac{1}{2}\) l

Number of buckets of water the boy get = 210 ÷ 3\(\frac{1}{2}\)

= 210 ÷ \(\frac{7}{2}\)

= \(\frac{210}{1} \times \frac{2}{7}\)

= \(\frac{420}{7}\) = 60

∴ Number of buckets the boy get = 60