Andhra Pradesh AP Board 4th Class Maths Solutions 7th Lesson Geometry Textbook Exercise Questions and Answers.
AP State Syllabus 4th Class Maths Solutions Chapter 7 Geometry
Textbook Page No. 86
Think and Discuss
Question 1.
Does a cone or cylinder have any edges and corners ?
Solution:
Yes, cone has 1 edge and 1 comer.
Yes, cylinder has 2 edges and no comers.
Do this
a) Draw a line to divide the adjacent, rectangles into two equal parts.
Solution:
b) Name some objects which are in rectangle shape.
Solution:
Book, Brick, Cell phone, Exam pad.
Textbook Page No. 87
Do this
Draw a line to divide the following squares into two equal parts.
Solution:
Textbook Page No. 89
Do this
a) How many triangles are formed when a square or rectangle is cut diagonally ?
Solution:
When a square or rectangle is cut diagonally two triangles are formed.
b) In a figure, the four sides are 20cm, 16 cm, 20 cm, 16 cm then what is the shape of the object ?
Solution:
Given measurements 20 cm, 16 cm, 20 cm, and 16 cm. Here two sides are equal in measurements. So it is a rectangle.
c) In a figure, measurements of four sides are 15 cm each and the adjacent sides are vertical to each other. What is the shape of the object ?
Solution:
Given measurement is 15 cm. All sides are equal and vertical to each other are equal.
∴ It is a square.
Textbook Page No. 90
Do this
Question 1.
Observe the following:
Question 2.
Observe the net shapes of the boxes and match them with their 3 – D shapes.
Solution:
1 – b
2 – d
3 – a
4 – c
Textbook Page No. 92
Try this
Make some squares, rectangles and triangles with some cool drink straws. Find the perimeter of the shapes.
Solution:
P = 6m
P = 4m
P = 3m
Exercise – 7.1
Question 1.
The length and breadth of a rectangular field are 60m and 40m respectively. If Somaiah walked around the field, then find the distance covered by him.
Solution:
Length of a rectangular field = 60m
Breadth of a rectangular field = 40 m
Somaiah walked around the field
Distance covered by him = 2(1 + b)
= 2(60 + 40)
= 2 × 100
= 200 m
Question 2.
Somulu’s site is in square shape. He wanted to construct the compound wall around it. Find the length of the compound wall.
Solution:
Length at a square shaped side = 14 cm
He wanted to construct the compound wall around it.
Total length at the compound wall
= 4 side = 4 × 14 = 56 cm
Question 3.
A park is in a triangular shape as shown below. What is the perimeter of the park ?
Solution:
Park is in a triangular shape.
Length of park sides are 30m, 40m and 50m.
Perimeter of the park = 30 + 40 + 50
= 120 m
4. Find the perimeter of the following figures.
a)
Perimeter = ………………. cm
Solution:
From figure, perimeter of figure a
= 6cm + 6cm + 6cm + 6 cm
= 24 cm
b)
Perimeter = ………………. cm
Solution:
From figure, perimeter of figure a
= 4cm + 7cm + 4cm + 7 cm
= 22 cm
c)
Perimeter = ……………… cm
Solution:
From figure, perimeter of figure
= 5cm + 5 cm + 5 cm
= 15 cm
d)
Perimeter = ……………… cm
Solution:
Perimeter of the shape a
= 3 cm + 1 cm + 3 cm + 1 cm
= 8 cm
Textbook Page No. 95
Do this
Find the perimeter of the given shapes
Solution:
∴ Perimeter of the shape
= 3 cm + 1 cm + 3 cm + 1 cm
= 8 cm
Solution:
∴ Perimeter of the shape
= (1 + 1 + 1 + 1 + 1 + 1 + 1 + 1) cm
= 8 cm
Solution:
∴ Perimeter of the shape
= 2 + 2 + 1 + 1 + 1
= 7 cm
Solution:
∴ Perimeter of the shape
= (1 + 2 + 1 + 2) cm
= 6 cm
Solution:
∴ Perimeter of the shape
= (1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1 + 1) cm
= 11 cm
Textbook Page No. 97
Do this
Calculate the area of the shapes formed by colouring three, four and five grids.
Solution:
Area of the shapes formed by colouring
Three grids =3 square units.
Four grids =4 square units.
Five grids = 5 square units.
Try this
Find the area and perimeter of each shaded shape in the pictures. What do you notice?
i)
This figure occupies 4 grids. Hence its area = 4 square units.
Solution:
This figure occupied 4 grids.
Hence its area = 4 square units.
Perimeter of this figure
= (2 + 2+ 2+ 2) cm
= 8cm
ii)
This figure occupies 9 grids.
Hence shaded area …………. square units.
Solution:
This figure occupies 9 grids.
Hence shaded area =9 square units.
Perimeter of this figure
= each grid perimeter × 9
= 4cm × 9
= 36 cm
iii)
This figure occupies ………….. grids.
Hence its area = …………. square units.
Solution:
This figure occupied 8 grids.
Hence shaded area 8 square units.
Perimeter of this figure
= each grid perimeter × 8
= 4 cm × 8
= 32 cm
Exercise – 7.2
Question 1.
On a grid paper, draw different shapes totalling to an area of 8 square units.
Solution:
Question 2.
Draw a rectangle of 4 units length and 3 units breadth on a grid paper. Also, calculate its area.
Solution:
Question 3.
Draw a square of side 5 units on a grid paper and calculate them.
Solution:
Textbook Page No. 100
Do this
a) Draw a few circles using a bangle, plate, bottle cap etc.
Solution:
b) Draw a circles using one-rupee, two- rupee-five-rupee and ten-rupees coins.
Solution:
Exercise – 7.3
Question 1.
What is the perimeter of the following figures?
Solution:
Perimeter of the given figure
= 3 cm + 3 cm + 3 cm
= 12 cm
Perimeter of the given figure
= 3 cm + 6 cm + 4 cm + 3 cm
= 16 cm
Question 2.
A piece of land in Simhachalam is in the following shape. Find the length of the fencing wire required to provide fencing around the land.
Solution:
Length of the fencing wire required to provide fencing around the land
= Perimeter of figure
= 18 m + 17 m + 16 m + 14 m
= 65 m
Question 3.
The perimeter of the following shape is ……………. metres.
Solution:
Perimeter of the given shape
= 3m + 3m + 2m + 5m + 6m
= 19 m
Question 4.
What is the perimeter of the figure?
Solution:
Perimeter of the figure
= 2cm + cm + 3 cm + 2 cm + 2 cm + 5 cm + 7 cm + 5 cm
= 30 cm
Question 5.
What is the perimeter and area of figures given below.
Solution:
Perimeter of given figure – 1:
= 2 cm + 1 cm + 1 cm + 1 cm + 1 cm + 1 cm + 1 cm + 2 cm + 1 cm + 1 cm+ 1 cm + 1 cm
= 14 cm
Perimeter of given figure – 2:
= 1 cm + 1 cm + 1 cm + 1 cm + 1 cm+ 1 cm + 1 cm + 1 cm + 1 cm+ 1 cm + 1 cm + 1 cm+ 1 cm+ 1 cm + 1 cm + 1 cm + 1 cm + 1 cm+ 1 cm + 1 cm
= 20 cm
Multiple Choice Questions
Question 1.
Carrot has………….
A) Joker hat
B) Ball
C) Brick
D) Drum
Answer:
A) Joker hat
Question 2.
Samosa is in …………. shape.
A) Rectangle
B) Square
C) Circle
D) Triangle
Answer:
D) Triangle
Question 3.
Shape of Joker cap ……………..
A) Cuboid
B) Cube
C) Square
D) Cone
Answer:
D) Cone
Question 4.
Carrams board is in ……………….. shape.
A) Rectangle
B) Square
C) Triangle
D) Circle
Answer:
B) Square
Question 5.
A Rubic cube shape is ……………..
A) Cube
B) Cuboid
C) Cone
D) Square
Answer:
A) Cube
Question 6.
Tooth paste box is in ………….. shape.
A) Square
B) Circle
C) Rectangle
D) Triangle
Answer:
C) Rectangle
Question 7.
Area of shaded region is ……………. sq. units.
A) 9
B) 18
C) 4
D) 10
Answer:
C) 4
Question 8.
Perimeter
of is ………………….. m
A) 20 m
B) 12 m
C) 15 m
D)18 m
Answer:
A) 20 m
Question 9.
Name of shape of the object
A) Square
B) Triangle
C) Circle
D) Rectangle
Answer:
C) Circle
Question 10.
Tangram has …………… shapes.
A) 7
B) 5
C) 6
D) 4
Answer:
A) 7